LeetCode()Substring with Concatenation of All Words 为什么我的超时呢?找不到原因了!!!
超时代码
class Solution {
public:
vector<int> findSubstring(string s, vector<string>& words) {
map<string,int> coll;
for(auto i:words)
coll[i]++;
vector<int> res;
int len=words[0].size(),sum=words.size();
for(int k=0;k<=s.length()-len*sum;k++)
if(check(s,k,len,sum,coll))
res.push_back(k);
return res;
}
bool check(string s,int start,int len,int sum,map<string,int> coll)
{
for(int i=start;i<=s.length()-len && sum!=0;i+=len)
{
string str=s.substr(i,len);
auto d=coll.find(str);
if(coll[str]>0 && d != coll.end())
{
coll[str]--;
sum--;
}
else
return false;
}
if(sum==0)
return true;
else
return false;
}
};
这个和我的没有什么区别吧?为什么就可以呢?
class Solution {
private:
int wordLen;
public:
vector<int> findSubstring(string S, vector<string> &L) {
unordered_map<string, int>wordTimes;
for(int i = 0; i < L.size(); i++)
wordTimes[L[i]]++;
wordLen = L[0].size();
vector<int> res;
for(int i = 0; i <= (int)(S.size()-L.size()*wordLen); i++)
if(helper(S, i, wordTimes, L.size()))
res.push_back(i);
return res;
}
//判断子串s[index...]的前段是否能由L中的单词组合而成
bool helper(const string &s, int index,
unordered_map<string, int>wordTimes, int wordNum)
{
for(int i = index; wordNum != 0 && i <= (int)s.size()-wordLen; i+=wordLen)
{
string word = s.substr(i, wordLen);
auto ite = wordTimes.find(word);
if(ite != wordTimes.end() && ite->second > 0)
{ite->second--; wordNum--;}
else return false;
}
if(wordNum == 0)return true;
else return false;
}
};
LeetCode()Substring with Concatenation of All Words 为什么我的超时呢?找不到原因了!!!的更多相关文章
- LeetCode: Substring with Concatenation of All Words 解题报告
Substring with Concatenation of All Words You are given a string, S, and a list of words, L, that ar ...
- [LeetCode] Substring with Concatenation of All Words 串联所有单词的子串
You are given a string, s, and a list of words, words, that are all of the same length. Find all sta ...
- LeetCode:Substring with Concatenation of All Words (summarize)
题目链接 You are given a string, S, and a list of words, L, that are all of the same length. Find all st ...
- [leetcode]Substring with Concatenation of All Words @ Python
原题地址:https://oj.leetcode.com/problems/substring-with-concatenation-of-all-words/ 题意: You are given a ...
- Leetcode Substring with Concatenation of All Words
You are given a string, S, and a list of words, L, that are all of the same length. Find all startin ...
- [LeetCode] Substring with Concatenation of All Words(good)
You are given a string, S, and a list of words, L, that are all of the same length. Find all startin ...
- Leetcode:Substring with Concatenation of All Words分析和实现
题目大意是传入一个字符串s和一个字符串数组words,其中words中的所有字符串均等长.要在s中找所有的索引index,使得以s[index]为起始字符的长为words中字符串总长的s的子串是由wo ...
- LeetCode HashTable 30 Substring with Concatenation of All Words
You are given a string, s, and a list of words, words, that are all of the same length. Find all sta ...
- leetcode面试准备: Substring with Concatenation of All Words
leetcode面试准备: Substring with Concatenation of All Words 1 题目 You are given a string, s, and a list o ...
随机推荐
- 可以创建专业的客户端/服务器视频会议应用程序的音频和视频控件LEADTOOLS Video Conferencing SDK
LEADTOOLS Video Streaming Module控件为您创建一个自定义的视频会议应用程序和工具提供所有需要的功能.软件开发人员可以使用Video Streaming Module SD ...
- Android ContentProvider的实现
当Android中的应用需要访问其他应用的数据时,用ContentProvider可以很好的解决这个问题.今天介绍一下ContentProvider的用法. 首先开发ContentProvider有两 ...
- root运行chrome
os:centos7 edit file : /usr/bin/google-chrome Add "--user-data-dir" (without the quotes) a ...
- iOS数据存取和对象序列化
一. 使用NSKeyedArchiver类操作对象的存取 特点:该类可以将对象以键值对的形式存入文件,并通过key从文件中取出,与android中的SharedPreference用法类似,而且它序列 ...
- 修复win8引导
格式化那个350MB的分区(Win8安装盘启动之后挂载在c:之后,用Win8的安装U盘,进去修复模式,然后进入高级选项的命令行提示符模式.接着,转到安装现有Win8的分区(Win8安装盘启动之后挂载在 ...
- hdu 2047
PS:又是上课偷懒..去递推.. 代码: #include "stdio.h"#include "math.h"long long dp[55];long lo ...
- Minimum Inversion Number_线段树||树状数组
Problem Description The inversion number of a given number sequence a1, a2, ..., an is the number of ...
- Unity3D ShaderLab 修改渲染队列进行深度排序
Unity3D ShaderLab 修改渲染队列进行深度排序 为了更深刻的理解透明度,我们还需要学习一下深度排序,简单来说就是物体被渲染的先后顺序. Unity允许我们通过代码来控制某个特定物体渲染到 ...
- PHP 防范CC攻击
CC攻击就是对方利用程序或一些代理对您的网站进行不间断的访问,造成您的网站处理不了而处于当机状态,下面是PHP方法:将以下代码另存为php文件,然后首行include入你的common.php文件中. ...
- Inno Setup 在安装程序开始前和卸载程序开始前,检查并关闭运行的进程
(2011-12-29 11:54:56) 转载▼ 标签: innosetup it 分类: 开发工具经验累积 Inno Setup在安装程序前,如果有使用的进程在运行,会有错误提示,而使得Insta ...