PAT 1064 Complete Binary Search Tree
#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <vector>
#include <algorithm> using namespace std; class Node {
public:
int val;
Node* left;
Node* right;
public:
Node(): val(), left(NULL), right(NULL) {}
Node(int _val, Node* _left = NULL, Node* _right = NULL): val(_val), left(_left), right(_right) {}
}; vector<Node*> build_next_level(vector<Node*> last_level, int &num) {
vector<Node*> res;
if (num < ) return res; for (auto iter = last_level.begin(); iter != last_level.end(); iter++) {
Node* parent = *iter; Node* lchild = new Node();
res.push_back(lchild);
parent->left = lchild;
if (--num < ) break; Node* rchild = new Node();
res.push_back(rchild);
parent->right= rchild;
if (--num < ) break;
} return res;
} void inorder_traverse(Node* root, int& order) {
if (root == NULL) return;
inorder_traverse(root->left, order);
root->val = order++;
inorder_traverse(root->right, order);
} int main() {
int cnt; scanf("%d", &cnt); vector<int> nums(cnt, ); if (cnt < ) return ; for (int i = ; i<cnt; i++) {
int num = ;
scanf("%d", &num);
nums[i] = num;
}
sort(nums.begin(), nums.end()); vector<vector<Node*> > levels; vector<Node*> last_level;
last_level.push_back(new Node()); levels.push_back(last_level); int node_cnt = cnt - ; // we already pushed the root node
while (node_cnt > ) {
vector<Node*> cur_level = build_next_level(last_level, node_cnt);
levels.push_back(cur_level);
swap(last_level, cur_level);
} int order = ;
inorder_traverse(levels[][], order); node_cnt = cnt; for (auto iter_levels = levels.begin(); iter_levels != levels.end(); iter_levels++) {
vector<Node*>& cur_level = *iter_levels;
for (auto iter = cur_level.begin(); iter != cur_level.end(); iter++) {
Node* node = *iter;
int val = nums[node->val];
if (--node_cnt > ) {
printf("%d ", val);
} else {
printf("%d\n", val); // last element
}
}
}
return ;
}
又是跟书本比较近的一题
PAT 1064 Complete Binary Search Tree的更多相关文章
- PAT 1064 Complete Binary Search Tree[二叉树][难]
1064 Complete Binary Search Tree (30)(30 分) A Binary Search Tree (BST) is recursively defined as a b ...
- PAT甲级:1064 Complete Binary Search Tree (30分)
PAT甲级:1064 Complete Binary Search Tree (30分) 题干 A Binary Search Tree (BST) is recursively defined as ...
- PAT题库-1064. Complete Binary Search Tree (30)
1064. Complete Binary Search Tree (30) 时间限制 100 ms 内存限制 32000 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHE ...
- pat 甲级 1064. Complete Binary Search Tree (30)
1064. Complete Binary Search Tree (30) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHE ...
- 1064. Complete Binary Search Tree (30)【二叉树】——PAT (Advanced Level) Practise
题目信息 1064. Complete Binary Search Tree (30) 时间限制100 ms 内存限制65536 kB 代码长度限制16000 B A Binary Search Tr ...
- PAT 甲级 1064 Complete Binary Search Tree (30 分)(不会做,重点复习,模拟中序遍历)
1064 Complete Binary Search Tree (30 分) A Binary Search Tree (BST) is recursively defined as a bin ...
- pat 甲级 1064 ( Complete Binary Search Tree ) (数据结构)
1064 Complete Binary Search Tree (30 分) A Binary Search Tree (BST) is recursively defined as a binar ...
- PAT 甲级 1064 Complete Binary Search Tree
https://pintia.cn/problem-sets/994805342720868352/problems/994805407749357568 A Binary Search Tree ( ...
- PAT Advanced 1064 Complete Binary Search Tree (30) [⼆叉查找树BST]
题目 A Binary Search Tree (BST) is recursively defined as a binary tree which has the following proper ...
随机推荐
- WPF:CheckBox竖向的滑块效果
原文:WPF:CheckBox竖向的滑块效果 之前做了一个横向的滑块效果,<WPF:CheckBox滑块效果>,其实我觉得那个不好看,今天又做了一个竖向的玩. <Style Targ ...
- ansible基本模块-cron
ansible XXX -m cron -a "name=‘XXX ’ job=‘执行的命令’ minute=XXX " ...
- C++_类和动态内存分配4-有关返回对象的说明
返回方式: 返回指向对象的引用: 指向对象的const引用: const对象: =============================================== 返回指向const对象 ...
- abp框架angular 项目docker 手动部署到Linux环境中
1.https://aspnetboilerplate.com/Templates 2.后端项目发布,在publish中abp默认已经存在DockerFile文件 3.修改后端文件中的DockerFi ...
- 【算法笔记】B1021 个位数统计
1021 个位数统计 (15 分) 给定一个 k 位整数 N=dk−110k−1+⋯+d1101+d0 (0≤di≤9, i=0,⋯,k−1, dk−1> ...
- loj 2038 / 洛谷 P4345 [SHOI2015] 超能粒子炮・改 题解
好玩的推式子 题目描述 曾经发明了脑洞治疗仪与超能粒子炮的发明家 SHTSC 又公开了他的新发明:超能粒子炮・改--一种可以发射威力更加强大的粒子流的神秘装置. 超能粒子炮・改相比超能粒子炮,在威力上 ...
- java的长字符串转化为短字符串
public class CustomEncrypt{ public static void main( String[] args ) { /* * c#给的正确测试用例: id=>mid * ...
- mutillidae2.6.48部署到phpstudy
废话不多说,先上链接 mutillidae2.6.48链接: https://pan.baidu.com/s/1hssyiVy 密码: pw67 phpstudy2016.exe链接: https:/ ...
- 螺旋队列(p98)
先判断这个坐标代表的数位于哪一层,然后依据该层最大的数去计算这个坐标所代表的数. #include"iostream" #include"stdio.h" #i ...
- vue 权限管理深度探究
实现思路如下:1.网页路由(route)中定义的每个路由都有meta属性,属性值防止可访问该路由的值.2.路由的全局前置守卫(beforeEach)会判断路由用户是否登录(未登录跳转至登录界面),以及 ...