Friends and Enemies

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 485    Accepted Submission(s): 271

Problem Description
On an isolated island, lived some dwarves. A king (not a dwarf) ruled the island and the seas nearby, there are abundant cobblestones of varying colors on the island. Every two dwarves on the island are either friends or enemies. One day, the king demanded that each dwarf on the island (not including the king himself, of course) wear a stone necklace according to the following rules:
  
  For any two dwarves, if they are friends, at least one of the stones from each of their necklaces are of the same color; and if they are enemies, any two stones from each of their necklaces should be of different colors. Note that a necklace can be empty.
  
  Now, given the population and the number of colors of stones on the island, you are going to judge if it's possible for each dwarf to prepare himself a necklace.
 
Input
Multiple test cases, process till end of the input. 
  
  For each test case, the one and only line contains 2 positive integers M,N (M,N<231) representing the total number of dwarves (not including the king) and the number of colors of stones on the island.
 
Output
For each test case, The one and only line of output should contain a character indicating if it is possible to finish the king's assignment. Output ``T" (without quotes) if possible, ``F" (without quotes) otherwise.
 
Sample Input
20 100
 
Sample Output
T
 
Source
 
 
 
 
 
 
#include <cstdio>
#define ll long long int main()
{
ll n, m;
while(~scanf("%I64d%I64d", &n, &m)){
printf((n/2)*(n-n/2) <= m ? "T\n" : "F\n");
}
return 0;
}

  

HDU 5874 Friends and Enemies的更多相关文章

  1. HDU 5874 Friends and Enemies 【构造】 (2016 ACM/ICPC Asia Regional Dalian Online)

    Friends and Enemies Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Othe ...

  2. hdu 5874 Friends and Enemies icpc大连站网络赛 1007 数学

    #include<stdio.h> #include<iostream> #include<algorithm> #include<math.h> #i ...

  3. hdu 5874

    On an isolated island, lived some dwarves. A king (not a dwarf) ruled the island and the seas nearby ...

  4. hdu 5131 Song Jiang's rank list

    题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5131 Song Jiang's rank list Description <Shui Hu Z ...

  5. hdu 1155 Bungee Jumping

    http://acm.hdu.edu.cn/showproblem.php?pid=1155 Bungee Jumping Time Limit: 2000/1000 MS (Java/Others) ...

  6. Hdu 3966-Aragorn's Story LCT,动态树

    题目:http://acm.hdu.edu.cn/showproblem.php?pid=3966 Aragorn's Story Time Limit: 10000/3000 MS (Java/Ot ...

  7. HDU 5889 Barricade 【BFS+最小割 网络流】(2016 ACM/ICPC Asia Regional Qingdao Online)

    Barricade Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total S ...

  8. HDU 5876 Sparse Graph 【补图最短路 BFS】(2016 ACM/ICPC Asia Regional Dalian Online)

    Sparse Graph Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)To ...

  9. hdu 4970 Killing Monsters(数学题)

    题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4970 Problem Description Kingdom Rush is a popular TD ...

随机推荐

  1. Android ActionBar与ViewPager合用

    内容可以左右滑动,因为使用了ViewPager(我这里用了V4包) view_pager_main.xml <?xml version="1.0" encoding=&quo ...

  2. 关于dynamic_cast

    http://www.groad.net/bbs/read.php?tid-5476.html dynamic_cast 进行运行时强制转换.如果在执行时转换非法,则会转换失败.dynamic_cas ...

  3. CentOS5下配置JDK1.6+TOMCAT6

    CentOS5下配置JDK1.6+TOMCAT6 安装环境:centos 5.5+jdk1.6.0_25+tomcat6.0.32 一.下载安装jdk1.6.0_25 mkdir /usr/java ...

  4. NAMESPACE_ERR: An attempt is made to create or change an object in a way which is incorrect with regard to namespaces.

    解决办法: http://stackoverflow.com/questions/4037125/namespace-err-an-attempt-is-made-to-create-or-chang ...

  5. hibernate.cfg.xml hibernate 配置文件模板

    <?xml version='1.0' encoding='UTF-8'?> <!--表明解析本XML文件的DTD文档位置,DTD是Document Type Definition ...

  6. jackson基于注解的简单使用

    Jackson提供了一系列注解,方便对JSON序列化和反序列化进行控制,下面介绍一些常用的注解. 1.@JsonIgnore 此注解用于属性上,作用是进行JSON操作时忽略该属性. 2.@JsonFo ...

  7. 李洪强iOS开发之OC语言构造方法

    OC语言构造方法 一.构造方法 (一)构造方法的调用 完整的创建一个可用的对象:Person *p=[Person new]; New方法的内部会分别调用两个方法来完成2件事情,1)使用alloc方法 ...

  8. lintcode:Valid Sudoku 判断数独是否合法

    题目: 判断数独是否合法 请判定一个数独是否有效.该数独可能只填充了部分数字,其中缺少的数字用 . 表示. 样例 下列就是一个合法数独的样例. 注意 一个合法的数独(仅部分填充)并不一定是可解的.我们 ...

  9. ASP.Net WebForm学习笔记:一、aspx与服务器控件探秘

    作者:周旭龙 出处:http://edisonchou.cnblogs.com 开篇:毫无疑问,ASP.Net WebForm是微软推出的一个跨时代的Web开发模式,它将WinForm开发模式的快捷便 ...

  10. spring是怎样面向接口编程的?

    1.只要分层,就涉及到接口来连接.各层之间只通过接口来向外暴露功能. 2.spring中service层调用dao层时候,service层声明接口变量,具体接口实现可以ioc注入