Friends and Enemies

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 485    Accepted Submission(s): 271

Problem Description
On an isolated island, lived some dwarves. A king (not a dwarf) ruled the island and the seas nearby, there are abundant cobblestones of varying colors on the island. Every two dwarves on the island are either friends or enemies. One day, the king demanded that each dwarf on the island (not including the king himself, of course) wear a stone necklace according to the following rules:
  
  For any two dwarves, if they are friends, at least one of the stones from each of their necklaces are of the same color; and if they are enemies, any two stones from each of their necklaces should be of different colors. Note that a necklace can be empty.
  
  Now, given the population and the number of colors of stones on the island, you are going to judge if it's possible for each dwarf to prepare himself a necklace.
 
Input
Multiple test cases, process till end of the input. 
  
  For each test case, the one and only line contains 2 positive integers M,N (M,N<231) representing the total number of dwarves (not including the king) and the number of colors of stones on the island.
 
Output
For each test case, The one and only line of output should contain a character indicating if it is possible to finish the king's assignment. Output ``T" (without quotes) if possible, ``F" (without quotes) otherwise.
 
Sample Input
20 100
 
Sample Output
T
 
Source
 
 
 
 
 
 
#include <cstdio>
#define ll long long int main()
{
ll n, m;
while(~scanf("%I64d%I64d", &n, &m)){
printf((n/2)*(n-n/2) <= m ? "T\n" : "F\n");
}
return 0;
}

  

HDU 5874 Friends and Enemies的更多相关文章

  1. HDU 5874 Friends and Enemies 【构造】 (2016 ACM/ICPC Asia Regional Dalian Online)

    Friends and Enemies Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Othe ...

  2. hdu 5874 Friends and Enemies icpc大连站网络赛 1007 数学

    #include<stdio.h> #include<iostream> #include<algorithm> #include<math.h> #i ...

  3. hdu 5874

    On an isolated island, lived some dwarves. A king (not a dwarf) ruled the island and the seas nearby ...

  4. hdu 5131 Song Jiang's rank list

    题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5131 Song Jiang's rank list Description <Shui Hu Z ...

  5. hdu 1155 Bungee Jumping

    http://acm.hdu.edu.cn/showproblem.php?pid=1155 Bungee Jumping Time Limit: 2000/1000 MS (Java/Others) ...

  6. Hdu 3966-Aragorn's Story LCT,动态树

    题目:http://acm.hdu.edu.cn/showproblem.php?pid=3966 Aragorn's Story Time Limit: 10000/3000 MS (Java/Ot ...

  7. HDU 5889 Barricade 【BFS+最小割 网络流】(2016 ACM/ICPC Asia Regional Qingdao Online)

    Barricade Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total S ...

  8. HDU 5876 Sparse Graph 【补图最短路 BFS】(2016 ACM/ICPC Asia Regional Dalian Online)

    Sparse Graph Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)To ...

  9. hdu 4970 Killing Monsters(数学题)

    题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4970 Problem Description Kingdom Rush is a popular TD ...

随机推荐

  1. VS2010 MFC DataGrid绑定实例

    VS2010环境下MFC使用DataGrid绑定数据源 参考:http://blog.csdn.net/fddqfddq/article/details/7874706 详细介绍如何在MFC中使用Da ...

  2. POJ 3321 Apple Tree(后根遍历将树转化成序列,用树状数组维护)

    题意:一棵树,有很多分叉,每个分叉上最多有1个苹果. 给出n,接下来n-1行,每行u,v,表示分叉u,v之间有树枝相连.这里数据中u相当于树中的父节点,v相当于子节点. 给出两个操作: 1.C x  ...

  3. cast——java类型转换

    以下例说之: byte b = 3; //??? 3是一个int常量,但是会自动判断3是不是在byte类型的范围内 b = b + 2; //Type mismatch: cannot convert ...

  4. Spring多资源文件properties的配置

    Spring简化了加载资源文件的配置,可以通过<context:property-placeholder去加载,这个元素的写法如下: <context:property-placehold ...

  5. java基础面试题(转)

    JAVA相关基础知识1.面向对象的特征有哪些方面 1.抽象:抽象就是忽略一个主题中与当前目标无关的那些方面,以便更充分地注意与当前目标有关的方面.抽象并不打算了解全部问题,而只是选择其中的一部分,暂时 ...

  6. springmvc环境的搭建

    最近应公司要求,用了2天时间学了springmvc的搭建,就简单总结一下: springmvc和struts2的比较,因为我是学过struts的,它们都是基于mvc模式而设计的web层框架 它们最大的 ...

  7. Yii2 的问题解决方案

    yii2 Class 'app\controllers\AccessControl' not found 一般是命名空间问题, 写成\yii\filters\AccessControl::classN ...

  8. 关于Linux的时间与时区

    转:http://linux.chinaunix.net/techdoc/beginner/2007/06/22/960790.shtml 首先要说明的是我的系统是fedora,其他系统可能不完全相同 ...

  9. 使用 Spring 3 来创建 RESTful Web Services(转)

    使用 Spring 3 来创建 RESTful Web Services 在 Java™ 中,您可以使用以下几种方法来创建 RESTful Web Service:使用 JSR 311(311)及其参 ...

  10. SQL效率问题

    关于in和or的效率对比:http://blog.chinaunix.net/uid-20639775-id-3416737.html 在没有索引的情况下,in的效率高 SQL语句效率:http:// ...