POJ 1064 Cable master (二分查找)
Description
Inhabitants of the Wonderland have decided to hold a regional programming contest. The Judging Committee has volunteered and has promised to organize the most honest contest ever. It was decided to connect computers for the contestants using a "star" topology - i.e. connect them all to a single central hub. To organize a truly honest contest, the Head of the Judging Committee has decreed to place all contestants evenly around the hub on an equal distance from it.
To buy network cables, the Judging Committee has contacted a local network solutions provider with a request to sell for them a specified number of cables with equal lengths. The Judging Committee wants the cables to be as long as possible to sit contestants as far from each other as possible.
The Cable Master of the company was assigned to the task. He knows the length of each cable in the stock up to a centimeter,and he can cut them with a centimeter precision being told the length of the pieces he must cut. However, this time, the length is not known and the Cable Master is completely puzzled.
You are to help the Cable Master, by writing a program that will determine the maximal possible length of a cable piece that can be cut from the cables in the stock, to get the specified number of pieces.
Input
The first line of the input file contains two integer numb ers N and K, separated by a space. N (1 = N = 10000) is the number of cables in the stock, and K (1 = K = 10000) is the number of requested pieces. The first line is followed by N lines with one number per line, that specify the length of each cable in the stock in meters. All cables are at least 1 meter and at most 100 kilometers in length. All lengths in the input file are written with a centimeter precision, with exactly two digits after a decimal point.
Output
Write to the output file the maximal length (in meters) of the pieces that Cable Master may cut from the cables in the stock to get the requested number of pieces. The number must be written with a centimeter precision, with exactly two digits after a decimal point.
If it is not possible to cut the requested number of pieces each one being at least one centimeter long, then the output file must contain the single number "0.00" (without quotes).
Sample Input
4 11
8.02
7.43
4.57
5.39
Sample Output
2.00
分析:
根据最长的棍子二分枚举切割长度。
这点很容易想到。
本题麻烦的地方在于小数的二分。
由于精度丢失问题,如果直接使用double进行二分,那么二分确定的最大长度必然是不精确的。
如:只有1根100.0的棍子,分成10段。如果使用double二分,那么就算把精度控制到0.0000001,
最后的答案也就9.9999666。,而不是10.
由于只要求2位小数,则把所有棍子长度*100,变成整数二分即可。
最后答案ans/=100。
代码:
#include<iostream>
#include<stdio.h>
#include<stdlib.h>
#include<math.h>
using namespace std;
int N,K;
double L[10009];
///判断每小段的长度为x的话,能不能满足分成K段
bool C(double x)
{
int num=0;
for(int i=0; i<N; i++)
{
num+=(int)(L[i]/x);
}
return num>=K;
}
void solve()
{
double lb=0,ub=0x3f3f3f3f;
for(int i=0; i<100; i++)///尽可能的将分的范围具体
{
double mid=(lb+ub)/2;
if(C(mid)) lb=mid;
else ub=mid;
}
printf("%.2lf\n",floor(ub*100)/100);
}
int main()
{
scanf("%d%d",&N,&K);
for(int i=0; i<N; i++)
scanf("%lf",&L[i]);
solve();
return 0;
}
POJ 1064 Cable master (二分查找)的更多相关文章
- [POJ] 1064 Cable master (二分查找)
题目地址:http://poj.org/problem?id=1064 有N条绳子,它们的长度分别为Ai,如果从它们中切割出K条长度相同的绳子,这K条绳子每条最长能有多长. 二分绳子长度,然后验证即可 ...
- POJ 1064 Cable master (二分答案)
题目链接:http://poj.org/problem?id=1064 有n条绳子,长度分别是Li.问你要是从中切出m条长度相同的绳子,问你这m条绳子每条最长是多少. 二分答案,尤其注意精度问题.我觉 ...
- poj 1064 Cable master 二分 题解《挑战程序设计竞赛》
地址 http://poj.org/problem?id=1064 题解 二分即可 其实 对于输入与精度计算不是很在行 老是被卡精度 后来学习了一个函数 floor 向负无穷取整 才能ac 代码如下 ...
- POJ 1064 Cable master | 二分+精度
题目: 给n个长度为l[i](浮点数)的绳子,要分成k份相同长度的 问最多多长 题解: 二分长度,控制循环次数来控制精度,输出也要控制精度<wa了好多次> #include<cstd ...
- POJ 1064 Cable master (二分)
题意:给定 n 条绳子,它们的长度分别为 ai,现在要从这些绳子中切出 m 条长度相同的绳子,求最长是多少. 析:其中就是一个二分的水题,但是有一个坑,那么就是最后输出不能四舍五入,只能向下取整. 代 ...
- POJ 1064 Cable master(二分查找+精度)(神坑题)
POJ 1064 Cable master 一开始把 int C(double x) 里面写成了 int C(int x) ,莫名奇妙竟然过了样例,交了以后直接就wa. 后来发现又把二分查找的判断条 ...
- poj 1064 Cable master 判断一个解是否可行 浮点数二分
poj 1064 Cable master 判断一个解是否可行 浮点数二分 题目链接: http://poj.org/problem?id=1064 思路: 二分答案,floor函数防止四舍五入 代码 ...
- 二分搜索 POJ 1064 Cable master
题目传送门 /* 题意:n条绳子问切割k条长度相等的最长长度 二分搜索:搜索长度,判断能否有k条长度相等的绳子 */ #include <cstdio> #include <algo ...
- [ACM] poj 1064 Cable master (二分查找)
Cable master Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 21071 Accepted: 4542 Des ...
随机推荐
- 3ds Max学习日记(一)
暑假闲来无事学习一发3ds Max.为啥要学这玩意?貌似可以用这东西三维建模.暑期生产实习选了一个搞vr的导师,貌似他忙得很,无奈只好先自己研究一下啦~ vr神马的还是有点意思的,虽然自己仅仅 ...
- wine update错误 "the cache has no package" error when wine update is available
网址:https://bugs.launchpad.net/pipelight/+bug/1318321/
- lucene 学习之编码篇
本文环境:lucene5.2 JDK1.7 IKAnalyzer 引入lucene相关包 <!-- lucene核心包 --> <dependency> <g ...
- MyBatis的架构设计以及实例分析
MyBatis是目前非常流行的ORM框架,它的功能很强大,然而其实现却比较简单.优雅.本文主要讲述MyBatis的架构设计思路,并且讨论MyBatis的几个核心部件,然后结合一个sel ...
- 第43天:事件对象event
一.事件对象事件:onmouseover. onmouseout. onclickevent //事件的对象 兼容写法:var event = event || window.event; event ...
- ASP.NET MVC4中使用bootstrip模态框时弹不出的问题
最近发现使用在MVC中使用bootstrip的模态框时弹不出来,但单独建立一HTML文件时可以弹出,说明代码没有问题,经过多次测试发现,在MVC的cshtml文件中添加上以下语句就能正常 @{ Lay ...
- MATLAB中imfilter函数
功能:对任意类型数组或多维图像进行滤波. 用法:B = imfilter(A,H) B = imfilter(A,H,option1,option2,...) 或写作g = imfilter(f, w ...
- C++除法运算 // 静态断言
1.C++中"/"运算:对两个整数做除法,结果仍为整数,如果它的商包含小数部分,则小树部分会被截除. C++ Primer 第五章 P130 2.静态断言(static_asser ...
- uva1086 The Ministers' Major Mess
题意:有n 个议案,m 个大臣,每个大臣会对其中的ki 个议案投票,为赞成或反对.现要你判断是否存在一种方案,使得每个大臣有大于一半的投票被满足.若存在,还需判断某个议案是不是一定要通过,或者一定不能 ...
- Windows系统Unity3D中的快捷键
Windows系统Unity3D中的快捷键 组合键 键 功能 File 文件 Ctrl N New Scene 新建场景 Ctrl O Open Scene 打开场景 Ctrl S Sav ...