JS 跳转后保持当前参数

跳转
                var data = str+"&jc=0"+ "&data=" + $("form").serialize().replace(/&/g, "(").replace(/=/g, ")");
                window.location.href = data;
接收
          var data1 = data.Replace("(", "&").Replace(")", "=");
            ViewBag.URL = "/Backxx/xxx/List/?id=5001" + "&" + data1; //调回到菜单

html

     function GetUrlRelativePath() {
            var url = document.location.toString();
            var arrUrl = url.split("//");

            var start = arrUrl[1].indexOf("/");
            var relUrl = arrUrl[1].substring(start);//stop省略，截取从start开始到结尾的所有字符
            relUrl = relUrl.replace(/&/g, '(');
            //if (relUrl.indexOf("?") != -1) {
            //    relUrl = relUrl.split("?")[0];
            //}
            return relUrl;
        }
        window.location = url + "/?id=" + that.getAttribute("data_id") + "&data=" + GetUrlRelativePath();

cs

string data = request["data"];
ViewBag.Url = data;

html

  <a href="" id="ret" class="back" data-url="@ViewBag.Url">返回</a>

            document.getElementById("ret").onclick = function () {
                var URL = this.getAttribute("data-url").replace(/\(/g, '&');
                window.location.href = URL;
                return false;
            };