题意:

输入一个正整数N(<=1000),接着输入N行数据,每行包括一个ID和一个密码,长度不超过10的字符串,如果有歧义字符就将其修改。输出修改过多少组密码并按输入顺序输出ID和修改后的密码,如果没有修改过就输出There are N accounts and no account is modified。(根据样例如果N==1,are改成is并且accounts不加s)

AAAAAccepted code:

 #define HAVE_STRUCT_TIMESPEC
#include<bits/stdc++.h>
using namespace std;
char s[][];
char x[][];
int ans[];
int main(){
int n;
cin>>n;
int cnt=;
for(int i=;i<=n;++i){
cin>>x[i];
cin>>s[i];
int flag=;
for(int j=;s[i][j]!=;++j)
if(s[i][j]=='')
s[i][j]='@',flag=;
else if(s[i][j]=='')
s[i][j]='%',flag=;
else if(s[i][j]=='l')
s[i][j]='L',flag=;
else if(s[i][j]=='O')
s[i][j]='o',flag=;
if(flag)
ans[++cnt]=i;
}
if(!cnt&&n==)
cout<<"There is "<<n<<" account and no account is modified";
else if(!cnt&&n>)
cout<<"There are "<<n<<" accounts and no account is modified";
else{
cout<<cnt<<"\n";
for(int i=;i<=cnt;++i)
cout<<x[ans[i]]<<" "<<s[ans[i]]<<"\n";
}
return ;
}

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