Given a string S and a string T, count the number of distinct subsequences of T in S.

A subsequence of a string is a new string which is formed from the original string by deleting some (can be none) of the characters without disturbing the relative positions of the remaining characters. (ie, "ACE" is a subsequence of "ABCDE" while "AEC" is not).

Here is an example:
S = "rabbbit", T = "rabbit"

Return 3.

解题思路:

dp问题,弄清递推公式即可,参考Distinct Subsequences@LeetCode ,JAVA实现如下:

	public int numDistinct(String s, String t) {
if (t.length() == 0)
return 1;
int[] dp = new int[t.length() + 1];
dp[0] = 1;
for (int i = 0; i < s.length(); i++) {
int last = 1;
for (int j = 0; j < t.length(); j++) {
if (dp[j] == 0)
break;
int temp = dp[j + 1];
if (s.charAt(i) == t.charAt(j))
dp[j + 1] += last;
last = temp;
}
}
return dp[t.length()];
}

Java for LeetCode 115 Distinct Subsequences【HARD】的更多相关文章

  1. leetcode 115 Distinct Subsequences ----- java

    Given a string S and a string T, count the number of distinct subsequences of T in S. A subsequence ...

  2. [LeetCode] 115. Distinct Subsequences 不同的子序列

    Given a string S and a string T, count the number of distinct subsequences of S which equals T. A su ...

  3. [leetcode]115. Distinct Subsequences 计算不同子序列个数

    Given a string S and a string T, count the number of distinct subsequences of S which equals T. A su ...

  4. Leetcode 115 Distinct Subsequences 解题报告

    Distinct Subsequences Total Accepted: 38466 Total Submissions: 143567My Submissions Question Solutio ...

  5. Leetcode#115 Distinct Subsequences

    原题地址 转化为求非重路径数问题,用动态规划求解,这种方法还挺常见的 举个例子,S="aabb",T="ab".构造如下地图("."表示空位 ...

  6. Java for LeetCode 207 Course Schedule【Medium】

    There are a total of n courses you have to take, labeled from 0 to n - 1. Some courses may have prer ...

  7. Java for LeetCode 146 LRU Cache 【HARD】

    Design and implement a data structure for Least Recently Used (LRU) cache. It should support the fol ...

  8. Java for LeetCode 072 Edit Distance【HARD】

    Given two words word1 and word2, find the minimum number of steps required to convert word1 to word2 ...

  9. Java for LeetCode 097 Interleaving String 【HARD】

    Given s1, s2, s3, find whether s3 is formed by the interleaving of s1 and s2. For example, Given: s1 ...

随机推荐

  1. C++面试试题汇总1

    1.C和C++的主要区别是什么? 答:1.C++语言包括过程性语言部分和类部分,过程性语言部分与C并无本质的差别,类部分是C语言中所没有的,它是面向对象程序设计的主体. 2.程序设计方法上已从结构化程 ...

  2. 【京东个人中心】——Nodejs/Ajax/HTML5/Mysql爬坑之静态页面

    一.引言 接着上一篇,京东个人中心的所有功能数据分析完成之后,现在需要把静态页面完成,实现过程中要用到的技术有:Bootstrap.html5表单新特性等.除此之外,还要利用Node.js的Expre ...

  3. Web开发人员不容错过的10个HTML5工具

    HTML5已经成为当今世界的一个必定组成部分.由于World Wide Web万维网是使用超文本标记语言来架构和呈现的,于是HTML5成为了最流行的编程语言之中的一个.随着网络的不断扩张,Web开发者 ...

  4. Map接口及其子类

    Map接口操作的是一对对象,即二元偶对象,Map接口中的每一个元素都使用"key--value"的形式存储在集合中. SortedMap接口是排序接口,仅仅要是实现了此接口的子类, ...

  5. 在cmd窗口输入命令遇到You must run this command from a command prompt with administrator privilege怎么办?

    点开始菜单,找到Accessories(附件),找到Command Prompt窗口,点右键,选“run as administrator”(以管理员身份运行),之后再执行先前的命令就好了. 2017 ...

  6. Openstack nova代码部分凝视一

    做个一个没怎么学过python的菜鸟.看源代码是最好的学习方式了,如今就从nova入手,主要凝视一下 nova/compute/api.py 中的 create_instance函数 def _cre ...

  7. cocos2d-x 3.0游戏实例学习笔记 《跑酷》移植到android手机

    说明:这里是借鉴:晓风残月前辈的博客.他是将泰然网的跑酷教程.用cocos2d-x 2.X 版本号重写的,眼下我正在学习cocos2d-X3.0 于是就用cocos2d-X 3.0重写,并做相关笔记 ...

  8. hql小经验

    hql如果查了子对象的属性,那么hql不允许子对象为空!

  9. 使用Hadoop自己的类操作HDFS

    package hdfs; import java.io.FileInputStream; import java.io.FileNotFoundException; import java.io.I ...

  10. Build Your Jekyll Blog (On Github)

    http://kevinjmh.github.io/web/2014/04/20/build-your-jekyll-blog/ 20 April 2014 On GitHub Follow the ...