数学场,做到怀疑人生系列

C - Flip,Flip, and Flip......


Time limit : 2sec / Memory limit : 256MB

Score : 300 points

Problem Statement

There is a grid with infinitely many rows and columns. In this grid, there is a rectangular region with consecutive N rows and M columns, and a card is placed in each square in this region. The front and back sides of these cards can be distinguished, and initially every card faces up.

We will perform the following operation once for each square contains a card:

  • For each of the following nine squares, flip the card in it if it exists: the target square itself and the eight squares that shares a corner or a side with the target square.

It can be proved that, whether each card faces up or down after all the operations does not depend on the order the operations are performed. Find the number of cards that face down after all the operations.

Constraints

  • 1≤N,M≤109
  • All input values are integers.

Input

Input is given from Standard Input in the following format:

N M

Output

Print the number of cards that face down after all the operations.


Sample Input 1

Copy
2 2

Sample Output 1

Copy
0

We will flip every card in any of the four operations. Thus, after all the operations, all cards face up.


Sample Input 2

Copy
1 7

Sample Output 2

Copy
5

After all the operations, all cards except at both ends face down.


Sample Input 3

Copy
314 1592

Sample Output 3

Copy
496080

这个可以找规律,314×5×k的末尾是0 ,然后不断找下去,竟然是这个数-2相乘

#include<bits/stdc++.h>
using namespace std;
long long a,b;
int main(){
cin>>a>>b;
cout<<abs((a-)*(b-));
}

D - Remainder Reminder


Time limit : 2sec / Memory limit : 256MB

Score : 400 points

Problem Statement

Takahashi had a pair of two positive integers not exceeding N(a,b), which he has forgotten. He remembers that the remainder of a divided by b was greater than or equal to K. Find the number of possible pairs that he may have had.

Constraints

  • 1≤N≤105
  • 0≤KN−1
  • All input values are integers.

Input

Input is given from Standard Input in the following format:

N K

Output

Print the number of possible pairs that he may have had.


Sample Input 1

Copy
5 2

Sample Output 1

Copy
7

There are seven possible pairs: (2,3),(5,3),(2,4),(3,4),(2,5),(3,5) and (4,5).


Sample Input 2

Copy
10 0

Sample Output 2

Copy
100

Sample Input 3

Copy
31415 9265

Sample Output 3

Copy
287927211

这个题目骚啊,去暴力统计每个值对应的方案

#include<bits/stdc++.h>
using namespace std;
int main()
{
int n,k;
cin>>n>>k;
long long ans=;
for(int i=k+; i<=n; i++)
ans+=(n/i)*1LL*(i-k)+max(n%i-k+,)-!k;
cout<<ans;
}

AtCoder Regular Contest 091的更多相关文章

  1. AtCoder Regular Contest 091&092

    091E(构造) 题意: 给出n,a,b.你需要构造出一个长度为n的n的排列,其中最长上升子序列的长度为a,最长下降子序列的长度为b. n,a,,b<=3e5 分析: 我们可以构造出这样的数列, ...

  2. AtCoder Regular Contest 061

    AtCoder Regular Contest 061 C.Many Formulas 题意 给长度不超过\(10\)且由\(0\)到\(9\)数字组成的串S. 可以在两数字间放\(+\)号. 求所有 ...

  3. AtCoder Regular Contest 094 (ARC094) CDE题解

    原文链接http://www.cnblogs.com/zhouzhendong/p/8735114.html $AtCoder\ Regular\ Contest\ 094(ARC094)\ CDE$ ...

  4. AtCoder Regular Contest 092

    AtCoder Regular Contest 092 C - 2D Plane 2N Points 题意: 二维平面上给了\(2N\)个点,其中\(N\)个是\(A\)类点,\(N\)个是\(B\) ...

  5. AtCoder Regular Contest 093

    AtCoder Regular Contest 093 C - Traveling Plan 题意: 给定n个点,求出删去i号点时,按顺序从起点到一号点走到n号点最后回到起点所走的路程是多少. \(n ...

  6. AtCoder Regular Contest 094

    AtCoder Regular Contest 094 C - Same Integers 题意: 给定\(a,b,c\)三个数,可以进行两个操作:1.把一个数+2:2.把任意两个数+1.求最少需要几 ...

  7. AtCoder Regular Contest 095

    AtCoder Regular Contest 095 C - Many Medians 题意: 给出n个数,求出去掉第i个数之后所有数的中位数,保证n是偶数. \(n\le 200000\) 分析: ...

  8. AtCoder Regular Contest 102

    AtCoder Regular Contest 102 C - Triangular Relationship 题意: 给出n,k求有多少个不大于n的三元组,使其中两两数字的和都是k的倍数,数字可以重 ...

  9. AtCoder Regular Contest 096

    AtCoder Regular Contest 096 C - Many Medians 题意: 有A,B两种匹萨和三种购买方案,买一个A,买一个B,买半个A和半个B,花费分别为a,b,c. 求买X个 ...

随机推荐

  1. telegraf1.8+influxdb1.6+grafana5.2 环境搭建 结合JMeter3.2

    telegraf1.8+influxdb1.6+grafana5.2 环境搭建 结合JMeter3.2 参考地址:https://blog.csdn.net/laisinanvictor/articl ...

  2. Python+selenium之测试报告(3)

    较测试报告(2),该文章将测试报告和测试截图存放在随机变动的文件夹下面,去除了要存放在指定文件夹下面的限制. 注:遇到问题有: 1.创建由时间自动拼接的多级文件夹 2. import os impor ...

  3. 洛谷 P1145 约瑟夫

    题目描述 n个人站成一圈,从某个人开始数数,每次数到m的人就被杀掉,然后下一个人重新开始数,直到最后只剩一个人.现在有一圈人,k个好人站在一起,k个坏人站在一起.从第一个好人开始数数.你要确定一个最小 ...

  4. BZOJ 3130: [Sdoi2013]费用流 网络流+二分

    3130: [Sdoi2013]费用流 Time Limit: 10 Sec  Memory Limit: 128 MBSec  Special JudgeSubmit: 1230  Solved: ...

  5. vue props 传入对象Object,如果外层更改属性,默认里面是不更新,需要使用 this.$set(this.datese1, 'xsfaDateYear1', '')

    vue props 传入对象Object,如果外层更改属性,默认里面是不更新,需要使用 this.$set(this.datese1, 'xsfaDateYear1', '')

  6. ubuntu下安装eclipse<转>

    转载自http://my.oschina.net/u/1407116/blog/227084      http://my.oschina.net/u/1407116/blog/227087 一 JD ...

  7. iOS快速开发框架--Bee Framework

    Bee Framework是一款iOS快速开发框架,允许开发者使用Objective-C和XML/CSS来进行iPhone和iPad开发,由 Gavin Kwoe 和 QFish 开发并维护. 其早期 ...

  8. virtualvenv+django+uWSGI+nginx 部署

    原创博文 转载请注明出处! 1. virtualvenv 2. django 3. uWSGI 4. nginx 5. 踩坑记录 1. virtualvenv virtualvenv install ...

  9. NOIP2016——大家一起实现の物语

    由于最近硬盘挂了,换了个固态硬盘,比赛结束后四天一直在装Linux,所以最近一直没怎么更新 看起来挺漂亮的 比赛前一个月申请停了一个月晚自习,在我们这座城市里能做到这种事情已经可以被称为奇迹了,并且在 ...

  10. Codevs3324 新斯诺克

    题目描述 Description 斯诺克又称英式台球,是一种流行的台球运动.在球桌上,台面四角以及两长边中心位置各有一个球洞,使用的球分别为1 个白球,15 个红球和6 个彩球(黄.绿.棕.蓝.粉红. ...