JNI DETECTED ERROR IN APPLICATION: input is not valid Modified UTF-8: illegal start byte 0xfe

在使用Jni的JNIEnv->NewStringUTF的时候抛出了异常"JNI DETECTED ERROR IN APPLICATION: input is not valid Modified UTF-8: illegal start byte 0xfe "。网上搜索了一下,这个异常是由于Java虚拟机内部的dalvik/vm/CheckJni.c中的checkUtfString函数抛出的,并且JVM的这个接口明确是不支持四个字节的UTF8字符。因此需要在调用函数之前,对接口传入的字符串进行过滤,过滤函数如下:

checkUtfString

C++
int checkUtfString(const char* bytes)
{
const char* origBytes = bytes;
if (bytes == NULL) {
return -1;
}
while (*bytes != '\0') {
unsigned char utf8 = *(bytes++);
// Switch on the high four bits.
switch (utf8 >> 4) {
case 0x00:
case 0x01:
case 0x02:
case 0x03:
case 0x04:
case 0x05:
case 0x06:
case 0x07: {
// Bit pattern 0xxx. No need for any extra bytes.
break;
}
case 0x08:
case 0x09:
case 0x0a:
case 0x0b:
case 0x0f: {
/*printf("****JNI WARNING: illegal start byte 0x%x\n", utf8);*/
return -1;
}
case 0x0e: {
// Bit pattern 1110, so there are two additional bytes.
utf8 = *(bytes++);
if ((utf8 & 0xc0) != 0x80) {
/*printf("****JNI WARNING: illegal continuation byte 0x%x\n", utf8);*/
return -1;
}
// Fall through to take care of the final byte.
}
case 0x0c:
case 0x0d: {
// Bit pattern 110x, so there is one additional byte.
utf8 = *(bytes++);
if ((utf8 & 0xc0) != 0x80) {
/*printf("****JNI WARNING: illegal continuation byte 0x%x\n", utf8);*/
return -1;
}
break;
}
}
}
return 0;
}
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int checkUtfString(const char* bytes)
{
    const char* origBytes = bytes;
    if (bytes == NULL) {
        return -1;
    }
    while (*bytes != '\0') {
       unsigned char utf8 = *(bytes++);
        // Switch on the high four bits.
        switch (utf8 >> 4) {
            case 0x00:
            case 0x01:
            case 0x02:
            case 0x03:
            case 0x04:
            case 0x05:
            case 0x06:
            case 0x07: {
                // Bit pattern 0xxx. No need for any extra bytes.
                break;
            }
            case 0x08:
            case 0x09:
            case 0x0a:
            case 0x0b:
            case 0x0f: {
                /*printf("****JNI WARNING: illegal start byte 0x%x\n", utf8);*/
                return -1;
            }
            case 0x0e: {
                // Bit pattern 1110, so there are two additional bytes.
                utf8 = *(bytes++);
                if ((utf8 & 0xc0) != 0x80) {
                    /*printf("****JNI WARNING: illegal continuation byte 0x%x\n", utf8);*/
                    return -1;
                }
                // Fall through to take care of the final byte.
            }
            case 0x0c:
            case 0x0d: {
                // Bit pattern 110x, so there is one additional byte.
                utf8 = *(bytes++);
                if ((utf8 & 0xc0) != 0x80) {
                    /*printf("****JNI WARNING: illegal continuation byte 0x%x\n", utf8);*/
                    return -1;
                }
                break;
            }
        }
    }
    return 0;
}

参考链接 android jni中 utf-8的check

发布者

 

默默

默默码农 查看所有由默默发布的文章

#########################################################################################################

newStringUTF出现input is not valid Modified UTF-8错误解决办法

2013年10月12日 ⁄ 综合 ⁄ 共 883字 ⁄ 字号 ⁄ 评论关闭
 

JNI调用newStringUTF时遇到不认识的字符串就直接出错退出~~,网上原因是dalvik/vm/CheckJni.c里面的checkUtfString函数检查通不过.找了半天没找到修正办法,把这个函数改了下,当做一个修正函数,下面是代码

void correctUtfBytes(char* bytes) {
char three = 0;
while (*bytes != '\0') {
unsigned char utf8 = *(bytes++);
three = 0;
// Switch on the high four bits.
switch (utf8 >> 4) {
case 0x00:
case 0x01:
case 0x02:
case 0x03:
case 0x04:
case 0x05:
case 0x06:
case 0x07:
// Bit pattern 0xxx. No need for any extra bytes.
break;
case 0x08:
case 0x09:
case 0x0a:
case 0x0b:
case 0x0f:
/*
* Bit pattern 10xx or 1111, which are illegal start bytes.
* Note: 1111 is valid for normal UTF-8, but not the
* modified UTF-8 used here.
*/
*(bytes-1) = '?';
break;
case 0x0e:
// Bit pattern 1110, so there are two additional bytes.
utf8 = *(bytes++);
if ((utf8 & 0xc0) != 0x80) {
--bytes;
*(bytes-1) = '?';
break;
}
three = 1;
// Fall through to take care of the final byte.
case 0x0c:
case 0x0d:
// Bit pattern 110x, so there is one additional byte.
utf8 = *(bytes++);
if ((utf8 & 0xc0) != 0x80) {
--bytes;
if(three)--bytes;
*(bytes-1)='?';
}
break;
}
}
} http://www.xuebuyuan.com/1240531.html
http://www.mobibrw.com/2016/2859

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