水题。每种情况取最小值即可。

#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std; long long d1,d2,d3; int main()
{
scanf("%lld%lld%lld",&d1,&d2,&d3);
long long X,Y,Z;
X=min(d1,d2+d3);
Y=min(d2,d1+d3);
Z=min(d3,d1+d2);
long long ans=min(*X+*Y,X+Y+Z);
printf("%lld\n",ans);
return ;
}

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