SqlServer函数获取指定日期后的第某个工作日

获取工作日

　　需要编写一个SqlServer函数，F_getWorkday，传入两个参数，第一个为时间date，第二个参数为第几个工作日num。调用F_getWorkday后返回date之后的第num个工作日。

　　现有节假日安排表如下：

　　

 drop function [dbo].[F_getWorkday];
 create   function [dbo].[F_getWorkday](
    @staDate   datetime,
    @workDay   int
 )
 returns   datetime
 as
 begin
   declare @curDay int ;
   declare @tempDay datetime;
   declare @weekday int;
   declare @endDate datetime;
   set @curDay=1;
   select @tempDay = dateadd(day,1,@staDate);
   while @curDay <=@workDay
   begin
      declare @tempDay2 datetime; --没有放假
      if(select COUNT(1) from dategrid where set_type=1 and begin_date<=@tempDay and end_date>=@tempDay)<=0
         begin--没加班
             if(select COUNT(1) from dategrid where set_type=2 and begin_date<=@tempDay and end_date>=@tempDay)<=0
                 begin
                   select @weekday = datepart(weekday, @tempDay);
                   if (@weekday=1)--星期天
                       begin
                          select @tempDay = dateadd(day,1,@tempDay);
                       end
                   else if(@weekday>=2 and @weekday<=6)--周一到周五
                       begin
                           set @endDate = @tempDay;
                           select @tempDay = dateadd(day,1,@tempDay);
                         set @curDay = @curDay + 1;
                       end
                   else--周六
                       begin
                          select @tempDay = dateadd(day,2,@tempDay);
                       end;
                 end
             else--加班
                 begin
                     set @tempDay2 = null;
                     select @tempDay2 = end_date from dategrid where set_type=2 and begin_date<=@tempDay and end_date>=@tempDay;--@tempDay在加班中的最后一天
                     set @endDate = @tempDay2;
                     select @tempDay = dateadd(day,1,@tempDay2);
                     set @curDay = @curDay + 1;
                 end;
         end
      else--放假
         begin
             select @tempDay2 = end_date from dategrid where set_type=1 and begin_date<=@tempDay and end_date>=@tempDay;--@tempDay在放假中的最后一天
             select @tempDay = dateadd(day,1,@tempDay2);
             set @endDate =@tempDay;--最后一天在假期情况
             set @curDay = @curDay + 1;--叠加器加一次
         end;
   end;
   return @endDate;
 end