POJ 2609 Ferry Loading
双塔DP+输出路径。
由于内存限制,DP只能开滚动数组来记录。
我的写法比较渣,但是POJ能AC,但是ZOJ依旧MLE,更加奇怪的是Uva上无论怎么改都是WA,其他人POJ过的交到Uva也是WA。
#include<cstdio>
#include<cstring>
#include<cmath>
#include<stack>
#include<algorithm>
using namespace std; int dp[][+];
struct P
{
int x,y;
int f;
}pre[][+];
int sum;
int a[],tot; void read()
{
while()
{
scanf("%d",&a[tot+]);
if(a[tot+]==) break;
tot++;
} for(int i=;i<=tot;i++)
for(int j=;j<=*sum;j++)
pre[i][j].f=-; for(int j=;j<=*sum;j++) dp[][j]=dp[][j]=0x7FFFFFFF;
} void init()
{
sum=sum*;
tot=;
} void work()
{
int now=;
dp[][a[]+sum]=;
pre[][a[]+sum].f=;
dp[][-a[]+sum]=;
pre[][-a[]+sum].f=; for(int i=;i<=tot;i++)
{
now=now^;
for(int j=;j<=*sum;j++) dp[now][j]=0x7FFFFFFF;
for(int j=;j<=*sum;j++)
{
if(dp[now^][j]==0x7FFFFFFF) continue; int tmp=j-sum; if(tmp>=)
{
if(dp[now^][j]+tmp+a[i]<=sum&&dp[now^][j]<dp[now][tmp+a[i]+sum])
{
dp[now][tmp+a[i]+sum]=dp[now^][j];
pre[i][tmp+a[i]+sum].x=i-;
pre[i][tmp+a[i]+sum].y=j;
pre[i][tmp+a[i]+sum].f=;
} if(max(tmp,a[i])+dp[now^][j]<=sum&&dp[now^][j]+min(tmp,a[i])<dp[now][tmp-a[i]+sum])
{
dp[now][tmp-a[i]+sum]=dp[now^][j]+min(tmp,a[i]);
pre[i][tmp-a[i]+sum].x=i-;
pre[i][tmp-a[i]+sum].y=j;
pre[i][tmp-a[i]+sum].f=;
}
} else
{
tmp=-tmp;
if(dp[now^][j]+tmp+a[i]<=sum&&dp[now^][j]<dp[now][-(tmp+a[i])+sum])
{
dp[now][-(tmp+a[i])+sum]=dp[now^][j];
pre[i][-(tmp+a[i])+sum].x=i-;
pre[i][-(tmp+a[i])+sum].y=j;
pre[i][-(tmp+a[i])+sum].f=;
} if(max(tmp,a[i])+dp[now^][j]<=sum&&dp[now^][j]+min(tmp,a[i])<dp[now][a[i]-tmp+sum])
{
dp[now][a[i]-tmp+sum]=dp[now^][j]+min(tmp,a[i]);
pre[i][a[i]-tmp+sum].x=i-;
pre[i][a[i]-tmp+sum].y=j;
pre[i][a[i]-tmp+sum].f=;
} }
}
}
} void output()
{
bool flag=;
int now_i,now_j;
for(int i=tot;i>=;i--)
{
for(int j=*sum;j>=;j--)
{
if(pre[i][j].f!=-)
{
now_i=i;
now_j=j;
flag=;
break;
}
}
if(flag) break;
} if(flag==) {printf("0\n");return;}
printf("%d\n",now_i); stack<int>S; while()
{
if(pre[now_i][now_j].f==-) break;
S.push(pre[now_i][now_j].f); int newx,newy;
newx=pre[now_i][now_j].x;
newy=pre[now_i][now_j].y;
now_i=newx;
now_j=newy;
} int k=;
int left=;
int right=; while(!S.empty())
{
if(S.top()==)
{
printf("port\n");
left=left+a[k];k++;
}
else
{
printf("starboard\n");
right=right+a[k];k++;
}
S.pop();
}
} int main()
{
scanf("%d",&sum);
init();
read();
work();
output();
return ;
}
POJ 2609 Ferry Loading的更多相关文章
- POJ 2609 Ferry Loading(双塔DP)
Ferry Loading Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 1807 Accepted: 509 Sp ...
- poj 2336 Ferry Loading II ( 【贪心】 )
Ferry Loading II Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 3704 Accepted: 1884 ...
- Ferry Loading III[HDU1146]
Ferry Loading IIITime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Tot ...
- POJ-2336 Ferry Loading II(简单DP)
Ferry Loading II Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 3763 Accepted: 1919 Desc ...
- poj-2336 Ferry Loading II(dp)
题目链接: Ferry Loading II Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 3946 Accepted: ...
- TOJ 2419: Ferry Loading II
2419: Ferry Loading II Time Limit(Common/Java):1000MS/10000MS Memory Limit:65536KByteTotal Subm ...
- Ferry Loading II_贪心
Description Before bridges were common, ferries were used to transport cars across rivers. River fer ...
- [POJ2336]Ferry Loading II
题目描述 Description Before bridges were common, ferries were used to transport cars across rivers. Rive ...
- POJ 3377 Ferry Lanes
虽然它出现在dp专场里···但是我第一反应是一道最短路题···不过幸好它出现在dp专场里···因为我不怎么会dijstra什么的··· 题意:一条河上有N+1对码头,每个相邻码头之间需要一定时间到达, ...
随机推荐
- 编译使用tinyxml
环境: win7 32位旗舰版,VS2010,tinyxml_2_6_2版本 1.下载tinyxml,并解压到tinyxml文件夹下 2.生成动态链接库 原生的Tinyxml只支持静态库(没有在.h文 ...
- ReactiveCocoa 浅析
转载自:http://limboy.me/ios/2013/12/27/reactivecocoa-2.html ReactiveCocoa是Github开源的一款cocoa FRP 框架,我在之 ...
- UVALive 2035 The Monocycle(BFS状态处理+优先队列)
这道题目真是非常坎坷啊,WA了很多次,但所有的思路都是奔着广搜去想的,一开始出现了比答案大的数据,才想到了应该是优先队列,再说加上也肯定不会错.一开始我读错了题意,以为旋转并且前行需要的时间跟其他一样 ...
- android平台菜单返回键监听
//声明 void onKeyReleased(EventKeyboard::KeyCode keyCode, Event* event); //实现 //按键控制(检测onKeyReleased有反 ...
- ubuntu 12.04 安装snort acidbase相关注意事项
一.安装Snort 1.安装libpcap 1 apt-get install libpcap-dev 2.安装snort 1 2 apt-get install snort apt-get inst ...
- Stem Cell 华人科学家
Jianping Fu 密歇根大学机械工程系生物医学工程专业 PhD, Massachusetts Institute of Technology, 2007MS, University of Cal ...
- Chapter 1 First Sight——17
Once I got around the cafeteria, building three was easy to spot. 我一走出自助餐厅,很容易看见建筑三. A large black & ...
- Chapter 1 First Sight——15
The red-haired woman looked up. "Can I help you?" 红头发的女人抬头看了一眼说,有什么我能帮助你的吗? "I'm Isab ...
- HDU 3487 Play with Chain | Splay
Play with Chain Time Limit: 6000/2000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) ...
- margin:0 auto在ie7浏览器里面无效
把文件头改成 <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN""http://www.w ...