bzoj4698

题解：

后缀数组

对所有序列差分一下

公共串的长度+1就是答案了

二分 扫一遍height即可,..

代码：

#include <bits/stdc++.h>
using namespace std;
const int N=,M=;
int n,mn=2e9,mx=,lt,rt=2e9,mid,ans=,a[N][N],l[N],b[M],id[M];
int tot,vis[N],cnt,sa[M],ta[M],rk[M],ht[M],wa[M],wb[M],ca[M],cb[M];
int check(int k)
{
      for (int i=;i<=tot;i++)
        {
        if (ht[i]<k)
         {
             memset(vis,,sizeof(vis));
            cnt=;
         }
        if (!vis[id[sa[i]]])vis[id[sa[i]]]=,++cnt;
        if (cnt==n)return ;
       }
      return ;
}
int main()
{
      scanf("%d",&n);
      for (int i=;i<=n;i++)
     {
        scanf("%d",l[i]);
        for (int j=;j<=l[i];j++)
         {
              scanf("%d",&a[i][j]);
              if (j>)mx=max(mx,a[i][j]-a[i][j-]);
         }
        rt=min(rt,l[i]);
       }
      for (int i=;i<=n;i++)
        {
        for (int j=;j<=l[i];j++)
         {
             b[++tot]=a[i][j]-a[i][j-];
            id[tot]=i;
         }
        b[++tot]=++mx;
       }
      for (int i=;i<=tot;i++)mn=min(mn,b[i]);
      for (int i=;i<=tot;i++)b[i]=b[i]-mn+,mx=max(mx,b[i]);
      memset(ca,,sizeof(ca));
      for (int i=;i<=tot;i++)ca[b[i]]++;
      for (int i=;i<=mx;i++)ca[i]+=ca[i-];
      for (int i=tot;i>=;i--)sa[ca[b[i]]--]=i;
      rk[sa[]]=;
      for (int i=;i<=tot;i++)rk[sa[i]]=rk[sa[i-]]+(b[sa[i]]!=b[sa[i-]]);
      for (int k=;rk[sa[tot]]<tot;k<<=)
       {
        memset(ca,,sizeof(ca));
        memset(cb,,sizeof(cb));
        for (int i=;i<=tot;i++)
         {
             ca[wa[i]=rk[i]]++;
            cb[wb[i]=i+k<=tot?rk[i+k]:]++;
         }
        for (int i=;i<=tot;i++)
         {
             ca[i]+=ca[i-];
            cb[i]+=cb[i-];
         }
        for (int i=tot;i;i--)ta[cb[wb[i]]--]=i;
        for (int i=tot;i;i--)sa[ca[wa[ta[i]]]--]=ta[i];
        rk[sa[]]=;
        for (int i=;i<=tot;i++)
         rk[sa[i]]=rk[sa[i-]]+(wa[sa[i]]!=wa[sa[i-]]||wb[sa[i]]!=wb[sa[i-]]);
       }
      for (int i=,j=;i<=tot;i++)
       {
        if (j)j--;
        while (b[i+j]==b[sa[rk[i]-]+j])j++;
        ht[rk[i]]=j;
       }
      while (lt<=rt)
       {
        if (check(mid=(lt+rt)>>))ans=mid+,lt=mid+;
        else rt=mid-;
       }
      printf("%d\n",ans);
}