1、正则表达式写法:

CREATE OR REPLACE FUNCTION Func_checkidcard (p_idcard IN VARCHAR2) RETURN INT
IS
v_regstr VARCHAR2 (2000);
v_sum NUMBER;
v_mod NUMBER;
v_checkcode CHAR (11) := '10X98765432';
v_checkbit CHAR (1);
v_areacode VARCHAR2 (2000) := '11,12,13,14,15,21,22,23,31,32,33,34,35,36,37,41,42,43,44,45,46,50,51,52,53,54,61,62,63,64,65,71,81,82,91,';
BEGIN
CASE LENGTHB (p_idcard)
WHEN 15
THEN -- 15位
IF INSTRB (v_areacode, SUBSTR (p_idcard, 1, 2) || ',') = 0 THEN
RETURN 0;
END IF; IF MOD (TO_NUMBER (SUBSTRB (p_idcard, 7, 2)) + 1900, 400) = 0
OR
(
MOD (TO_NUMBER (SUBSTRB (p_idcard, 7, 2)) + 1900, 100) <> 0
AND
MOD (TO_NUMBER (SUBSTRB (p_idcard, 7, 2)) + 1900, 4) = 0
)
THEN -- 闰年
v_regstr :=
'^[1-9][0-9]{5}[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|[1-2][0-9]))[0-9]{3}$';
ELSE
v_regstr :=
'^[1-9][0-9]{5}[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|1[0-9]|2[0-8]))[0-9]{3}$';
END IF; IF REGEXP_LIKE (p_idcard, v_regstr) THEN
RETURN 1;
ELSE
RETURN 0;
END IF;
WHEN 18
THEN -- 18位
IF INSTRB (v_areacode, SUBSTRB (p_idcard, 1, 2) || ',') = 0 THEN
RETURN 0;
END IF; IF MOD (TO_NUMBER (SUBSTRB (p_idcard, 7, 4)), 400) = 0
OR
(
MOD (TO_NUMBER (SUBSTRB (p_idcard, 7, 4)), 100) <> 0
AND
MOD (TO_NUMBER (SUBSTRB (p_idcard, 7, 4)), 4) = 0
)
THEN -- 闰年
v_regstr :=
'^[1-9][0-9]{5}(19|20)[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|[1-2][0-9]))[0-9]{3}[0-9Xx]$';
ELSE
v_regstr :=
'^[1-9][0-9]{5}(19|20)[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|1[0-9]|2[0-8]))[0-9]{3}[0-9Xx]$';
END IF; IF REGEXP_LIKE (p_idcard, v_regstr) THEN
v_sum :=
( TO_NUMBER (SUBSTRB (p_idcard, 1, 1))
+ TO_NUMBER (SUBSTRB (p_idcard, 11, 1))
)
* 7
+ ( TO_NUMBER (SUBSTRB (p_idcard, 2, 1))
+ TO_NUMBER (SUBSTRB (p_idcard, 12, 1))
)
* 9
+ ( TO_NUMBER (SUBSTRB (p_idcard, 3, 1))
+ TO_NUMBER (SUBSTRB (p_idcard, 13, 1))
)
* 10
+ ( TO_NUMBER (SUBSTRB (p_idcard, 4, 1))
+ TO_NUMBER (SUBSTRB (p_idcard, 14, 1))
)
* 5
+ ( TO_NUMBER (SUBSTRB (p_idcard, 5, 1))
+ TO_NUMBER (SUBSTRB (p_idcard, 15, 1))
)
* 8
+ ( TO_NUMBER (SUBSTRB (p_idcard, 6, 1))
+ TO_NUMBER (SUBSTRB (p_idcard, 16, 1))
)
* 4
+ ( TO_NUMBER (SUBSTRB (p_idcard, 7, 1))
+ TO_NUMBER (SUBSTRB (p_idcard, 17, 1))
)
* 2
+ TO_NUMBER (SUBSTRB (p_idcard, 8, 1)) * 1
+ TO_NUMBER (SUBSTRB (p_idcard, 9, 1)) * 6
+ TO_NUMBER (SUBSTRB (p_idcard, 10, 1)) * 3;
v_mod := MOD (v_sum, 11);
v_checkbit := SUBSTRB (v_checkcode, v_mod + 1, 1); IF v_checkbit = upper(substrb(p_idcard,18,1)) THEN
RETURN 1;
ELSE
RETURN 0;
END IF;
ELSE
RETURN 0;
END IF;
ELSE
RETURN 0; -- 身份证号码位数不对
END CASE;
EXCEPTION
WHEN OTHERS
THEN
RETURN 0;
END fn_checkidcard;
/
Show Err;

2、非正则表达式写法

Create Or Replace Function Func_checkIdcard (p_idcard in varchar2) Return Number
Is
v_sum Number;
v_mod Number;
v_length Number;
v_date Varchar2(10);
v_isDate Boolean;
v_isNumber Boolean;
v_isNumber_17 Boolean;
v_checkbit CHAR (1);
v_checkcode CHAR (11) := '10X98765432';
v_areacode VARCHAR2 (2000) := '11,12,13,14,15,21,22,23,31,32,33,34,35,36,37,41,42,43,44,45,46,50,51,52,53,54,61,62,63,64,65,71,81,82,91,'; --[isNumber]--
Function isNumber (p_string in varchar2) Return Boolean
Is
i number;
k number;
flag boolean;
v_length number;
Begin
/*
算法:
通过ASCII码判断是否数字,介于[48, 57]之间。
select ascii('0'),ascii('1'),ascii('2'),ascii('3'),ascii('4'),ascii('5'),ascii('6'),ascii('7'),ascii('8'),ascii('9') from dual;
*/ flag := True;
select length(p_string) into v_length from dual; for i in 1..v_length loop
k := ascii(substr(p_string,i,1));
if k < 48 or k > 57 then
flag := False;
Exit;
end if;
end loop; Return flag;
End isNumber; --[isDate]--
Function isDate (p_date in varchar2) Return Boolean
Is
v_flag boolean;
v_year number;
v_month number;
v_day number;
v_isLeapYear boolean;
Begin
--[初始化]--
v_flag := True; --[获取信息]--
v_year := to_number(substr(p_date,1,4));
v_month := to_number(substr(p_date,5,2));
v_day := to_number(substr(p_date,7,2)); --[判断是否为闰年]--
if (mod(v_year,400) = 0) Or (mod(v_year,100) <> 0 And mod(v_year,4) = 0) then
v_isLeapYear := True;
else
v_isLeapYear := False;
end if; --[判断月份]--
if v_month < 1 Or v_month > 12 then
v_flag := False;
Return v_flag;
end if; --[判断日期]--
if v_month in (1,3,5,7,8,10,12) and (v_day < 1 or v_day > 31) then
v_flag := False;
end if;
if v_month in (4,6,9,11) and (v_day < 1 or v_day > 30) then
v_flag := False;
end if;
if v_month in (2) then
if (v_isLeapYear) then
--[闰年]--
if (v_day < 1 or v_day > 29) then
v_flag := False;
end if;
else
--[非闰年]--
if (v_day < 1 or v_day > 28) then
v_flag := False;
end if;
end if;
end if; --[返回结果]--
Return v_flag;
End isDate;
Begin
/*
返回值说明:
-1 身份证号码位数不对
-2 身份证号码出生日期超出范围
-3 身份证号码含有非法字符
-4 身份证号码校验码错误
-5 身份证号码地区码非法
1 身份证号码通过校验
*/
--[长度校验]--
if p_idcard is null then
return -1;
end if ;
select lengthb(p_idcard) into v_length from dual;
if v_length not in (15,18) then
return -1;
end if; --[区位码校验]--
if instrb(v_areacode, substr(p_idcard, 1, 2)||',') = 0 then
return -5;
end if; --[格式化校验]--
if v_length = 15 then
v_isNumber := isNumber (p_idcard);
if not (v_isNumber) then
return -3;
end if;
elsif v_length = 18 then
v_isNumber := isNumber (p_idcard);
v_isNumber_17 := isNumber (substr(p_idcard,1,17));
if not ((v_isNumber) or (v_isNumber_17 and upper(substr(p_idcard,18,1)) = 'X')) then
return -3;
end if;
end if; --[出生日期校验]--
if v_length = 15 then
select ''||substr(p_idcard,7,6) into v_date from dual;
elsif v_length = 18 then
select substr(p_idcard,7,8) into v_date from dual;
end if;
v_isDate := isDate (v_date);
if not (v_isDate) then
return -2;
end if; --[校验码校验]--
if v_length = 18 then
v_sum :=
( TO_NUMBER (SUBSTRB (p_idcard, 1, 1))
+ TO_NUMBER (SUBSTRB (p_idcard, 11, 1))
)
* 7
+ ( TO_NUMBER (SUBSTRB (p_idcard, 2, 1))
+ TO_NUMBER (SUBSTRB (p_idcard, 12, 1))
)
* 9
+ ( TO_NUMBER (SUBSTRB (p_idcard, 3, 1))
+ TO_NUMBER (SUBSTRB (p_idcard, 13, 1))
)
* 10
+ ( TO_NUMBER (SUBSTRB (p_idcard, 4, 1))
+ TO_NUMBER (SUBSTRB (p_idcard, 14, 1))
)
* 5
+ ( TO_NUMBER (SUBSTRB (p_idcard, 5, 1))
+ TO_NUMBER (SUBSTRB (p_idcard, 15, 1))
)
* 8
+ ( TO_NUMBER (SUBSTRB (p_idcard, 6, 1))
+ TO_NUMBER (SUBSTRB (p_idcard, 16, 1))
)
* 4
+ ( TO_NUMBER (SUBSTRB (p_idcard, 7, 1))
+ TO_NUMBER (SUBSTRB (p_idcard, 17, 1))
)
* 2
+ TO_NUMBER (SUBSTRB (p_idcard, 8, 1)) * 1
+ TO_NUMBER (SUBSTRB (p_idcard, 9, 1)) * 6
+ TO_NUMBER (SUBSTRB (p_idcard, 10, 1)) * 3;
v_mod := MOD (v_sum, 11);
v_checkbit := SUBSTRB (v_checkcode, v_mod + 1, 1); if v_checkbit = upper(substrb(p_idcard,18,1)) then
return 1;
else
return -4;
end if;
else
return 1;
end if;
End Func_checkIdcard;
/
Show Err;

oracle 身份证校验函数的更多相关文章

  1. Oracle 身份证校验

    SELECT SUBSTR('&AI', 0, 17) || TRANSLATE(DECODE(MOD(SUM(SUBSTR(WI, REGEXP_INSTR(WI, ' ', 1, I) + ...

  2. 完美实现身份证校验 js正则

    注意: 1.只针对18为身份证号码进行校验,现在15位的应该很少了, 2.不区分xX大小写, 3.出生年份1900-2099,每月的天数也进行相关验证(考虑的闰月的情况), 4.校验规则详见,这个写的 ...

  3. Java 常用正则表达式,Java正则表达式,Java身份证校验,最新手机号码正则表达式

    Java 常用正则表达式,Java正则表达式,Java身份证校验,最新手机号码校验正则表达式 ============================== ©Copyright 蕃薯耀 2017年11 ...

  4. Oracle的nvl函数和nvl2函数

    一.基本语法 介绍一下oracle的nvl函数和nvl2函数. nvl函数 nvl函数基本语法为nvl(E1,E2),意思是E1为null就返回E2,不为null就返回E1. nvl2函数 nvl2函 ...

  5. Oracle 中 decode 函数用法

    Oracle 中 decode 函数用法 含义解释:decode(条件,值1,返回值1,值2,返回值2,...值n,返回值n,缺省值) 该函数的含义如下:IF 条件=值1 THEN RETURN(翻译 ...

  6. 重写Oracle的wm_concat函数,自定义分隔符、排序

    oracle中,wm_concat函数是一个聚合函数,和mysql中的group_concat函数类似,不过group_concat函数比较强大,可以定义分隔符和排序,当然所谓强大是相对的,这里假使我 ...

  7. 篇二:JS身份证校验

    身份证校验 function identityCodeValid(code) { var city={11:"北京",12:"天津",13:"河北&q ...

  8. Oracle日期时间函数大全

    ORACLE日期时间函数大全 TO_DATE格式(以时间:2007-11-02 13:45:25为例) Year: yy two digits 两位年 显示值:07 yyy three digits ...

  9. Oracle过程及函数的参数模式,In、out、in out模式

    Oracle过程及函数的参数模式 In.out.in out模式 在Oracle中过程与函数都可以有参数,参数的类型可以指定为in.out.in out三种模式. 三种参数的具体说明,如下图所示: ( ...

随机推荐

  1. delphi 一个自动控制机的硅控板检测程序,用多线程和API,没有用控件,少做改动就能用 用485开发

    一个自动控制机的硅控板检测程序,用多线程和API,没有用控件,少做改动就能用Unit CommThread; Interface Uses  Windows, Classes, SysUtils, G ...

  2. rpm命令

    RPM 安装.卸载.升级.查询和验证. RPM 安装 命令: rpm -i 文件名 如: rpm -i example.rpm 安装 example.rpm 包: rpm -iv example.rp ...

  3. js复选框操作

    $(".checkall").click(function () {                if (this.checked) {                    $ ...

  4. IOS :编译时出现的错误 ,希望可以有所帮助

    1."std::ios_base::Init::~Init()", referenced from 答1: 如果出现这样的编译问题,是需要再加进libstdc++.dylib和li ...

  5. JS-为金额添加千分位逗号分割符

    前言:这个功能在前端页面中使用的还是比较多的,正好我们的项目中也有使用此功能,不过YY同学写的代码不像个方法的样子,一个入口中间又插了几道子,所             以,我写了下面这个方法,经过测 ...

  6. 腾讯云Centos下Nginx反向代理Apache+Tomcat

    1. 安装Apahce, PHP, MySQL以及php连接mysql库的组件#yum -y install httpd php mysql mysql-server php-mysql     // ...

  7. SBCL 从REPL 中提取lisp代码

    1, 在emacs C-x C-W 文件另存为保存所有REPL过程 由于 (load "foo.lisp")时只有定义语句可以正确执行, 执行语句不可正确被 (load " ...

  8. TP-LINK WR841N V8刷OpenWRT

    在某宝上淘了一个TP-LINK WR841N V8,已经硬改为8M闪存和64M内存,还刷好了Uboot.但是卖家刷好的系统是第三方定制过的OpenWRT,集成了很多不需要用到的软件,所以我要刷回官方原 ...

  9. java文件名更改一直是false,看看是否是文件打开没有关

    // 更改文件名称 public static void chenckFileName(String oldFile, String newFileName) { File file = new Fi ...

  10. CSS 定位机制 position

    position属性W3School有详细介绍 1.(position:relative;)相对定位会按照元素的原始位置对该元素进行移动.relative 2.(position:absolute;) ...