projecteuler---->problem=10----Summation of primes
title:
The sum of the primes below 10 is 2 + 3 + 5 + 7 = 17.
Find the sum of all the primes below two million.
翻译:
10下面的质数的和为2 + 3 + 5 + 7 = 17。
请求出200,0000下面全部质数的和。
import math,time
def isOk(a):
for i in range(2,int(math.sqrt(a))+1):
if a%i==0:
return False
return True
s=0
begin=time.time()
for i in range(2,2000000):
if isOk(i):
s += i
print s
end = time.time()
print end-begin
projecteuler---->problem=10----Summation of primes的更多相关文章
- Problem 10: Summation of primes
def primeslist(max): ''' 求max值以内的质数序列 ''' a = [True]*(max+1) a[0],a[1]=False,False for index in rang ...
- Project Euler Problem 10
Summation of primes Problem 10 The sum of the primes below 10 is 2 + 3 + 5 + 7 = 17. Find the sum of ...
- Problem 10
Problem 10 # Problem_10.py """ The sum of the primes below 10 is 2 + 3 + 5 + 7 = 17. ...
- (Problem 47)Distinct primes factors
The first two consecutive numbers to have two distinct prime factors are: 14 = 2 7 15 = 3 5 The fi ...
- (Problem 37)Truncatable primes
The number 3797 has an interesting property. Being prime itself, it is possible to continuously remo ...
- (Problem 35)Circular primes
The number, 197, is called a circular prime because all rotations of the digits: 197, 971, and 719, ...
- uoj problem 10
uoj problem 10 题目大意: 给定任务若干,每个任务在\(t_i\)收到,需要\(s_i\)秒去完成,优先级为\(p_i\) 你采用如下策略: 每一秒开始时,先收到所有在该秒出现的任务,然 ...
- (Problem 10)Summation of primes
The sum of the primes below 10 is 2 + 3 + 5 + 7 = 17. Find the sum of all the primes below two milli ...
- projecteuler Summation of primes
The sum of the primes below 10 is 2 + 3 + 5 + 7 = 17. Find the sum of all the primes below two milli ...
- Summation of primes
是我算法不对,还是笔记本CPU太差? 我优化了两次,还是花了三四个小时来得到结果. 在输出上加1就是最终结果. The sum of the primes below 10 is 2 + 3 + 5 ...
随机推荐
- EOJ Monthly 2018.8 D. Delivery Service-树上差分(边权/边覆盖)(边权转点权)(模板题)
D. Delivery Service 单测试点时限: 2.5 秒 内存限制: 512 MB EOJ Delivery Service Company handles a massive amount ...
- CodeForces 779E Bitwise Formula
位运算,枚举. 按按分开计算,枚举$?$是$0$还是$1$,分别计算出$sum$,然后就可以知道该位需要填$1$还是$0$了. #include<map> #include<set& ...
- CodeForces 740A Alyona and copybooks
完全背包. 直接做个背包容量为$100000$的完全背包,这样就可以避免繁琐的分类讨论了. #pragma comment(linker, "/STACK:1024000000,102400 ...
- Bzoj4753/洛谷P4432 [JSOI2016]最佳团体(0/1分数规划+树形DP)
题面 Bzoj 洛谷 题解 这种求比值最大就是\(0/1\)分数规划的一般模型. 这里用二分法来求解最大比值,接着考虑如何\(check\),这里很明显可以想到用树形背包\(check\),但是时间复 ...
- JZYZOJ 1388 旅游 状压dp
http://172.20.6.3/Problem_Show.asp?id=1388 求拓扑排序方案数 状压dp,最开始以为是拓扑排序加数论或者搜索,没想到是状压dp,突然气死.jpg: 完全没有 ...
- Educational Codeforces Round 41 (Rated for Div. 2) ABCDEF
最近打的比较少...就只有这么点题解了. A. Tetris time limit per test 1 second memory limit per test 256 megabytes inpu ...
- BZOJ 2654 tree(二分答案+并查集)
[题目链接] http://www.lydsy.com/JudgeOnline/problem.php?id=2654 [题目大意] 给你一个无向带权连通图,每条边是黑色或白色. 让你求一棵最小权的恰 ...
- BZOJ 1827 [Usaco2010 Mar]gather 奶牛大集会(树形DP)
[题目链接] http://www.lydsy.com/JudgeOnline/problem.php?id=1827 [题目大意] 给出一棵有点权和边权的树, 请确定一个点,使得每个点到这个点的距离 ...
- (1)CorePlot配置
先来看一下官方的说法,贴内容(https://code.google.com/p/core-plot/wiki/UsingCorePlotInApplications) Dependent Proje ...
- Idea集成svn
Idea集成svn 既然要使用svn,首先需要下载一个 svn的客户端,到这里下载对应的安装程序:http://subversion.apache.org/packages.html#windows ...