Poj 1887 Testing the CATCHER(LIS)
一、Description
is supposed to be a remarkable defensive missile. It can move forward, laterally, and downward at very fast speeds, and it can intercept an offensive missile without being damaged. But it does have one major flaw. Although it can be fired to reach any initial
elevation, it has no power to move higher than the last missile that it has intercepted.
The tests which the contractor completed were computer simulations of battlefield and hostile attack conditions. Since they were only preliminary, the simulations tested only the CATCHER's vertical movement capability. In each simulation, the CATCHER was fired
at a sequence of offensive missiles which were incoming at fixed time intervals. The only information available to the CATCHER for each incoming missile was its height at the point it could be intercepted and where it appeared in the sequence of missiles.
Each incoming missile for a test run is represented in the sequence only once.
The result of each test is reported as the sequence of incoming missiles and the total number of those missiles that are intercepted by the CATCHER in that test.
The General Accounting Office wants to be sure that the simulation test results submitted by the military contractor are attainable, given the constraints of the CATCHER. You must write a program that takes input data representing the pattern of incoming missiles
for several different tests and outputs the maximum numbers of missiles that the CATCHER can intercept for those tests. For any incoming missile in a test, the CATCHER is able to intercept it if and only if it satisfies one of these two conditions:
The incoming missile is the first missile to be intercepted in this test.
-or-
The missile was fired after the last missile that was intercepted and it is not higher than the last missile which was intercepted.
Input
sequence is -1, which signifies the end of data for that particular test and is not considered to represent a missile height. The end of data for the entire input is the number -1 as the first value in a test; it is not considered to be a separate test.
Output
Output for each test consists of a test number (Test #1, Test #2, etc.) and the maximum number of incoming missiles that the CATCHER could possibly intercept for the test. That maximum number appears after an identifying message. There must be at least one
blank line between output for successive data sets.
Note: The number of missiles for any given test is not limited. If your solution is based on an inefficient algorithm, it may not execute in the allotted time.
二、题解
这题和3903一样属于LIS问题,在之前有关于LIS的分析最长递增子序列(LIS)。这次我们不采用DP+二分查找的方法(虽然更好),把之前谈到的纯DP实现一下。注意这里求的是最长非递增序列,是LIS的反问题,只要从数组的最后面开始就行了。
三、java代码
import java.util.Scanner;
public class Main{
static int[] a =new int[10000];
static int[] maxlen=new int[10000];
public static void main(String[] args){
Scanner cin = new Scanner(System.in);
int n,i,j,len,max,ans,cas=0;
while(cin.hasNext()){
n=cin.nextInt();
if(n==-1)
break;
a[0]=n;
for(i=1;;i++){
n=cin.nextInt();
if(n==-1)
break;
else
a[i]=n;
}
len=i-1;
maxlen[len]=1;
for(i=len-1;i>=0;i--){
max=0;
for(j=i+1;j<=len;j++){
if(maxlen[j]>max&&a[j]<a[i])
max=maxlen[j];
}
maxlen[i]=max+1;
}
ans=0;
for(i=0;i<=len;i++){
if(maxlen[i]>ans)
ans=maxlen[i];
}
System.out.println("Test #"+ ++cas +":");
System.out.println(" maximum possible interceptions: "+ans);
System.out.println();
}
}
}
版权声明:本文为博主原创文章,未经博主允许不得转载。
Poj 1887 Testing the CATCHER(LIS)的更多相关文章
- POJ 1887 Testing the CATCHER(LIS的反面 最大递减子序列)
Language: Default Testing the CATCHER Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 1 ...
- POJ 1887 Testing the CATCHER
Testing the CATCHER Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 13396 Accepted: 4 ...
- poj 1887 Testing the CATCHER_最长上升子序列
题意:题目太长没看,直接看输入输出猜出是最长下降子序列 用了以前的代码直接a了,做法类似贪心,把最小的顺序数存在数组里面,每次二分更新数组得出最长上升子序列 #include<iostream& ...
- POJ 1887 Testingthe CATCHER (LIS:最长下降子序列)
POJ 1887Testingthe CATCHER (LIS:最长下降子序列) http://poj.org/problem?id=3903 题意: 给你一个长度为n (n<=200000) ...
- POJ 1887:Testing the CATCHER 求递减序列的最大值
Testing the CATCHER Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 16131 Accepted: 5 ...
- poj1887 Testing the CATCHER
Testing the CATCHER Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 13968 Accepted: 5 ...
- POJ-1887 Testing the CATCHER(dp,最长下降子序列)
Testing the CATCHER Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 16515 Accepted: 6082 ...
- POJ 1631 Bridging signals(LIS O(nlogn)算法)
Bridging signals Description 'Oh no, they've done it again', cries the chief designer at the Waferla ...
- POJ - 3903 Stock Exchange(LIS最长上升子序列问题)
E - LIS Time Limit:1000MS Memory Limit:65536KB 64bit IO Format:%I64d & %I64u Descripti ...
随机推荐
- 7.FactoryBean 和BeanFactory去区别
FactoryBean源码: /* * Copyright 2002-2012 the original author or authors. * * Licensed under the Apach ...
- bug_1——oracle listagg():列转行
select listagg(字段名 ,',') within group (order by 字段名) from表 where 条件 listagg():列转行 WM_CONCAT():和并列 ...
- activiti踩坑
最近在学习activiti,偶然间遇到一个错误:加载引擎的时候报错,显示空指针错误,跟代码发现初始化配置文件返回为null.几经排查,可能是因为我发布流程后又清空了数据库数据导致的.然后我把表全部删除 ...
- Android Studio实现代码混淆
1,在build.grandle添加,其中规则写在proguard-rules.pro中,也可以自定义一个文件,将其代替,比如eclipse常用的 proguard-project.txt: bui ...
- interface -- 接口类
<?php /** *为了声明接口,需要使用关键字interface *interface IExampleInterface {} *说明(大多数开发人员选择在节后名称前加上大写字母I作为前缀 ...
- [原创]java WEB学习笔记18:java EE 中的MVC 设计模式(理论)
本博客为原创:综合 尚硅谷(http://www.atguigu.com)的系统教程(深表感谢)和 网络上的现有资源(博客,文档,图书等),资源的出处我会标明 本博客的目的:①总结自己的学习过程,相当 ...
- BestCoder Round #4 之 Miaomiao's Geometry(2014/8/10)
最后收到邮件说注意小数的问题!此代码并没有过所有数据,请读者参考算法, 自己再去修改一下吧!注意小数问题! Miaomiao's Geometry Time Limit: 2000/1000 MS ( ...
- keeplive使用
一.简介 Keepalived是一个免费开源的,用C编写的类似于layer3, 4 & 7交换机制软件,具备我们平时说的第3层.第4层和第7层交换机的功能.主要提供loadbalancing( ...
- Spring Cloud之网关搭建
统一由网关进行拦截判断 要不放到每个服务里面就很不合适了 冗余 主要的: <dependency> <groupId>org.springframework.cloud< ...
- codevs1218 疫情控制
疫情控制(blockade.cpp/c/pas)[问题描述]H 国有 n 个城市,这 n 个城市用 n-1 条双向道路相互连通构成一棵树,1 号城市是首都,也是树中的根节点.H 国的首都爆发了一种危害 ...