实体类转xml

看项目中需要实体类转xml，大家是拼接的。感觉可以利用反射实现。于是写了下

代码如下

package com.kevin.util;

import org.springframework.util.ObjectUtils;

import java.lang.reflect.Field;
import java.lang.reflect.ParameterizedType;
import java.lang.reflect.Type;
import java.util.List;

/**
 * @description: 实体类转xml
 * @author: kevin
 * @create: 2020-08-17 08:50
 */

public class EntityToXml {

    public static String entityToXml(Object obj) {
        StringBuilder xml = new StringBuilder();
        xml.append("\"<?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?><root>");
        try {
            Class<?> aClass = obj.getClass();
            Field[] fields = aClass.getDeclaredFields();

            for (Field field : fields) {
                field.setAccessible(true);
                String name = field.getName();
                name = name.substring(0, 1).toUpperCase() + name.substring(1);
                Object o = ObjectUtils.isEmpty(field.get(obj)) ? "" : field.get(obj);
                Class<?> curFieldType = field.getType();
                xml.append("<").append(name).append(">");
                if (curFieldType.equals(List.class)) {
                    getListXMl(xml, field, (List) o);
                } else {
                    xml.append(o);
                }
                xml.append("</").append(name).append(">");

            }
        } catch (IllegalAccessException e) {
            //todo 这里记录异常
        }
        xml.append("</root>");
        return xml.toString();
    }

    private static StringBuilder getListXMl(StringBuilder xml, Field field, List o) throws IllegalAccessException {
        Type genericType = field.getGenericType();
        if (null == genericType) {
            return xml;
        }
        if (genericType instanceof ParameterizedType) {
            ParameterizedType pt = (ParameterizedType) genericType;
            // 得到泛型里的class类型对象
            Class<?> actualTypeArgument = (Class<?>) pt.getActualTypeArguments()[0];
            List<Object> lists = o;
            Field[] declaredFields = actualTypeArgument.getDeclaredFields();

            for (Object list : lists) {
                xml.append("<row>");
                for (Field declaredField : declaredFields) {
                    declaredField.setAccessible(true);
                    String rowName = declaredField.getName();
                    rowName = rowName.substring(0, 1).toUpperCase() + rowName.substring(1);
                    Object rowValue = ObjectUtils.isEmpty(declaredField.get(list)) ? "" : declaredField.get(list);
                    xml.append("<").append(rowName).append(">").append(rowValue).append("</").append(rowName).append(">");
                }
                xml.append("</row>");
            }
        }
        return xml;
    }

}

测试

    @Test
    public void entityToXml() {

        QueryDrugListVO queryDrugListVO = new QueryDrugListVO();
        queryDrugListVO.setBlDrugName("a");
        queryDrugListVO.setId(1);
        QueryDrugListReq req = new QueryDrugListReq();
        req.setBigKindName("大佬");
        QueryDrugListReq req1 = new QueryDrugListReq();
        req1.setBigKindName("大佬1");
        List<QueryDrugListReq> reqs = new ArrayList<>();
        reqs.add(req);
        reqs.add(req1);
        queryDrugListVO.setOrders(reqs);
        String s = EntityToXml.entityToXml(queryDrugListVO);
        System.out.println(s);

    }

输出结果：
"<?xml version=\"1.0\" encoding=\"UTF-8\"?><root><Id>1</Id><BlDrugName>a</BlDrugName><SpecValue></SpecValue><MinPackageUnit></MinPackageUnit><Orders><row><FirstKindCode></FirstKindCode><BigKindName>大佬</BigKindName><BigKindState></BigKindState><PageNumber></PageNumber><PageSize></PageSize></row><row><FirstKindCode></FirstKindCode><BigKindName>大佬1</BigKindName><BigKindState></BigKindState><PageNumber></PageNumber><PageSize></PageSize></row></Orders></root>