The 5th Zhejiang Provincial Collegiate Programming Contest---ProblemG：Give Me the Number

http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=2971

题意：将输入的英文数字表达转化为阿拉伯数字。

 #include<bits/stdc++.h>
 using namespace std;

 char aa[][]= {"zero", "one","two", "three", "four", "five", "six",  "seven", "eight", "nine",
                   "ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen","nineteen",
                   "twenty","thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety"
                  };
 int bb[]= {,,,,,,,,,,,,,,,,,,,,,,,,,,,};
 char cc[][];
 int main() {
     int t;
     char s[];
     scanf("%d",&t);
     getchar();//先吃掉t后面的回车
     while(t--) {
         memset(s,,sizeof(s));
         memset(cc,,sizeof(cc));
         gets(s);
         int num=,k=;
         int len=strlen(s);
         for(int i=; i<len; i++) {
             if(i>=&&s[i]==' '&&s[i-]!=' ') {
                 num++;//在’ ‘前算上一个字符串
                 k=;
                 continue;
             }
             if(s[i]!=' ')
                 cc[num][k++]=s[i];//装入一个字符串
         }
         int sum1=,sum2=;
         int j;
　　　　　　　　//有前至后读入字符串
         for(int i=; i<=num; i++) {
             for(j=; j<; j++) {
                 if(strcmp(cc[i],aa[j])==) {
                     sum1+=bb[j];
                     break;
                 }
             }
             if(j=) {
                 if(strcmp(cc[i],"and")==)
                     continue;
                 if(strcmp(cc[i],"thousand")==) {
                     sum1*=;
                     sum2+=sum1;
                     sum1=;
                 } else if(strcmp(cc[i],"hundred")==)
                     sum1*=;
                 else if(strcmp(cc[i],"million")==) {
                     sum1*=;
                     sum2+=sum1;
                     sum1=;
                 }
             }
         }
         printf("%d\n",sum2+sum1);
     }
     return ;
 }//善于使用strcmp函数，其实想到就很简单了