Java Lambda map返回部分属性

通过map，返回部分属性。

MyUser，作为源数据

MyUserS，作为返回的新数据。

@Test
    public void Test1()
    {
        List<MyUser> ulist=new ArrayList<>();
        MyUser u1=new MyUser();
        u1.setName("1");u1.setAge(1);u1.setHobby("swimming");
        MyUser u2=new MyUser();
        u2.setName("2");u2.setAge(2);u2.setHobby("sleeping");
        MyUser u3=new MyUser();
        u3.setName("3");u3.setAge(3);u3.setHobby("playing");
        ulist.add(u1);ulist.add(u2);ulist.add(u3);

        List<MyUserS> usList=ulist.stream().map(x->{return new MyUserS(x.getName(),x.getAge());}).collect(Collectors.toList());

    }

    @Data
    public class MyUser
    {
        public String name;
        public Integer age;
        public String hobby;
    }

    @Data
    public class MyUserS
    {
        public MyUserS(String name,Integer age)
        {
            this.name=name;
            this.age=age;
        }
        public String name;
        public Integer age;
    }