Beat the Spread![HDU1194]
Beat the Spread!
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 3482 Accepted Submission(s): 1821
Problem Description
Superbowl Sunday is nearly here. In order to pass the time waiting for the half-time commercials and wardrobe malfunctions, the local hackers have organized a betting pool on the game. Members place their bets on the sum of the two final scores, or on the absolute difference between the two scores.
Given the winning numbers for each type of bet, can you deduce the final scores?
Input
The first line of input contains n, the number of test cases. n lines follow, each representing a test case. Each test case gives s and d, non-negative integers representing the sum and (absolute) difference between the two final scores.
Output
For each test case, output a line giving the two final scores, largest first. If there are no such scores, output a line containing "impossible". Recall that football scores are always non-negative integers.
Sample Input
2
40 20
20 40
Sample Output
30 10
impossible
Source
University of Waterloo Local Contest 2005.02.05
Recommend
Ignatius.L
#include<stdio.h>
int main()
{
int T;
scanf("%d",&T);
while (T--)
{
int u,v;
scanf("%d%d",&u,&v);
if (u<v || (u+v)&1) printf("impossible\n");
else printf("%d %d\n",(u+v)/2,(u-v)/2);
}
return 0;
}
Beat the Spread![HDU1194]的更多相关文章
- ZOJ2388 Beat the Spread! 2017-04-16 19:18 91人阅读 评论(0) 收藏
Beat the Spread! Time Limit: 2 Seconds Memory Limit: 65536 KB Superbowl Sunday is nearly here. ...
- zoj 2388 Beat the Spread!
Beat the Spread! Time Limit: 2 Seconds Memory Limit: 65536 KB Superbowl Sunday is nearly here. ...
- HDOJ 1194 Beat the Spread!(简单题)
Problem Description Superbowl Sunday is nearly here. In order to pass the time waiting for the half- ...
- HDU 1194 - Beat the Spread!
给两数之和和两数之差,求两数,两数还必须同奇偶 #include <iostream> using namespace std; int main() { int a,b,t; cin&g ...
- UVa 10812 - Beat the Spread!
题目大意:知道一场橄榄球比赛比分的和以及差的绝对值,算出这两个数.注意判断结果的可能性(比分为非负数). #include <cstdio> int main() { #ifdef LOC ...
- HDU1194_Beat the Spread!
Beat the Spread! Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) ...
- POJ 题目分类(转载)
Log 2016-3-21 网上找的POJ分类,来源已经不清楚了.百度能百度到一大把.贴一份在博客上,鞭策自己刷题,不能偷懒!! 初期: 一.基本算法: (1)枚举. (poj1753,poj2965 ...
- HDU——PKU题目分类
HDU 模拟题, 枚举1002 1004 1013 1015 1017 1020 1022 1029 1031 1033 1034 1035 1036 1037 1039 1042 1047 1048 ...
- (转)POJ题目分类
初期:一.基本算法: (1)枚举. (poj1753,poj2965) (2)贪心(poj1328,poj2109,poj2586) (3)递归和分治法. (4)递推. ...
随机推荐
- ubuntu 快速安装jre
sudo add-apt-repository ppa:webupd8team/java sudo apt-get update sudo apt-get install oracle-java7-i ...
- DICOM:DICOM3.0网络通信协议(续)
转载:http://blog.csdn.net/zssureqh/article/details/44278693 题记: 近一年来一直坚持周末写博客,整理工作和闲暇之余的点点滴滴.对于新知识点.新技 ...
- 配置oss bucket cors
到bucket中属性中选择跨越设置,点击添加规则会看到以下界面: 对应的输入如上即可.
- ZOJ3741 状压DP Eternal Reality
E - Eternal Reality Time Limit:2000MS Memory Limit:65536KB 64bit IO Format:%lld & %llu S ...
- poj2240最短路 floyd
Arbitrage Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 17360 Accepted: 7308 Descri ...
- Python: 什么是*args和**kwargs
转自: http://blog.sina.com.cn/s/blog_65a8ab5d0101fglm.html http://blog.csdn.net/chenjinyu_tang/article ...
- Maximum Gap
Given an unsorted array, find the maximum difference between the successive elements in its sorted f ...
- wsp反编译
最后出于好奇,我把wsp文件解压缩,看看里面是什么(如果您的机器上的压缩软件不能直接解压,可尝试修改后缀名为cab.).我看到的首先是一个清单文件(manifest.xml),一个DLL文件(Shar ...
- windows下安装coreseek/sphinx
2013年12月8日 17:26:26 注意的地方: 1.配置文件的 数据源, 索引, 服务 这3处配置的路径要写成windows识别的路径,最好是绝对路径 2.安装windows服务的时候,可以不带 ...
- Sass 中的 @ 规则
一. @import Sass 扩展了 CSS 的 @import 规则,让它能够引入 SCSS 和 Sass 文件. 所有引入的 SCSS 和 Sass 文件都会被合并并输出一个单一的 CSS 文件 ...