Average Cost (AVCO) Method
Average cost method (AVCO) calculates the cost of ending inventory and cost of goods sold for a period on the basis of weighted average cost per unit of inventory. Weighted average cost per unit is calculated using the following formula:
| Weighted Average | = | Total Cost of Inventory |
| Unit Cost | Total Units in Inventory |
Like FIFO and LIFO methods, AVCO is also applied differently in periodic inventory system and perpetual inventory system. In periodic inventory system, weighted average cost per unit is calculated for the entire class of inventory. It is then multiplied with number of units sold and number of units in ending inventory to arrive at cost of goods sold and value of ending inventory respectively. In perpetual inventory system, we have to calculate the weighted average cost per unit before each sale transaction.
The calculation of inventory value under average cost method is explained with the help of the following example:
Example
Apply AVCO method of inventory valuation on the following information, first in periodic inventory system and then in perpetual inventory system to determine the value of inventory on hand on Mar 31 and cost of goods sold during March.
| Mar 1 | Beginning Inventory | 60 units @ $15.00 per unit |
| 5 | Purchase | 140 units @ $15.50 per unit |
| 14 | Sale | 190 units @ $19.00 per unit |
| 27 | Purchase | 70 units @ $16.00 per unit |
| 29 | Sale | 30 units @ $19.50 per unit |
Solution
AVCO Periodic
| Units Available for Sale | = 60 + 140 + 70 | = 270 | |
| Units Sold | = 190 + 30 | = 220 | |
| Units in Ending Inventory | = 270 − 220 | = 50 | |
| Weighted Average Unit Cost | Units | Unit Cost | Total |
| Mar 1 Inventory | 60 | $15.00 | $900 |
| Mar 5 Purchase | 140 | $15.50 | $2,170 |
| 27 Purchase | 70 | $16.00 | $1,120 |
| 270 | * $15.52 | $4,190 | |
| * $4,190 ÷ 270 | |||
| Cost of Goods Sold | 220 | $15.52 | $3,414 |
| Ending Inventory | 50 | $15.52 | $776 |
AVCO Perpetual
| Date | Purchases | Sales | Balance | ||||||
| Units | Unit Cost | Total | Units | Unit Cost | Total | Units | Unit Cost | Total | |
| Mar 1 | 60 | $15.00 | $900 | ||||||
| 5 | 140 | $15.50 | $2,170 | 60 | $15.00 | $900 | |||
| 140 | $15.50 | $2,170 | |||||||
| 200 | $15.35 | $3,070 | |||||||
| 14 | 190 | $15.35 | $2,916 | 10 | $15.35 | $154 | |||
| 27 | 70 | $16.00 | $1,190 | 10 | $15.35 | $154 | |||
| 70 | $16.00 | $1,120 | |||||||
| 80 | $15.92 | $1,274 | |||||||
| 29 | 30 | $15.92 | $478 | 50 | $15.92 | $796 | |||
| 31 | 50 | $15.92 | $796 | ||||||
Average Cost (AVCO) Method的更多相关文章
- 论文解析 "A Non-Local Cost Aggregation Method for Stereo Matching"
传统的使用窗口的方法缺陷主要在 1.窗口外的像素不能参与匹配判断. 2.在低纹理区域很容易产生错误匹配 论文的主要贡献在代价聚类上(左右图像带匹配点/区域的匹配代价计算),目标是图像内所有点都对该点传 ...
- 基于MST的立体匹配及相关改进(A Non-Local Cost Aggregation Method for Stereo Matching)
怀着很纠结的心情来总结这篇论文,这主要是因为作者提虽然供了源代码,但是我并没有仔细去深究他的code,只是把他的算法加进了自己的项目.希望以后有时间能把MST这一结构自己编程实现!! 论文题目是基于非 ...
- Oracle EBS-SQL (CST-1):检查BOM历史成本查询(Average Cost).sql
select msi1.segment1 父件编码, msi1.description 父件描述, msi1.primary_u ...
- 泡泡一分钟: A Linear Least Square Initialization Method for 3D Pose Graph Optimization Problem
张宁 A Linear Least Square Initialization Method for 3D Pose Graph Optimization Problem "链接:https ...
- Odoo13 新变化:存货核算
Odoo13将于2019年10月发布,本次发布也包含了大量的改进,例如,对存货核算的重构. 去掉了 产品历史价格product.price.history ,增加了 stock valuation l ...
- Adding New Functions to MySQL(User-Defined Function Interface UDF、Native Function)
catalog . How to Add New Functions to MySQL . Features of the User-Defined Function Interface . User ...
- UVA 1456 六 Cellular Network
Cellular Network Time Limit:3000MS Memory Limit:0KB 64bit IO Format:%lld & %llu Submit S ...
- 大规模视觉识别挑战赛ILSVRC2015各团队结果和方法 Large Scale Visual Recognition Challenge 2015
Large Scale Visual Recognition Challenge 2015 (ILSVRC2015) Legend: Yellow background = winner in thi ...
- R语言-聚类与分类
一.聚类: 一般步骤: 1.选择合适的变量 2.缩放数据 3.寻找异常点 4.计算距离 5.选择聚类算法 6.采用一种或多种聚类方法 7.确定类的数目 8.获得最终聚类的解决方案 9.结果可视化 10 ...
随机推荐
- BZOJ4399 : 魔法少女LJJ
将所有权值离散化,建立权值线段树,维护区间内数字个数以及对数的和,用于比较乘积大小. 对于每个连通块维护一棵权值线段树,合并时用线段树合并. 对于操作3和4,暴力删除所有不合法节点,然后一并修改后插入 ...
- 【Vijos】1218 数字游戏
题目链接:https://vijos.org/p/1218 算法:环形DP+划分型DP 环形DP的思路很简单,将1~n中每一个节点当成起点进行划分型DP即可,关于划分型DP前面论文有介绍~查找tag把 ...
- BZOJ1196: [HNOI2006]公路修建问题
Description OI island是一个非常漂亮的岛屿,自开发以来,到这儿来旅游的人很多.然而,由于该岛屿刚刚开发不久,所以那里的交通情况还是很糟糕.所以,OIER Association组织 ...
- UiAutomator 测试工程开发小结
一. 关于bundle无法导入中文参数 答: 将文件改为UTF-8格式 二. 关于对无法抓取的控件进行快速输入问题 答: 主要通过pressKeyCode方法,首先将光标锁定在 ...
- WebConfig配置文件详解(转载自逆心的博客)
<?xml version="1.0"?> <!--注意: 除了手动编辑此文件以外,您还可以使用 Web 管理工具来配置应用程序的设置.可以使用 Visual S ...
- ASP.NET RepeatLayout 属性
定义和用法 RepeatLayout 属性用于设置或获取如何显示在 CheckBoxList 中的项目. 语法 <asp:CheckBoxList RepeatLayout="mode ...
- PHP统计字符串里单词查询关键字
<?function full_count_words($str) { //返回完整数组,包含字符串里每个单词 $words = str_word_count($str,1); ...
- Scrum会议10(Beta版本) 补交
组名:天天向上 组长:王森 组员:张政.张金生.林莉.胡丽娜 代码地址:HTTPS:https://git.coding.net/jx8zjs/llk.git SSH:git@git.coding.n ...
- NBOJv2 1022 短信篮球(种类并查集)
Problem 1022: 短信篮球 Time Limits: 1000 MS Memory Limits: 65536 KB 64-bit interger IO format: %lld ...
- c#String的不变特性,可读但不可写性
谈到字符串,大家自然觉得简单,但是总是有一些小的问题隐约出现,下面我就系统的说一下字符串的问题,有说不到日后再予补充. 1,首先String是一个类,string只是String类的一个别名,别名的意 ...