Advanced Data Structures in competitive programming
1.bit
#define isOn(S, j) (S & (1 << j))
#define setBit(S, j) (S |= (1 << j))
#define clearBit(S, j) (S &= ~(1 << j))
#define toggleBit(S, j) (S ^= (1 << j))
#define lowBit(S) (S & (-S))
#define setAll(S, n) (S = (1 << n) - 1)
#define modulo(S, N) ((S) & (N - 1)) // returns S % N, where N is a power of 2
#define isPowerOfTwo(S) (!(S & (S - 1)))
#define nearestPowerOfTwo(S) ((int)pow(2.0, (int)((log((double)S) / log(2.0)) + 0.5)))
#define turnOffLastBit(S) ((S) & (S - 1))
#define turnOnLastZero(S) ((S) | (S + 1))
#define turnOffLastConsecutiveBits(S) ((S) & (S + 1))
#define turnOnLastConsecutiveZeroes(S) ((S) | (S - 1))
2.UF
#include<iostream>
#include<vector>
#define FOR(i,a,b) for(int (i) = (a); (i) < (b); (i)++)
using namespace std;
typedef vector<int> vi;
vi p,rank;
void build(int N){
p.assign(N,0);//import
FOR(i,0,N+1) p[i] = i;
rank.assign(N,0);
}
void link(int i,int j){
if(p[i]==p[j]) return ;
if(rank[i] < rank[j]){
p[i] = j;
}
else{
p[j] = i;
if(rank[i] == rank[j])
rank[i]++;
}
}
int find(int i){
return p[i] == i ? i : find(p[i]);
}
bool same(int i,int j){
return find(i) == find(j);
}
int main(){
build(5);
link(2,3);
cout << p[2] << " " << p[3] << endl;
cout << same(2,3) << endl;
cout << find(2) << " " << find(3) << endl;
return 0;
}
3.ST
#include<iostream>
#include<vector>
#define FOR(i,a,b) for(int (i) = (a); (i) < (b); (i)++)
#define lc(p) (p)<<1
#define rc(p) ((p)<<1)+1
using namespace std;
typedef vector<int> vi;
vi st,a;
int n;
void initST(vi &b){
a = b; n = b.size();
st.assign(4*n,0);
}
int build(int p,int L,int R){//1,0,n-1
if(L == R) return st[p] = L; //base1
else{
int v1 = build(lc(p),L,(L+R)/2);
int v2 = build(rc(p),(L+R)/2+1,R);
return st[p] = v1 < v2 ? v1:v2; //base2,/********NOTE***/
}
}
int rmq(int p,int L,int R,int i,int j){
if(L > j || R < i) return -1;
if(L >= i && R <= j) return st[p];//trivial condition
//
int p1 = rmq(lc(p),L,(L+R)/2,i,j);
int p2 = rmq(rc(p),(L+R)/2+1,R,i,j);
if(p1 == -1) return p2;
if(p2 == -1) return p1;
return a[p1] < a[p2] ? p1 : p2;
}
int rmq(int i,int j){
return rmq(1,0,n-1,i,j);
}
int main(){
int arr[] = {0,1,2,3,4,5,6,7,8,9}; vi b(&arr[0],&arr[9]);
initST(b);
//a.assign(10,0); FOR(i,0,10) a[i] = i; st.assign(4*10,0); n = 10;//init
build(1,0,10-1);
cout << st[1] << " " << st[3] << endl;
cout << rmq(0,3) << " " << rmq(1,3) << " " << rmq(3,5) << endl;
return 0;
}
Trie
struct trie{
int id;
trie *next[10];//仅用于存储数字,自行扩展
Node(){
id = -1;
for(i,0,10){
next[i] = NULL;
}
}
};
trie *root = new trie();
void add(char *str,int id){
int len = strlen(str);
trie *u = root;
f(i,0,len){
int v = str[i]-'0';
if(!u->next[v])
u->next[v] = new trie();
u = u->next[v];
if(u->id == -1) //NOTE:首先出现者占有ID
u->id = id;
}
}
int query(char *str){
trie *u = root;
int len = strlen(str);
f(i,0,len){
u = u->next[str[i]-'0'];
if(!u) return -1;
}
return u->id;
}
Fenwick Tree
int v[32003]; //N
int lowbit(int a){
return a&(-a);
}
void update(int r){
while(r<=32000){
v[r]++;
r+=lowbit(r);
}
}
int sum(int r){
int k = 0;
while(r>0){
k+=v[r];
r-=lowbit(r);
}
k+=v[r];//
return k;
}
#include<iostream>
#include<algorithm>
#include<cstdio>
#include<cstring>
#include<vector>
#define lowbit(b) (b)&(-b)
using namespace std;
vector<int> ft;
int n;
void init(int n){
ft.assign(n+1,0);
}
int rsq(int b){
int sum = 0;
while(b){
sum+=ft[b];
b-=lowbit(b);
}
return sum;
}
int rsq(int a,int b){
if(a-1) return rsq(b)-rsq(a-1);
return rsq(b);
}
void update(int k,int v){
while(k<ft.size()){
ft[k]+=v;
k+=lowbit(k);
}
}
int main(){
int f[] = {2,4,5,5,6,6,6,7,7,8,9};
n = 10;//0-based
init(n);
for(int i = 0; i < 11; i++)
update(f[i],1);
cout << rsq(1,1) << endl;//ft[1]
cout << rsq(1,2) << endl;//ft[2]
cout << rsq(1,6) << endl;//ft[6]+ft[4] = 5+2
cout << rsq(1,10) << endl;//ft[10]+ft[8] = 1+10
cout << rsq(3,6) << endl;//rsq(1,6)-rsq(1,2)
update(5,2);
cout << rsq(1,10) << endl;
return 0;
}
FT(2D)
POJ1195
#include<iostream>
#include<algorithm>
#include<cstdio>
#include<vector>
#include<cstring>
#define lowbit(b) (b)&(-b)
using namespace std;
int ft[1100][1100];
int n,x,y,m,l,b,r,t;
void init(){
memset(ft,0,sizeof ft);
}
int rsq(int x,int y){
int sum = 0;
for(int i = x; i; i -= lowbit(i)){
for(int j = y; j; j -= lowbit(j)){
sum+=ft[i][j];
}
}
return sum;
}
int rsq(int l,int b,int r,int t){
return rsq(r,t)-rsq(r,b-1)-rsq(l-1,t)+rsq(l-1,b-1);
}
void update(int x,int y,int v){
for(int i = x; i <= n; i += lowbit(i)){
for(int j = y; j <= n; j += lowbit(j)){
ft[i][j] += v;
}
}
}
int main(){
int op;
while(scanf("%d",&op)!=EOF){
if(op==3) continue;
else if(op==0){
scanf("%d",&n);
init();
}
else if(op==1){
scanf("%d%d%d",&x,&y,&m); x++;y++;
update(x,y,m);
}
else{
scanf("%d%d%d%d",&l,&b,&r,&t); l++;b++;r++;t++;
printf("%d\n",rsq(l,b,r,t));
}
}
return 0;
}
More
https://github.com/Dev-XYS/Algorithms
Advanced Data Structures in competitive programming的更多相关文章
- Advanced Data Structures
Advanced Data Structures Advanced Data Structures
- Persistent Data Structures
原文链接:http://www.codeproject.com/Articles/9680/Persistent-Data-Structures Introduction When you hear ...
- CSIS 1119B/C Introduction to Data Structures and Algorithms
CSIS 1119B/C Introduction to Data Structures and Algorithms Programming Assignment TwoDue Date: 18 A ...
- [Data Structures and Algorithms - 1] Introduction & Mathematics
References: 1. Stanford University CS97SI by Jaehyun Park 2. Introduction to Algorithms 3. Kuangbin' ...
- The Swiss Army Knife of Data Structures … in C#
"I worked up a full implementation as well but I decided that it was too complicated to post in ...
- Python Tutorial 学习(五)--Data Structures
5. Data Structures 这一章来说说Python的数据结构 5.1. More on Lists 之前的文字里面简单的介绍了一些基本的东西,其中就涉及到了list的一点点的使用.当然,它 ...
- 学习笔记之Problem Solving with Algorithms and Data Structures using Python
Problem Solving with Algorithms and Data Structures using Python — Problem Solving with Algorithms a ...
- [Javascript] Avoiding Mutations in JavaScript with Immutable Data Structures
To demonstrate the difference between mutability and immutability, imagine taking a drink from a gla ...
- 20162314 《Program Design & Data Structures》Learning Summary Of The Fifth Week
20162314 2017-2018-1 <Program Design & Data Structures>Learning Summary Of The Fifth Week ...
随机推荐
- javac老提示无效的标记
加上-cp libs/*后,就开始提示无效的标记,搞了半天,似乎是shell展开的问题,估计是把后面的jar文件当源文件了? 加上引号就行了-cp "libs/*",不让shell ...
- Luogu 3616 富金森林公园
刚看到此题的时候:sb分块??? Rorshach dalao甩手一句看题 于是回去看题……果然是题读错了…… [思路] 对权值离散化后(要先读入所有输入里的权值一起离散化……所以一共有4e4个数据( ...
- Django ——Timezone 处理
Django ——Timezone 处理 https://blog.csdn.net/qq_37049781/article/details/79347278 2018年02月22日 14:50:24 ...
- DataTable 设置primarykey 后进行 Merge操作
1.先查看概念 可以看highplayer博客 http://blog.csdn.net/highplayer/article/details/6613817 2. protected void st ...
- [原创]MongoDB C++ 驱动部分问题解决方案(MongoDB C++ Driver)
本文为我长时间开发以及修改MongoDB C++ Driver时的一些问题和解决方案.目前本文所介绍的相关引擎也已经发布闭源版本,请自行下载 库版本以及相关位置:http://code.google. ...
- (回溯法)ip地址的合理性
题目: 给定一个只包含数字的字符串,通过返回所有可能有效的IP地址组合来恢复它. 例如: 给定“”, return [“255.255.11.135”,“255.255.111.35”]. (顺序无所 ...
- python 爬虫proxy,BeautifulSoup+requests+mysql 爬取样例
实现思路: 由于反扒机制,所以需要做代理切换,去爬取,内容通过BeautifulSoup去解析,最后入mysql库 1.在西刺免费代理网获取代理ip,并自我检测是否可用 2.根据获取的可用代理ip去发 ...
- docker run hello-world失败
提示镜像拉取失败,解决方案 到 https://cr.console.aliyun.com/ 注册一个账户 列表中就有 加速器 启动 Docker 端 右键 选择配置 在Docker Dae ...
- Http报头中不能添加中文字符
今逢一Bug,如下: Invalid non-ASCII or control character in header: 0x6D4B 大意为:报头中有非法字符.故可将其编码后,set入Header, ...
- javascript webstorm用法
javascript webstorm用法 一.什么是webstorm? WebStorm 是jetbrains公司旗下一款JavaScript 开发工具.被广大中国JS开发者誉为“We ...