Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 -> 4 after calling your function.

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一上来就感觉这个题没法做啊,没有提供头结点,只是被删除的节点,怎么找到被删除节点的上一个节点啊。
看了下其他人的答案,才发现自己已经形成了思维定势。
也可以采用节点内赋值的方法
void deleteNode(ListNode* node) {
if (node == nullptr)
return;
node->val = node->next->val;
node->next = node->next->next;
}

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