oracle sum(col1) over(partition by col2 order by col3):实现分组递增汇总

应公司业务要求，需要对数据进行分组汇总做辅助列进行查询

所以使用到了sum(col1) over(partition by col2 order by col3)函数，为了学习与提高在此进行记录。

1、准备数据源

CREATE TABLE TEST01 (
  NAME  VARCHAR(20),
  DEP_NO VARCHAR(10),
  SALARY  NUMBER(20,2)
);

2、插入数据

INSERT INTO TEST01(NAME,DEP_NO,SALARY) VALUES('张三','0010',12000);
INSERT INTO TEST01(NAME,DEP_NO,SALARY) VALUES('李四','0010',12500);
INSERT INTO TEST01(NAME,DEP_NO,SALARY) VALUES('王五','0020',13000);
INSERT INTO TEST01(NAME,DEP_NO,SALARY) VALUES('赵六','0020',11000);
INSERT INTO TEST01(NAME,DEP_NO,SALARY) VALUES('田七','0020',10000);
INSERT INTO TEST01(NAME,DEP_NO,SALARY) VALUES('如花','0030',8000);
INSERT INTO TEST01(NAME,DEP_NO,SALARY) VALUES('阿卡','0030',9000);
INSERT INTO TEST01(NAME,DEP_NO,SALARY) VALUES('似玉','0030',9500);
INSERT INTO TEST01(NAME,DEP_NO,SALARY) VALUES('撒人','0030',8800);
INSERT INTO TEST01(NAME,DEP_NO,SALARY) VALUES('三忍','0030',6000);
INSERT INTO TEST01(NAME,DEP_NO,SALARY) VALUES('三舞','0030',6600);

3、进行查询

SELECT T.NAME
             ,T.SALARY
             ,T.DEP_NO
             ,SUM(T.SALARY) OVER(PARTITION BY T.DEP_NO ORDER BY T.NAME)
   FROM TEST01 T;

　　查询结果如下图：

　　

这里对DEP_NO进行分组，根据NAME进行排序，然后统计每组递增汇总结果！