LCIS

Time Limit: 6000/2000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 5951    Accepted Submission(s): 2578

Problem Description
Given n integers.
You have two operations:
U A B: replace the Ath number by B. (index counting from 0)
Q A B: output the length of the longest consecutive increasing subsequence (LCIS) in [a, b].
 
Input
T in the first line, indicating the case number.
Each case starts with two integers n , m(0<n,m<=105).
The next line has n integers(0<=val<=105).
The next m lines each has an operation:
U A B(0<=A,n , 0<=B=105)
OR
Q A B(0<=A<=B< n).
 
Output
For each Q, output the answer.
 
Sample Input
1
10 10
7 7 3 3 5 9 9 8 1 8
Q 6 6
U 3 4
Q 0 1
Q 0 5
Q 4 7
Q 3 5
Q 0 2
Q 4 6
U 6 10
Q 0 9
 
Sample Output
1
1
4
2
3
1
2
5
 #include <iostream>
#include <cstring>
#include <cstdio>
using namespace std;
const int maxn=;
int T[maxn<<],L[maxn<<],R[maxn<<],ar[maxn],n,m; void Updata(int node,int l,int r)
{
int mid=(l+r)>>,a=node<<,b=a|; L[node]=L[a];
if(L[a]==mid-l+&&ar[mid]<ar[mid+])
L[node]+=L[b]; R[node]=R[b];
if(R[b]==r-mid&&ar[mid]<ar[mid+])
R[node]+=R[a]; T[node]=max(T[a],T[b]);
if(ar[mid]<ar[mid+])
T[node]=max(T[node],R[a]+L[b]);
} void Change(int node,int l,int r,int pos,int x)
{
if(l==r){
T[node]=L[node]=R[node]=;
ar[pos]=x;
return;
}
int mid=(l+r)>>;
if(mid>=pos)
Change(node<<,l,mid,pos,x);
else
Change(node<<|,mid+,r,pos,x);
Updata(node,l,r);
}
int ans; int Query(int node,int l,int r,int a,int b)
{
if(l>=a&&r<=b)
return T[node];
int mid=(l+r)>>;
int ret=;
if(a<=mid)
ret=Query(node<<,l,mid,a,b);
if(b>mid)
ret=max(ret,Query(node<<|,mid+,r,a,b));
if(a<=mid&&b>mid&&ar[mid]<ar[mid+])
ret=max(ret,min(R[node<<],mid-a+)+min(L[node<<|],b-mid));
return ret;
}
int main()
{
int Tk,a,b;
char s[];
scanf("%d",&Tk);
while(Tk--)
{
scanf("%d%d",&n,&m);
memset(L,,sizeof(L));
memset(R,,sizeof(R));
memset(T,,sizeof(T)); for(int i=;i<=n;i++){
scanf("%d",&ar[i]);
Change(,,n,i,ar[i]);
}
while(m--){
scanf("%s",s);
scanf("%d%d",&a,&b);
if(s[]=='U')
Change(,,n,a+,b);
else{
printf("%d\n",Query(,,n,a+,b+));
}
}
}
return ;
}

线段树(区间维护):HDU 3308 LCIS的更多相关文章

  1. 线段树(区间合并) HDOJ 3308 LCIS

    题目传送门 题意:线段树操作:1. 单点更新 2. 求区间的LCIS(longest consecutive increasing subsequence) 分析:注意是连续的子序列,就是简单的区间合 ...

  2. hdu 1556 Color the ball(线段树区间维护+单点求值)

    传送门:Color the ball Color the ball Time Limit: 9000/3000 MS (Java/Others)    Memory Limit: 32768/3276 ...

  3. HDU 6315 Naive Operations(线段树+区间维护)多校题解

    题意:a数组初始全为0,b数组题目给你,有两种操作: 思路:dls的思路很妙啊,我们可以将a初始化为b,加一操作改为减一,然后我们维护一个最小值,一旦最小值为0,说明至少有一个ai > bi,那 ...

  4. 线段树 + 区间更新 ----- HDU 4902 : Nice boat

    Nice boat Time Limit: 30000/15000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Tot ...

  5. POJ3468(线段树区间维护)

    A Simple Problem with Integers Time Limit: 5000MS   Memory Limit: 131072K Total Submissions: 85502   ...

  6. HDU1540 Tunnel Warfare(线段树区间维护&求最长连续区间)题解

    Tunnel Warfare Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)To ...

  7. 线段树-区间更新-HDU 1689

    #include <iostream> #include <cstdio> #include <string> #include <cstring> # ...

  8. hdu 5475 An easy problem(暴力 || 线段树区间单点更新)

    http://acm.hdu.edu.cn/showproblem.php?pid=5475 An easy problem Time Limit: 8000/5000 MS (Java/Others ...

  9. LCIS HDU - 3308 (线段树区间合并)

    LCIS HDU - 3308 Given n integers. You have two operations: U A B: replace the Ath number by B. (inde ...

随机推荐

  1. iOS图片压缩

    项目中常会遇到,上传图片的操作,由于iPhone手机直接拍照的图片往往比较大,一般3-4M,如果直接上传不做处理会浪费用户很多流量,再者有很多场景并不需要高清图片,所以在上传图片前对图片进行压缩,是很 ...

  2. 9.23 noip模拟试题

      Problem 1 抓牛(catchcow.cpp/c/pas) [题目描述] 农夫约翰被通知,他的一只奶牛逃逸了!所以他决定,马上出发,尽快把那只奶牛抓回来. 他们都站在数轴上.约翰在N(O≤N ...

  3. Quartz Features

    Runtime Environments Quartz can run embedded within another free standing application Quartz can be ...

  4. R cannot be resolved to a variable

    1. 检查Android 的SDK是否丢失需要重新下载,检查build path,把需要导入的JAR包确认都导入成功 2. 确保class没有import Android.R,注意是不能有Androi ...

  5. android menu菜单自动生成

    Android提供了一些简单的方法来为应用添加Menu菜单. 提供了三种类型应用菜单: 一.Options Menu:通过Menu按钮调用菜单 1.在/res/目录下新建menu文件夹,用于存储Men ...

  6. sublime text 2 笔记

    sublime text 2 ,是代码程序员最佳编辑器,不是之一.其快捷优雅的操作风格,和便利的快捷键,是程序员码农的不二选择. 网上下载sublime text 2,支持文件拖放,文件夹拖放.3.0 ...

  7. Core Data 教学

    看了一篇国外的文章,关于iOS9的Core Data教学,在这里做了一下总结 Core Data 教学 示例开源地址:LastDayCoreData 在这篇文章中我们将学习Core Data的系列教程 ...

  8. error C2220: warning treated as error - no 'object' file generated解决方法

    error C2220: warning treated as error - no 'object' file generated 警讯视为错误 - 生成的对象文件 / WX告诉编译器将所有警告视为 ...

  9. linux负载均衡

    1.linux lvs nat实现负载均衡 添加两块网卡并开启路由管道 > /proc/sys/net/ipv4/ip_forward //开始路由管道 安装ipvsadm yum instal ...

  10. ios开发之ios9UIWebView不显示网页问题

    错误描述: App Transport Security has blocked a cleartext HTTP (http://) resource load since it is insecu ...