Building a Space Station
Time Limit: 1000MS   Memory Limit: 30000K
Total Submissions: 5874   Accepted: 2914

Description

You are a member of the space station engineering team, and are assigned a task in the construction process of the station. You are expected to write a computer program to complete the task. 

The space station is made up with a number of units, called cells. All cells are sphere-shaped, but their sizes are not necessarily uniform. Each cell is fixed at its predetermined position shortly after the station is successfully put into its orbit. It is
quite strange that two cells may be touching each other, or even may be overlapping. In an extreme case, a cell may be totally enclosing another one. I do not know how such arrangements are possible. 



All the cells must be connected, since crew members should be able to walk from any cell to any other cell. They can walk from a cell A to another cell B, if, (1) A and B are touching each other or overlapping, (2) A and B are connected by a `corridor', or
(3) there is a cell C such that walking from A to C, and also from B to C are both possible. Note that the condition (3) should be interpreted transitively. 



You are expected to design a configuration, namely, which pairs of cells are to be connected with corridors. There is some freedom in the corridor configuration. For example, if there are three cells A, B and C, not touching nor overlapping each other, at least
three plans are possible in order to connect all three cells. The first is to build corridors A-B and A-C, the second B-C and B-A, the third C-A and C-B. The cost of building a corridor is proportional to its length. Therefore, you should choose a plan with
the shortest total length of the corridors. 



You can ignore the width of a corridor. A corridor is built between points on two cells' surfaces. It can be made arbitrarily long, but of course the shortest one is chosen. Even if two corridors A-B and C-D intersect in space, they are not considered to form
a connection path between (for example) A and C. In other words, you may consider that two corridors never intersect. 

Input

The input consists of multiple data sets. Each data set is given in the following format. 





x1 y1 z1

posted on 2017-06-19 10:53 cynchanpin 阅读(...) 评论(...) 编辑 收藏

var allowComments=true,cb_blogId=347763,cb_entryId=7047739,cb_blogApp=currentBlogApp,cb_blogUserGuid='43c87c18-831e-e711-9fc1-ac853d9f53cc',cb_entryCreatedDate='2017/6/19 10:53:00';loadViewCount(cb_entryId);var cb_postType=1;var isMarkdown=false;

poj2031-Building a Space Station(最小生成树,kruskal,prime)的更多相关文章

  1. POJ2031 Building a Space Station 2017-04-13 11:38 48人阅读 评论(0) 收藏

    Building a Space Station Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 8572   Accepte ...

  2. POJ 2031 Building a Space Station (最小生成树)

    Building a Space Station Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 5173   Accepte ...

  3. POJ 2031:Building a Space Station 最小生成树

    Building a Space Station Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 6083   Accepte ...

  4. POJ-2031 Building a Space Station (球的最小生成树)

    http://poj.org/problem?id=2031 Description You are a member of the space station engineering team, a ...

  5. Building a Space Station(kruskal,说好的数论呢)

    Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 3820   Accepted: 1950 Description You a ...

  6. POJ - 2031C - Building a Space Station最小生成树

    You are a member of the space station engineering team, and are assigned a task in the construction ...

  7. POJ Building a Space Station 最小生成树

    Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 15664   Accepted: 6865 Description You ...

  8. POJ2031 Building a Space Station【最小生成树】

    题意: 就是给出三维坐标系上的一些球的球心坐标和其半径,搭建通路,使得他们能够相互连通.如果两个球有重叠的部分则算为已连通,无需再搭桥.求搭建通路的最小边长总和是多少. 思路: 先处理空间点之间的距离 ...

  9. poj2031 Building a Space Station

    这题目,用G++ WA,用C++ AC. 题目要求,现给出n个球,然后要使每两个球直接或者间接连通,可以在任意两球之间做管道(在表面),最后的要求是,如果使得都连通的话,管道最小长度是多少. 思路简单 ...

  10. POJ 2031 Building a Space Station 最小生成树模板

    题目大意:在三维坐标中给出n个细胞的x,y,z坐标和半径r.如果两个点相交或相切则不用修路,否则修一条路连接两个细胞的表面,求最小生成树. 题目思路:最小生成树树模板过了,没啥说的 #include& ...

随机推荐

  1. POJ 1064 Cable master 【二分答案】

    和杭电那一题一样,只不过G++交不能通过,C++能过 wa了好多好多好多次----------------------------------------- #include<iostream& ...

  2. javascript 异或运算符实现简单的密码加密功能

    写在前面的 当我们需要在数据库中存储用户的密码时,当然是不能明文存储的. 我们就是介绍一下用^运算符来实现简单的密码加密以及解密功能 上代码 首先,回顾一下基础知识. String.fromCharc ...

  3. 爬虫来啦!Day91

    # 一.爬虫# 1.基本操作# 排名爬虫刷票# 抽屉网的所有发布新闻点赞# 自动化程序模拟用于的日常操作# 投票的机制是利用cookies,禁用cookies模式# 自定义的异步IO模块就是Socke ...

  4. C语言的常用printf打印占位符%d, %u, %f, %s, %c, %o, %x

    占位符含义及用法 代码: #include <stdio.h> int main(int argc, char const *argv[]) { , b = -; // 默认10进制赋值 ...

  5. C语言传参的类型匹配

    有一个这样的问题: 形参const char *p和实参char *c可以匹配 形参const char**p和实参char**c不可以匹配 注:argument和parameter:严格而言,par ...

  6. 紫书 习题8-11 UVa 1615 (区间选点问题)

    这个点就是贪心策略中的区间选点问题. 把右端点从大到小排序, 左端点从小到大排序. 每次取区间右端点就可以了, 到不能覆盖的时候就ans++, 重新取点 ps:这道题不考虑精度也可以过 要着重复习一下 ...

  7. vue2.0移动端自定义性别选择提示框

    这篇文章主要是简单的实现了vue2.0移动端自定义性别选择的功能,很简单但是经常用到,于是写了一个小小的demo,记录下来. 效果图: 实现代码: <template> <div c ...

  8. A simpleHttp Proxy

    http://www.java2s.com/Code/Java/Network-Protocol/Asimpleproxyserver.htm

  9. Android使用ShowcaseView加入半透明操作提示图片的方法

    http://beeder.me/2014/11/11/how-to-add-a-semi-transparent-demo-screen-using-showcaseview/ 这篇文章具体介绍了如 ...

  10. [MST] Loading Data from the Server using lifecycle hook

    Let's stop hardcoding our initial state and fetch it from the server instead. In this lesson you wil ...