Leetcode_237_Delete Node in a Linked List
本文是在学习中的总结,欢迎转载但请注明出处:http://blog.csdn.net/pistolove/article/details/47334649
Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.
Supposed the linked list is 1 -> 2 -> 3 -> 4
and you are given the third node with value 3
, the linked list should become 1 -> 2 -> 4
after calling your function.
思路:
(1)该题为给定一个链表中的一个节点,要求删除该节点。
(2)该题主要对链表存储的考察。在一般情况下,要删除链表的一个节点,需要知道当前节点的前驱节点。该题没有给出前驱节点,所以就需要将当前节点的后继节点的值复制到当前节点,然后删除后继节点即可。
(3)该题比较简单。详情见下方代码。希望本文对你有所帮助。
算法代码实现如下:
package leetcode; import leetcode.utils.ListNode; /** * * @author lqq * */ public class Delete_Node_in_a_LinkedList { public void deleteNode(ListNode node) { if (node == null) return; ListNode after = node.next; if (after != null) { int value = after.val; node.val = value; node.next = after.next; } } }
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