MongoDB数据库的操作，增删改查

在student集合中插入一些数据

db.student.insert({
"学号":10010,
"姓名":"德莱文",
"年龄":26,
"地址":"淄博市"
});

var stuData1={
"学号":10020,
"姓名":"奥巴马",
"年龄":27,
"地址":"艾泽拉斯"
};
db.student.insert(stuData1);

var stuData2={
"学号":10030,
"姓名":"女枪",
"年龄":27,
"地址":"艾泽拉斯"
};
db.student.insert(stuData2);

var stuData3={
"学号":10050,
"姓名":"瑞雯",
"年龄":18,
"地址":"超神学院"
};
db.student.insert(stuData3);

　　插入数组（数据为json）

var stuData=[
{"姓名":"Anner","age":26},
{"姓名":"James","age":28},
{"姓名":"Allen","age":31},
{"姓名":"Smith","age":17}
];
db.student.insert(stuData);

　　插入insert()，用JavaScript操作

//添加1万条数据
for(var i=0;i<10000;i++){
db.student.insert({"vid":"www.oracle.com"+i+"line"});
};

　　查看数据

db.student.find();

　　●数据查询

　　　示例1：查询学号为10020的记录

db.student.find({"学号":10020});
db.student.find({"学号":10020}).pretty();

　　示例2：不显示_id的查询

db.student.find({"学号":10020},{"_id":0});

　　●关系运算

> $gt
< $lt
>= $gte
<= $lte
!= $ne
= key:value $eq

定义一个员工信息集合

db.employee.drop();
db.employee.insert([
{"name":"Smith","age":25,"sex":"男","job":"教授","addr":"北京大学","cellphone":"17166660001"},
{"name":"Clark","age":29,"sex":"男","job":"讲师","addr":"燕京大学","cellphone":"17166660002"},
{"name":"Allen","age":28,"sex":"女","job":"主任","addr":"南京大学","cellphone":"17166660003"},
{"name":"Anner","age":15,"sex":"女","job":"宣传","addr":"东京大学","cellphone":"17166660004"},
{"name":"James","age":19,"sex":"男","job":"教务","addr":"西京大学","cellphone":"17166660005"}
]);
db.employee.find();
db.employee.find().pretty();

　　示例3：查询姓名为Anner的记录

db.employee.find({"name":"Anner"}).pretty();

　　示例4：查询性别为男的记录

db.employee.find({"sex":"男"}).pretty();

　　示例5：查询年龄大于19岁的记录

db.employee.find({"age":{"$gt":19}}).pretty();

　　示例6：查询年龄小于等于19岁的记录

db.employee.find({"age":{"$lte":19}}).pretty();

　　示例7：查询性别不是女的的记录

db.employee.find({"sex":{"$ne":"女"}}).pretty();

　　●逻辑运算

与 $and
或 $or
非 $not $nor

　　示例8：查询年龄在10~20之间的记录

db.employee.find({"age":{"$gt":10,"$lte":20}});
db.employee.find({"age":{"$gt":10,"$lte":20}}).pretty();

　　示例9：查询年龄不是19岁的记录

db.employee.find({"age":{"$ne":19}});

　　示例10：查询年龄大于19岁，或者性别为女的记录

db.employee.find({"age":{"$gt":19}},);

db.employee.find({"$or":[
	{"age":{"$gt":19}},
	{"sex":{"$eq":"女"}}
]});

　　示例11：对上一题求反

db.employee.find({"$nor":[
	{"age":{"$gt":19}},
	{"sex":{"$eq":"女"}}
]});

　　●模运算 "$mod"

　　示例12：求年龄mod27余1的记录，也就是28

db.employee.find({"age":{"$mod":[27,1]}});

　　

　　●范围查询
　　$in $nin

　　示例13：查询姓名是Allen，Anner，James的记录

db.employee.find({"name":{"$in":["Allen","Anner","James"]}});

　　示例14：查询姓名不是Allen，Anner，James的记录

db.employee.find({"name":{"$nin":["Allen","Anner","James"]}})

　　构建一个集合 employee集合

db.employee.insert([
{"name":"Jones","age":31,"sex":"男","job":"技术员","addr":"哈佛大学","cellphone":"15166660001"},
{"name":"Blake","age":35,"sex":"男","job":"销售员","addr":"牛津大学","cellphone":"15166660002"},
{"name":"Martin","age":21,"sex":"男","job":"销售员","addr":"剑桥大学","cellphone":"15166660003"},
{"name":"Turner","age":25,"sex":"女","job":"后勤","addr":"北京大学","cellphone":"15166660004"},
{"name":"Miller","age":23,"sex":"女","job":"行政","addr":"南京大学","cellphone":"15166660005"}
]);

　　示例15：查询job不是"技术员"的记录

db.emp.find({"jod":{"$nin":["技术员"]}});