hdu 2102 A计划_bfs搜索

题意：略

思路：此题陷阱超多，当##，#*,*#时不能走进去，套下模板就行了。

#include <iostream>
#include<cstdio>
#include<cstring>
#include<queue>
using namespace std;
#define N 20
struct node{
    int x,y,z;
    int step;
}pri;
int next[][2]={{1,0},{0,1},{-1,0},{0,-1}};
char map[2][N][N];
int n,m,time;
bool vis[2][N][N];
bool check(node a){
    if(a.x>=0&&a.x<n&&a.y>=0&&a.y<m&&map[a.z][a.x][a.y]!='*'
    &&!vis[a.z][a.x][a.y]&&a.step<=time)
        return 1;
    return 0;
}
bool bfs(){
    int i;
    queue<node>q;
    node tmp;
    memset(vis,0,sizeof(vis));
    q.push(pri);
    vis[pri.z][pri.x][pri.y]=1;
    while(!q.empty()){
        tmp=q.front();
        q.pop();
        if(map[tmp.z][tmp.x][tmp.y]=='P'&&tmp.step<=time)
            return 1;
        for(i=0;i<4;i++){
            node u;
            u=tmp;
            u.x+=next[i][0];
            u.y+=next[i][1];
            u.step+=1;
            if(check(u)){
                vis[u.z][u.x][u.y]=1;
                if(map[u.z][u.x][u.y]=='#'&&!vis[(u.z+1)%2][u.x][u.y]){
                    u.z=(u.z+1)%2;
                }
                q.push(u);
            }
        }
    }
    return 0;
}
int main(int argc, char** argv) {
    int t,i,j,k;
    scanf("%d",&t);
    while(t--){
        scanf("%d%d%d",&n,&m,&time);
        for(k=0;k<2;k++)
        for(i=0;i<n;i++){
            scanf("%s",map[k][i]);
            for(j=0;j<m;j++){
                if(map[k][i][j]=='S'){
                    pri.x=i;
                    pri.y=j;
                    pri.z=k;
                    pri.step=0;
                }
            }
        }

        for(i=0;i<n;i++)
            for(j=0;j<m;j++){
                if(map[0][i][j]=='#'&&map[1][i][j]=='#')
                    map[0][i][j]=map[1][i][j]='*';
                if(map[0][i][j]=='*'&&map[1][i][j]=='#')
                    map[0][i][j]=map[1][i][j]='*';
                if(map[1][i][j]=='*'&&map[0][i][j]=='#')
                    map[0][i][j]=map[1][i][j]='*';
            }
        if(bfs())
            printf("YES\n");
        else
            printf("NO\n");
    }
    return 0;
}