LN : leetcode 263 Ugly Number
lc 263 Ugly Number
Write a program to check whether a given number is an ugly number.
Ugly numbers are positive numbers whose prime factors only include 2, 3, 5. For example, 6, 8 are ugly while 14 is not ugly since it includes another prime factor 7.
Note that 1 is typically treated as an ugly number.
analysation##
Use recursion, then the problem will be much easier.
solution
bool isUgly(int num) {
if (num <= 0)
return 0;
if (num == 1)
return 1;
else if (num%2 == 0)
return isUgly(num/2);
else if (num%3 == 0)
return isUgly(num/3);
else if (num%5 == 0)
return isUgly(num/5);
return 0;
}
LN : leetcode 263 Ugly Number的更多相关文章
- leetcode 263. Ugly Number 、264. Ugly Number II 、313. Super Ugly Number 、204. Count Primes
263. Ugly Number 注意:1.小于等于0都不属于丑数 2.while循环的判断不是num >= 0, 而是能被2 .3.5整除,即能被整除才去除这些数 class Solution ...
- [LeetCode] 263. Ugly Number 丑陋数
Write a program to check whether a given number is an ugly number. Ugly numbers are positive numbers ...
- LeetCode 263 Ugly Number
Problem: Write a program to check whether a given number is an ugly number. Ugly numbers are positiv ...
- Leetcode 263 Ugly Number 数论 类似质因数分解
Ugly Number的质因数仅为2,3,5 将输入的数分别除以2,3,5直到不能除,看是否为1,为1的是Ugly Number,其他则不是. class Solution { public: boo ...
- (easy)LeetCode 263.Ugly Number
Write a program to check whether a given number is an ugly number. Ugly numbers are positive numbers ...
- Java [Leetcode 263]Ugly Number
题目描述: Write a program to check whether a given number is an ugly number. Ugly numbers are positive n ...
- [leetcode] 263. Ugly Number (easy)
只要存在一种因数分解后,其因子是2,3,5中的一种或多种,就算是ugly数字. 思路: 以2/3/5作为除数除后,最后结果等于1的就是ugly数字 Runtime: 4 ms, faster than ...
- [LeetCode] 264. Ugly Number II 丑陋数 II
Write a program to find the n-th ugly number. Ugly numbers are positive numbers whose prime factors ...
- 263. Ugly Number(C++)
263. Ugly Number Write a program to check whether a given number is an ugly number. Ugly numbers are ...
随机推荐
- [Jexus系列] 一、安装并运行 Jexus
注意,本教程使用的jexus版本为5.8.3专业版,操作系统为 Ubunutu 16.04 64位 一.创建默认站点 不熟悉vim的可以看这个: vim超简单入门教程 sudo mkdir -p /v ...
- Jsp+servlet 验证码案例
昨晚在csdn看到一位前辈写一个ajax+servlet+jsp验证.顿时心血来潮,在阅读前辈的代码下我亲手体验一下,做了一个验证码生成工具类.以供大家做个參考. 1:加入VeriyCodeUtils ...
- python的字典有些类似js对象
python的字典有些类似js对象 dict1 = {} dict1['one']= '1-one' dict1[2] = '2-tow' tinydict = {'name':'tome','cod ...
- 具体解释Android定位
相信非常多的朋友都有在APP中实现定位的需求,今天我就再次超炒冷饭,为大家献上国内开发人员经常使用到的三种定位方式.它们分别为GPS,百度和高德,惯例先简介下定位的背景知识. 什么是GPS定位.基站定 ...
- FFmpeg的HEVC解码器源码简单分析:概述
===================================================== HEVC源码分析文章列表: [解码 -libavcodec HEVC 解码器] FFmpeg ...
- Codeforces 216D Spider's Web 树状数组+模拟
题目链接:http://codeforces.com/problemset/problem/216/D 题意: 对于一个梯形区域,假设梯形左边的点数!=梯形右边的点数,那么这个梯形为红色.否则为绿色, ...
- linux服务器上的mysql允许远程连接
首先进入mysql: 输入GRANT ALL PRIVILEGES ON *.* TO 'root'@'%' IDENTIFIED BY '123456' WITH GRANT OPTION; 这里是 ...
- maven 打包排除配置文件
如果你想通过pom.xml文件的配置实现的话,你可以这样1.打jar包时过滤配置文件<build><!-- 过滤配置文件 --><resources><res ...
- dm385和8127的区别
DM385/DM8127在ITS智能交通中的应用分析德州仪器(TI)自推出DM385和DM8127视频处理器在业界反响很大特别是深圳安博会上展出的1080P60帧高清效果之后很多龙头企业也跃 ...
- kernel devel 安装与卸载
1.查看系统内核 uname -r 2.查看已安装kernel-devel uname -a ; rpm -qa kernel\* | sort 3.下载对应的rpm wget xxx/kernel- ...