B. The Monster and the Squirrel
B. The Monster and the Squirrel
Ari the monster always wakes up very early with the first ray of the
sun and the first thing she does is feeding her squirrel.Ari draws a regular convex polygon on the floor and numbers it’s
vertices 1, 2, …, n in clockwise order. Then starting from the
vertex 1 she draws a ray in the direction of each other vertex. The
ray stops when it reaches a vertex or intersects with another ray
drawn before. Ari repeats this process for vertex 2, 3, …, n (in
this particular order). And then she puts a walnut in each region
inside the polygon.
Ada the squirrel wants to collect all the walnuts, but she is not
allowed to step on the lines drawn by Ari. That means Ada have to
perform a small jump if she wants to go from one region to another.
Ada can jump from one region P to another region Q if and only if P
and Q share a side or a corner.Assuming that Ada starts from outside of the picture, what is the
minimum number of jumps she has to perform in order to collect all the
walnuts?Input The first and only line of the input contains a single integer n
(3 ≤ n ≤ 54321) - the number of vertices of the regular polygon drawn
by Ari.Output Print the minimum number of jumps Ada should make to collect
all the walnuts. Note, that she doesn’t need to leave the polygon
after.
Examples
Input
5
Output
9
Input
3
Output
1
Note One of the possible solutions for the first sample is shown on
the picture above.
题解如下
解题说明:题目的意思是每个点依次和其他点连线,如果这条直线连接的过程中,和另外一条直线相交的话,就会被截断。然后问你,正n边形,被截成了多少块。此题可以考虑用找规律的方法,先从边数少的n边型开始,计算数目,最后发现规律,值为(n-2)*(n-2)。网上有详细证明过程:
After drawing the rays from the first vertex (n - 2) triangles are formed. The subsequent rays will generate independently sub-regions in these triangles. Let’s analyse the triangle determined by vertices 1, i, i + 1, after drawing the rays from vertex i and (i + 1) the triangle will be divided into (n - i) + (i - 2) = n - 2 regions. Therefore the total number of convex regions is (n - 2)2

If the squirrel starts from the region that have 1 as a vertex, then she can go through each region of triangle (1, i, i + 1) once. That implies that the squirrel can collect all the walnuts in (n - 2)2 jumps.
思路如下
#include<iostream>
#include<algorithm>
using namespace std;
int main()
{
long long n;
cin>>n;
cout<<(n-2)*(n-2)<<endl;
return 0;
}
B. The Monster and the Squirrel的更多相关文章
- Codeforces Round #328 (Div. 2) B. The Monster and the Squirrel 打表数学
B. The Monster and the Squirrel Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/c ...
- Codeforces Round #328 (Div. 2)_B. The Monster and the Squirrel
B. The Monster and the Squirrel time limit per test 1 second memory limit per test 256 megabytes inp ...
- codeforces 592B The Monster and the Squirrel
题目链接:http://codeforces.com/contest/592/problem/B 题目分类:数学,找规律 题目分析:重要的是画图找规律 代码: #include<bits/s ...
- Codeforces Round #328 (Div. 2)
这场CF,准备充足,回寝室洗了澡,睡了一觉,可结果... 水 A - PawnChess 第一次忘记判断相等时A先走算A赢,hack掉.后来才知道自己的代码写错了(摔 for (int i=1; ...
- codeforces 592B/C
题目链接:http://codeforces.com/contest/592/problem/B B. The Monster and the Squirrel time limit per test ...
- Codeforces Round #328 (Div. 2) B
B. The Monster and the Squirrel time limit per test 1 second memory limit per test 256 megabytes inp ...
- Squirrel: 通用SQL、NoSQL客户端
安装 配置数据库 配置驱动 配置连接 如果你的工作中,需要使用到多个数据库,又不想在多种客户端之间切换来切换去.那么就需要找一款支持多数据库的客户端工具了.如果你要连接多个关系型数据库,你就可以使用N ...
- Font Squirrel
Font Squirrel FontSquirrel:国外免费字体下载网是一个提供高质量商业字体下载网站,提供海量的英文字体库,用户可以随意下载并应用于各种商业用字,无需考虑其版权问题. 官网地址:h ...
- 使用Squirrel创建基于Electron开发的Windows 应用安装包
我们把自己开发的Electron应用发布之前,需要把app打包成简单的安装包,这样app更容易被获取,以此来发布我们的应用.我们可以参考Wix或其他的安装程序,但是对于Electron应用更好的打包程 ...
随机推荐
- Codeforces Round #292 (Div. 2) C. Drazil and Factorial 515C
C. Drazil and Factorial time limit per test 2 seconds memory limit per test 256 megabytes input stan ...
- 第三篇:Linux的基本操作与文件管理(纯命令行模式下)(下)
接上篇介绍完软件的管理(查询.删除.安装)之后,本篇将介绍Linux的文件和目录的管理. 如何浏览Linux的目录(文件夹),就像Windows一样,我们平时需要打开各个目录,去里面找一找曾经悄悄存储 ...
- TCP粘包很难么,为何我屡屡受挫??
无论走到哪里,都应该记住,过去都是假的,回忆是一条没有尽头的路,一切以往的春天都不复存在,就连那最坚韧而又狂乱的爱情归根结底也不过是一种转瞬即逝的现实. --马尔克斯 本文已经收录至我的GitHub, ...
- 等宽字体的妙用-loading 点点点动画
原理 ch等宽字体 + text-indent 动画负缩进 显示效果如 loading . loading .. loading ... loading . loading .. loading .. ...
- POJ 1879
栈和队列的综合应用,利用栈和队列分别模拟分,5分,时槽,以及小球队列 利用求出一天后的置换可以求出周期,进而求出最大公约数(可以利用矩阵的角度,也许可以简化,因为每次都是乘上一个相同的置换矩阵) 要注 ...
- 测试必知必会系列- Linux常用命令 - mv
21篇测试必备的Linux常用命令,每天敲一篇,每次敲三遍,每月一循环,全都可记住!! https://www.cnblogs.com/poloyy/category/1672457.html 移动当 ...
- [项目分享]JSP+Servlet+JDBC实现的学生信息管理系统
本文存在视频版本,请知悉 项目简介 项目来源于:https://gitee.com/liu_xu111/JavaWeb01 这次分享一个学生管理系统,我感觉这是程序员在大学时期的毕设和课程设计选择最多 ...
- Natas4 Writeup(Referer篡改)
Natas4: 提示来源出错,合法用户只能来自"http://natas5.natas.labs.overthewire.org/". 在http的header中,referer代 ...
- python编码的原理以及写入文件中乱码的原因
1.unicode可以理解为世界上所有字符的集合,它不对应二进制编码 2.详见: https://blog.csdn.net/qq_33692803/article/details/81321340 ...
- 常用正则表达式(手机号、邮箱、URL地址、身份证等等)
一.前言 不好的习惯:1.每一次用到正则都是上网copy一份,也没有去学习思考,看看都是什么意思: 2.一个项目里不同的地方用到了相同的校验,一直在重复的copy代码,并没有统一起来,万一哪天要修改规 ...