C++

Traverse

 /**
* Definition of TreeNode:
* class TreeNode {
* public:
* int val;
* TreeNode *left, *right;
* TreeNode(int val) {
* this->val = val;
* this->left = this->right = NULL;
* }
* }
*/
class Solution {
public:
/**
* @param root: a TreeNode, the root of the binary tree
* @return: nothing
*/
void flatten(TreeNode *root) {
if(!root) return;
vector<TreeNode*> allNodes;
preorder(root, allNodes);
int n = allNodes.size();
for(int i=; i<n-; i++) {
allNodes[i]->left = NULL;
allNodes[i]->right = allNodes[i+];
}
allNodes[n-]->left = allNodes[n-]->right = NULL;
} void preorder(TreeNode *root, vector<TreeNode*> &allNodes) {
if(!root) return;
allNodes.push_back(root);
preorder(root->left, allNodes);
preorder(root->right, allNodes);
}
};

C++

Divide-Conquer

Recursive

 /**
* Definition of TreeNode:
* class TreeNode {
* public:
* int val;
* TreeNode *left, *right;
* TreeNode(int val) {
* this->val = val;
* this->left = this->right = NULL;
* }
* }
*/
class Solution {
public:
/**
* @param root: a TreeNode, the root of the binary tree
* @return: nothing
*/
void flatten(TreeNode *root) {
helper(root);
} TreeNode* helper(TreeNode *root) {
if (root == NULL) {
return NULL;
}
if (root->left == NULL && root->right == NULL) {
return root;
}
if (root->left == NULL) {
return helper(root->right);
}
if (root->right == NULL) {
root->right = root->left;
root->left = NULL;//!important
return helper(root->right);
}
//Divide
TreeNode *leftLastNode = helper(root->left);
TreeNode *rightLastNode = helper(root->right); //Conquer
leftLastNode->right = root->right;
root->right = root->left;
root->left = NULL;//!important
return rightLastNode;
}
};

LintCode: Flatten Binary Tree to Linked List的更多相关文章

  1. [LintCode] Flatten Binary Tree to Linked List 将二叉树展开成链表

    Flatten a binary tree to a fake "linked list" in pre-order traversal. Here we use the righ ...

  2. Flatten Binary Tree to Linked List (LeetCode #114 Medium)(LintCode #453 Easy)

    114. Flatten Binary Tree to Linked List (Medium) 453. Flatten Binary Tree to Linked List (Easy) 解法1: ...

  3. 31. Flatten Binary Tree to Linked List

    Flatten Binary Tree to Linked List Given a binary tree, flatten it to a linked list in-place. For ex ...

  4. 【LeetCode】Flatten Binary Tree to Linked List

    随笔一记,留做重温! Flatten Binary Tree to Linked List Given a binary tree, flatten it to a linked list in-pl ...

  5. 114. Flatten Binary Tree to Linked List(M)

    . Flatten Binary Tree to Linked List Given a binary tree, flatten it to a linked list in-place. For ...

  6. LeetCode 114| Flatten Binary Tree to Linked List(二叉树转化成链表)

    题目 给定一个二叉树,原地将它展开为链表. 例如,给定二叉树 1 / \ 2 5 / \ \ 3 4 6 将其展开为: 1 \ 2 \ 3 \ 4 \ 5 \ 6 解析 通过递归实现:可以用先序遍历, ...

  7. Leetcode:Flatten Binary Tree to Linked List 解题报告

    Flatten Binary Tree to Linked List Given a binary tree, flatten it to a linked list in-place. For ex ...

  8. [LeetCode]Flatten Binary Tree to Linked List题解(二叉树)

    Flatten Binary Tree to Linked List: Given a binary tree, flatten it to a linked list in-place. For e ...

  9. 【LeetCode】114. Flatten Binary Tree to Linked List

    Flatten Binary Tree to Linked List Given a binary tree, flatten it to a linked list in-place. For ex ...

随机推荐

  1. 一个例子来看C#泛型是如何登场的

    有这样一个有关汽车的类. public class Car { public int ID { get; set; } public string Make { get; set; } } 现在,在客 ...

  2. CentOS 安装 nexus (maven 私服)

    原文:https://www.sunjianhua.cn/archives/centos-nexus.html 1.下载 wget http://download.sonatype.com/nexus ...

  3. 网络拥塞控制(七)BIC-TCP

    转自:http://www.cnblogs.com/fll/archive/2009/02/24/1397592.html 上面我们已经提到了HSTCP,它通过简单的修改标准TCP的增长方式,从而达到 ...

  4. 使用Spire.Office for .NET(Word、Excel、PPT、PDF等)的初步感受

    前言 本文大部分内容来自http://www.codeproject.com/Articles/710747/First-thoughts-on-Spire-Doc-for-NET. 针对我个人来说, ...

  5. Java并发编程的艺术(七)——Executors

    Executors框架简介 Executor框架便是Java 5中引入的,其内部使用了线程池机制,它在java.util.cocurrent 包下,通过该框架来控制线程的启动.执行和关闭,可以简化并发 ...

  6. Orchard 之:Widget,兼看 Layer 在权限控制中的作用

    一:Widget 可以理解为控件,可以直接被页面所引用.行为类似与分部页面,比如,我们可以创建一个 商品列表 Widget,然后这个 Widget 就可以被很多页面所引用. 理解 Widget 这个概 ...

  7. ORM(Object-Relational Mapping 对象关系映射)如何实现(转)

    原文链接:http://blog.163.com/hzd_love/blog/static/13199988120107891854473/ 1.什么是ORM ORM的全称是Object Relati ...

  8. Doxygen简单经验谈。。。

    Doxygen,大名鼎鼎的文档生成工具,被Boost.OpenCasCade等诸多项目作为文档生成的不二人选.人说,才华横溢往往是高深莫测,这句话放在 Doxygen这里显然是不适用的.十八般武艺样样 ...

  9. 轻松搞定 easyui datagrid 二次加载的问题(转)

    对于使用url方式的初学者,经常碰到重复请求的问题,这个问题的根源是因为一旦设置了url参数,Datagrid组件在实例化的时候就会做请求,如何避免二次加载这样问题呢,个人觉得注意以下两点基本就可以防 ...

  10. Binary Tree Maximum Path Sum leetcode java

    题目: Given a binary tree, find the maximum path sum. The path may start and end at any node in the tr ...