luogu 2216 理想的正方形 单调队列(其实没有DP)

#include<bits/stdc++.h>

using namespace std;

const int A=;
const int N=;
int a,b,n;
int g[A][A],q[A][N],Q[A][N];
int head[A],tail[A];
int Head[A],Tail[A];

inline int read(){
    int x=,f=;char ch=getchar();
    while(!isdigit(ch)){if(ch=='-')f=-;ch=getchar();}
    while(isdigit(ch)){x=(x<<)+(x<<)+(ch^);ch=getchar();}
    return x*f;}

int main(){
    a=read(),b=read(),n=read();
    for(register int i=;i<=a;i++)
    for(register int j=;j<=b;j++) g[i][j]=read();

    for(register int j=;j<=b;j++){
       head[j]=tail[j]=;
       Head[j]=Tail[j]=;
       for(register int i=;i<=n-;i++){
           while(head[j]<=tail[j]&&g[i][j]<=g[q[j][tail[j]]][j]) tail[j]--;
           q[j][++tail[j]]=i;
           while(Head[j]<=Tail[j]&&g[i][j]>=g[Q[j][Tail[j]]][j]) Tail[j]--;
           Q[j][++Tail[j]]=i;
       }
    }
    int ans=0x3f3f3f3f;
    for(register int i=n;i<=a;i++){
        for(register int j=;j<=b;j++){
            while(head[j]<=tail[j]&&q[j][head[j]]<i-n+) head[j]++;
            while(head[j]<=tail[j]&&g[i][j]<=g[q[j][tail[j]]][j]) tail[j]--;
            q[j][++tail[j]]=i;

            while(Head[j]<=Tail[j]&&Q[j][Head[j]]<i-n+) Head[j]++;
            while(Head[j]<=Tail[j]&&g[i][j]>=g[Q[j][Tail[j]]][j]) Tail[j]--;
            Q[j][++Tail[j]]=i;
        }
        for(register int j=n;j<=b;j++){
            int mi=0x3f3f3f3f,mx=-0x3f3f3f3f;
            for(register int k=j-n+;k<=j;k++){
                mi=min(mi,g[q[k][head[k]]][k]);
                mx=max(mx,g[Q[k][Head[k]]][k]);
            }
            ans=min(ans,mx-mi);
        }
    }
    printf("%d\n",ans);return ;
} 

二维单调队列