给你一个字符串和字典,从头扫到位,如果到当前的字符的字符串存在于字典中,则显示 buzz.

例子:

ILOVEPINEAPPLEJUICE

字典:

[pine, apple, pineapple, juice, applejuice]

那么当我们到达ILOVEPINE的时候,就要buzz,当我们到达APPLE的时候,也要buzz,当我们到达JUICE的时候,也要buzz.

 public class Solution {

     public static void main(String[] args) {
Trie trie = new Trie();
trie.insert("apple");
trie.insert("pie");
trie.insert("applejuice");
trie.insert("juice"); Solution s = new Solution();
s.buzz("applepiejuice", trie.root);
} public void buzz(String str, Node root) {
List<Node> list = new ArrayList<Node>();
List<Node> temp = new ArrayList<Node>();
list.add(root);
for (int i = ; i < str.length(); i++) {
for (Node node : list) {
Node child = node.getChildNode(str.charAt(i));
if (child != null) {
temp.add(child);
if (child.isEnd) {
System.out.println("buzz");
}
}
}
if (i != ) {
Node child = root.getChildNode(str.charAt(i));
if (child != null) {
temp.add(child);
if (child.isEnd) {
System.out.println("buzz");
}
}
} list = temp;
temp = new ArrayList<Node>();
} }
} class Trie {
Node root; public Trie() {
root = new Node(' ');
} public void insert(String word) {
if (exists(word))
return;
Node current = root;
for (int i = ; i < word.length(); i++) {
char ch = word.charAt(i);
Node node = current.getChildNode(ch);
if (node == null) {
current.map.put(ch, new Node(ch));
current = current.getChildNode(ch);
} else {
current = node;
}
}
current.isEnd = true;
} public boolean exists(String word) {
Node current = root;
for (int i = ; i < word.length(); i++) {
char ch = word.charAt(i);
current = current.getChildNode(ch);
if (current == null) {
return false;
}
}
if (current.isEnd) {
return true;
} else {
return false;
}
} } class Node {
char ch;
boolean isEnd;
Map<Character, Node> map; public Node(char ch) {
this.ch = ch;
map = new HashMap<Character, Node>();
} public Node getChildNode(char ch) {
return map.get(ch);
}
}

Buzz words的更多相关文章

  1. [LeetCode] Fizz Buzz 嘶嘶嗡嗡

    Write a program that outputs the string representation of numbers from 1 to n. But for multiples of ...

  2. 412. Fizz Buzz

    https://leetcode.com/problems/fizz-buzz/ 没什么好说的,上一个小学生解法 class Solution(object): def fizzBuzz(self, ...

  3. Lintcode 9.Fizz Buzz 问题

    ------------------------ AC代码: class Solution { /** * param n: As description. * return: A list of s ...

  4. LeetCode 412. Fizz Buzz

    Problem: Write a program that outputs the string representation of numbers from 1 to n. But for mult ...

  5. LeetCode之412. Fizz Buzz

    -------------------------------------------- 虽然是从最简单的开始刷起,但木有想到LeetCode上也有这么水的题目啊... AC代码: public cl ...

  6. LeetCode Fizz Buzz

    原题链接在这里:https://leetcode.com/problems/fizz-buzz/ 题目: Write a program that outputs the string represe ...

  7. Fizz Buzz

    class Solution { public: /** * param n: As description. * return: A list of strings. */ vector<st ...

  8. LintCode (9)Fizz Buzz

    下面是AC代码,C++风格: class Solution { public: vector<string> fizzBuzz(int N) { vector<string> ...

  9. [重构到模式-Chain of Responsibility Pattern]把Fizz Buzz招式重构到责任链模式

    写一段程序从1打印到100,但是遇到3的倍数时打印Fizz,遇到5的倍数时打印Buzz,遇到即是3的倍数同时也是5的倍数时打印FizzBuzz.例如: 1 2 Fizz 4 Buzz Fizz 7 8 ...

随机推荐

  1. 【MVC5】画面多按钮提交

    画面上有个多个按钮时,如何绑定到各自的Action上? 1.追加如下MultipleButtonAttribute类 1 using System; 2 using System.Reflection ...

  2. Nginx 支持 WAF 防护功能实战

    WAF(Web Application Firewall),中文名称叫做“Web应用防火墙 WAF的定义是这样的:Web应用防火墙是通过执行一系列针对HTTP/HTTPS的安全策略来专门为Web应用提 ...

  3. Last-Modified、ETag、Expires和Cache-Control

    前言 在客户端通过浏览器发出第一次请求某一个URL时,根据 HTTP 协议的规定,浏览器会向服务器传送报头(Http Request Header),服务器端响应同时记录相关属性标记(Http Rep ...

  4. 快速理解C#高级概念(一) Delegate委托

    做.NET开发很久,最近重新温习<C#高级编程>一书.发现很多曾经似懂非懂的问题,其实也是能够慢慢钻研慢慢理解的. 所以,打算开写<C#高级编程系列>博文.其中会借鉴<C ...

  5. jquery客户端验证插件

    http://www.cnblogs.com/masing/articles/2157420.html http://www.oschina.net/p/jquery+formvalidator ht ...

  6. 为什么构造器不能是abstract, static, final, native or synchronized的?

    Unlike methods, a constructor cannot be abstract, static, final, native  or synchronized. 1. A const ...

  7. IE6 Must Die

    最近 Twitter 上很多人在推一个名为 IE6 Must Die 的活动, 参与的朋友可以通过头像转换服务在自己的头像上加上一个禁止 IE6 的图标, 很是拉风. Internet Explore ...

  8. 存储过程获取最后插入到数据表里面的ID

    存储过程获取最后插入到数据表里面的ID SET NOCOUNT on;---不返回影响行数提高性能GOcreate proc [sp_bbs_thread_Insert] @id int output ...

  9. angularjs controller的两种写法

    在Angular中,Directive.Service.Filter.Controller都是以工厂方法的方式给出,而工厂方法的参数名对应着该工厂方法依赖的Service.如: app.control ...

  10. activti表结构

    1.结构设计 1.1.    逻辑结构设计 Activiti使用到的表都是ACT_开头的. ACT_RE_*: ’RE’表示repository(存储),RepositoryService接口所操作的 ...