time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the beginning of the line and a closing curved bracket
at the end of the line.

Unfortunately, from time to time Anton would forget writing some letter and write it again. He asks you to count the total number of distinct letters in his set.

Input

The first and the single line contains the set of letters. The length of the line doesn't exceed 1000. It is guaranteed that the line starts from an opening curved bracket and ends with a closing curved bracket. Between them, small English letters are listed,
separated by a comma. Each comma is followed by a space.

Output

Print a single number — the number of distinct letters in Anton's set.

Sample test(s)
input
{a, b, c}
output
3
input
{b, a, b, a}
output
2
input
{}
output
0

解题说明:此题事实上就是考察C++中的set,把输入处理好就可以。

#include<iostream>
#include<cstdio>
#include<cmath>
#include<algorithm>
#include<cstdlib>
#include<cstring>
#include <set>
using namespace std; int main()
{
string s;
set<char> t;
while (cin>>s)
{
if (s[0]!='{')
{
t.insert(s[0]);
}
else if (s[1]!='}')
{
t.insert(s[1]);
}
}
cout<<t.size()<<endl;
return 0;
}

A. Anton and Letters的更多相关文章

  1. cf443A Anton and Letters

    A. Anton and Letters time limit per test 2 seconds memory limit per test 256 megabytes input standar ...

  2. Anton and Letters

    Anton and Letters time limit per test 2 seconds memory limit per test 256 megabytes input standard i ...

  3. Y - Anton and Letters

    Problem description Recently, Anton has found a set. The set consists of small English letters. Anto ...

  4. Codeforces Round #253 (Div. 2) A. Anton and Letters

    题目很简单,只需要注意带空格的输入用getline即可 #include <iostream> #include <vector> #include <algorithm ...

  5. Codeforces Round 253 (Div. 2)

    layout: post title: Codeforces Round 253 (Div. 2) author: "luowentaoaa" catalog: true tags ...

  6. Codeforces Round #379 (Div. 2) A. Anton and Danik 水题

    A. Anton and Danik 题目连接: http://codeforces.com/contest/734/problem/A Description Anton likes to play ...

  7. C - Anton and Danik

    Problem description Anton likes to play chess, and so does his friend Danik. Once they have played n ...

  8. 【77.39%】【codeforces 734A】Anton and Danik

    time limit per test1 second memory limit per test256 megabytes inputstandard input outputstandard ou ...

  9. [LeetCode] Remove Duplicate Letters 移除重复字母

    Given a string which contains only lowercase letters, remove duplicate letters so that every letter ...

随机推荐

  1. LeetCode OJ平台上Maximum Subarray题目O(n)复杂度解决方式

    原始题目例如以下,意为寻找数组和最大的子串,返回这个最大和就可以. Find the contiguous subarray within an array (containing at least ...

  2. java学习笔记day07

    1.throwable下面的子类分为两大类:Error 和 Exception 2.如果方法上有throws Exception,则必须对异常进行处理:  try{    需要检测异常代码     } ...

  3. hdu1106 字符串水题strtok()&&strchr()&&sscanf()+atoi()使用

    字符串的题目 用库函数往往能大大简化代码量 以hdu1106为例 函数介绍 strtok() 原型: char *strtok(char s[], const char *delim); 功能: 分解 ...

  4. UIView--UIImageView

    1.contentMode view.contentMode = UIViewContentModeScaleAspectFill; 2.是否实现触摸 3.简单实现动画 图片的名字为campFire0 ...

  5. iOS 使用自定义的字体

    一.新建一个工程,准备好要使用的字体,后缀为.ttf或者.otf格式. 二.将字体直接拖入工程项目中. 三.在Info.plist中添加一个新的Key:Fonts provided by applic ...

  6. Fedora下用Iptux,中文乱码解决

    Ubuntu/Fedora下用Iptux与Windows下大飞鸽传书,中文乱码解决 问题描述: 在Ubuntu/Fedora下安装了Iptux后,再往Windows机器上发送文件或消息时,如果有中文, ...

  7. Aandroid Error之 新导入工程报Unable to resolve target 'android-18'和R cannot be resolved

    有段时间没有写安卓了,今天导入以前的项目,结果看到控制台打印出了这样一句:Unable to resolve target 'android-18', 解决方法: 项目->属性->Andr ...

  8. nginx,php日志分割

    作者:zhanhailiang 日期:2014-01-06 默认nginx只会生成一个access.log和一个error.log,并且每天不断积累,日志文件会变的非常大,如果需要做一下日志的分析,无 ...

  9. Loader之一:基本原理

    参考APIDEMO及http://developer.android.com/guide/components/loaders.html#app 1.Introduced in Android 3.0 ...

  10. Intent七在属性之一:ComponentName

    注:在<疯狂android讲义>中,此属性称为Component,官方文档中称为ComponentName. 1.The name of the component that should ...