思路:

找规律。参考了http://blog.csdn.net/harlow_cheng/article/details/71190999

实现:

 #include <iostream>
using namespace std;
const int mod = 1e9 + ;
int main()
{
string s;
cin >> s;
int n = s.length();
int cnt = ;
int sum = ;
for (int i = ; i < n; i++)
{
if (s[i] == 'a') cnt = cnt * % mod;
else sum = (sum + cnt - ) % mod;
}
cout << sum << endl;
return ;
}

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