【413】C 语言 Command line
Command-Line Arguments
All the executable programs above have a main(void) program
- more generally, executables take arguments on the command line
- these enter the program via parameters
For example:
prompt$ ./a.out -pre 3
means that:
argc refers to the number of arguments, including the program name
argc = 3
argv[] allows access to arguments represented as strings
argv[0] is a pointer to the string "./a.out"
argv[1] is a pointer to the string "-pre"
argv[2] is a pointer to the string "3"
Command-line argument processing example 1
Write a program that:
- takes an optional numerical command-line argument 1, 2, 3 or 4
- if the argument is not one of these characters (!), a usage message is printed
// commarg.c
#include <stdio.h>
#include <stdlib.h>
int main(int argc, char *argv[]) {
if (argc == 1 ||
(argc == 2 && atoi(argv[1]) >= 1 && atoi(argv[1]) <= 4)) {
// we can do something here
} else {
printf("Usage: %s [1|2|3|4]\n", argv[0]);
}
return EXIT_SUCCESS;
} notice that atoi() had to be called to convert the character to a number
- compiling and executing the program:
prompt$ dcc commarg.c
prompt$ ./a.out
prompt$ ./a.out 1
prompt$ ./a.out 2
prompt$ ./a.out 3
prompt$ ./a.out 4
prompt$ ./a.out 5
Usage: ./a.out [1|2|3|4]
Command-line argument processing example 2
Write a program that:
takes an optional command-line switch -reverse
- if the switch is not correct, a usage message is printed
// commargrev.c
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main(int argc, char *argv[]) {
if (argc == 1 ||
(argc == 2 && !strcmp(argv[1], "-reverse"))) {
// NOTE: strcmp returns 0 if matches.
// we could do something here
} else {
printf("Usage: %s [-reverse]\n", argv[0]);
}
return EXIT_SUCCESS;
}prompt$ ./a.out
prompt$ ./a.out -reverse
prompt$ ./a.out rubbish
Usage: ./a.out [-reverse]
Makefile
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