题意:两个二进制数相加,大数加法的变形

大数加法流程:

1.倒置两个大数,这一步能使所有大数对齐

2.逐位相加,同时进位

3.倒置两个大数的和作为输出

 class Solution {
public:
string addBinary(string a, string b) { if(a.size() < b.size()){
string t = a;
a = b;
b = t;
} //该步使的能大数加小数,使其能加
reverse(a.begin(),a.end());
reverse(b.begin(),b.end());//倒置两数
for(string::size_type i = ; i < a.size(); ++i){
a[i] += ((i < b.size())? b[i] : '') - '';//逐位相加
} for(string::size_type i = ; i < a.size() - ; ++i){
if(a[i] >='' ) {
a[i] -= ;
a[i+] ++;
}
}
if(a[a.size()-] >='' ) {
a[a.size()-] -= ;
a += "";
} //进位
reverse(a.begin(),a.end()); //倒置输出
return a;
}
};

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