python逐行读取替换文件中的字符串

用列表中的值逐行替换文件中符合条件的字符串，并保存为新的文件, open("file").readlines

方案1： 逐行替换并保存为新的文件

import re

def replace_string1():

new_name_list = ["string1", "string11", "string111",...]

# 正则提取

p_s0 = 'def test_TC_(.*?)\('#get accurate String2 at position:def test_TC_String2(

#逐行替换file中String1 with String2
f2 = open("./file_new.py", 'w', encoding='utf-8')
lines = open("./file.py", encoding='utf-8').readlines()

# 逐行查找file中是否包含String2， 找到之后用用列表中的值逐一替换
j = 0
for s in lines:
    casename = re.findall(p_s0, s, re.S) #逐行查找file中是是否包含String2, 找到返回列表["String2"], 否则返回[]
    if (casename):
        while j < len(new_name_list):
            s = s.replace(casename[0],new_name_list[j]) # file 行中包含String2， 则替换成列表中的值
            j += 1 
            break

    f2.write(s)

f2.close()

方案2： 逐行替换并保存文件

import re
def replace_string2():

    with open("./testlistrule.py", 'r+', encoding='utf-8') as f:
        content = f.read()

    # 正则提取
    p_s1 = 'self.case_id = (.*?)\n'
    p_s0 = 'def test_TC_(.*?)\('

    id = re.findall(p_s1, content, re.S)
    casename = re.findall(p_s0, content, re.S)

    new_name_list = []
    for i in range(len(casename)):
        new_casename = casename[i] + "_" + id[i]
        new_name_list.append(new_casename)

    with open("./testlistrule.py", 'r', encoding='utf-8') as f:
        lines = f.readlines()
    j = 0
    content = []
    for s in lines:
        casename = re.findall(p_s0, s, re.S)
        if (casename):
            while j < len(new_name_list):
                s = s.replace(casename[0],new_name_list[j])
                j += 1
                break
        content.append(s)
        with open("./testlistrule.py", 'w+', encoding='utf-8') as f:
            f.write(''.join(content))
    f.close()