Codeforces Round #356 (Div. 2) C
1 second
256 megabytes
standard input
standard output
This is an interactive problem. In the output section below you will see the information about flushing the output.
Bear Limak thinks of some hidden number — an integer from interval [2, 100]. Your task is to say if the hidden number is prime or composite.
Integer x > 1 is called prime if it has exactly two distinct divisors, 1 and x. If integer x > 1 is not prime, it's called composite.
You can ask up to 20 queries about divisors of the hidden number. In each query you should print an integer from interval [2, 100]. The system will answer "yes" if your integer is a divisor of the hidden number. Otherwise, the answer will be "no".
For example, if the hidden number is 14 then the system will answer "yes" only if you print 2, 7 or 14.
When you are done asking queries, print "prime" or "composite" and terminate your program.
You will get the Wrong Answer verdict if you ask more than 20 queries, or if you print an integer not from the range [2, 100]. Also, you will get the Wrong Answer verdict if the printed answer isn't correct.
You will get the Idleness Limit Exceeded verdict if you don't print anything (but you should) or if you forget about flushing the output (more info below).
After each query you should read one string from the input. It will be "yes" if the printed integer is a divisor of the hidden number, and "no" otherwise.
Up to 20 times you can ask a query — print an integer from interval [2, 100] in one line. You have to both print the end-of-line character and flush the output. After flushing you should read a response from the input.
In any moment you can print the answer "prime" or "composite" (without the quotes). After that, flush the output and terminate your program.
To flush you can use (just after printing an integer and end-of-line):
- fflush(stdout) in C++;
- System.out.flush() in Java;
- stdout.flush() in Python;
- flush(output) in Pascal;
- See the documentation for other languages.
Hacking. To hack someone, as the input you should print the hidden number — one integer from the interval [2, 100]. Of course, his/her solution won't be able to read the hidden number from the input.
yes
no
yes
2
80
5
composite
no
yes
no
no
no
58
59
78
78
2
prime
The hidden number in the first query is 30. In a table below you can see a better form of the provided example of the communication process.
The hidden number is divisible by both 2 and 5. Thus, it must be composite. Note that it isn't necessary to know the exact value of the hidden number. In this test, the hidden number is 30.
59 is a divisor of the hidden number. In the interval [2, 100] there is only one number with this divisor. The hidden number must be 59, which is prime. Note that the answer is known even after the second query and you could print it then and terminate. Though, it isn't forbidden to ask unnecessary queries (unless you exceed the limit of 20 queries).
题意:
题解:
#include<iostream>
#include<cstring>
#include<cstdio>
#include<bits/stdc++.h>
#include<algorithm>
#include<queue>
#define ll __int64
using namespace std;
int aa[]={,,,};
int pr[]={,,,,,,,,,,,,,,,,,,,,,,,,};
char a[];
int x,y=;
int n=,z,i,t=;
int main()
{
for(i=;i<;i++)
{
printf("%d\n",pr[i]);
fflush(stdout);
scanf("%s",a);
if(strcmp(a,"yes")==)
y++;
else
n++;
if(y>=)
break;
}
for(i=;i<;i++)
{
printf("%d\n",aa[i]);
fflush(stdout);
scanf("%s",a);
if(strcmp(a,"yes")==)
y++;
else
n++;
if(y>=)
break;
}
if(y>=)
{
printf("composite\n");
fflush(stdout);
}
else
{
printf("prime\n");
fflush(stdout);
}
return ;
}
Codeforces Round #356 (Div. 2) C的更多相关文章
- Codeforces Round #356 (Div. 2)-B
B. Bear and Finding Criminals 链接:http://codeforces.com/contest/680/problem/B There are n cities in B ...
- Codeforces Round #356 (Div. 2)-A
A. Bear and Five Cards 题目链接:http://codeforces.com/contest/680/problem/A A little bear Limak plays a ...
- Codeforces Round #356 (Div. 2) C. Bear and Prime 100(转)
C. Bear and Prime 100 time limit per test 1 second memory limit per test 256 megabytes input standar ...
- Codeforces Round #356 (Div. 2)B. Bear and Finding Criminals(水题)
B. Bear and Finding Criminals time limit per test 2 seconds memory limit per test 256 megabytes inpu ...
- Codeforces Round #356 (Div. 2)A. Bear and Five Cards(简单模拟)
A. Bear and Five Cards time limit per test 2 seconds memory limit per test 256 megabytes input stand ...
- 并查集+bfs+暴力滑窗 Codeforces Round #356 (Div. 2) E
http://codeforces.com/contest/680/problem/E 题目大意:给你一个n*n的图,然后图上的 . (我们下面都叫做‘点’)表示可以走,X表示不能走,你有如下的操作, ...
- dfs Codeforces Round #356 (Div. 2) D
http://codeforces.com/contest/680/problem/D 题目大意:给你一个大小为X的空间(X<=m),在该空间内,我们要尽量的放一个体积为a*a*a的立方体,且每 ...
- Codeforces Round #356 (Div. 1) D. Bear and Chase 暴力
D. Bear and Chase 题目连接: http://codeforces.com/contest/679/problem/D Description Bearland has n citie ...
- Codeforces Round #356 (Div. 2) E. Bear and Square Grid 滑块
E. Bear and Square Grid 题目连接: http://www.codeforces.com/contest/680/problem/E Description You have a ...
- Codeforces Round #356 (Div. 2) D. Bear and Tower of Cubes dfs
D. Bear and Tower of Cubes 题目连接: http://www.codeforces.com/contest/680/problem/D Description Limak i ...
随机推荐
- java 动态生成SQL
代码如下: /** * 动态生成SQ及SQL参数L * @param ve 接收到的消息的CHGLIST * @param paramList MQ消息中的SQL参数 * @param t 泛型对象 ...
- webstorm报错Unescaped xml character解决方案1
当idea认为你的书写格式不适合的时候便会报出Unescaped xml character提示,但不影响运行. 若想禁掉这个提示,可以尝试修改文档类型为:<!DOCTYPE html>
- 我的Hibernate学习
以下博客均为引用, 侵删 Hibernate初级 HQL和SQL的区别 https://blog.csdn.net/aaa1117a8w5s6d/article/details/7757097 ...
- Flask初学者:视图函数/方法返回值(HTML模板/Response对象)
返回HTML模板:使用“from flask import render_template”,在函数中传入相对于文件夹“templates”HTML模板路径名称字符串即可(默认模板路径),flask会 ...
- DNS无法区域传送(axfr,ixfr)
这两天博主在学习dns服务器的配 首先简单介绍一下axfr,ixfr axfr:完全区域传送 ixfr :增量区域传送 主要是在dns主从服务器上面进行备份更新的. ----------------- ...
- 文档-linux io模式及select,poll,epoll
文档-Linux IO模式详解 1. 概念说明 在进行解释之前,首先要说明几个概念:- 用户空间和内核空间- 进程切换- 进程的阻塞- 文件描述符- 缓存 I/O 1.1 用户空间与内核空间 现在操作 ...
- hihocoder1014 : Trie树
#1014 : Trie树 时间限制:10000ms 单点时限:1000ms 内存限制:256MB 描述 小Hi和小Ho是一对好朋友,出生在信息化社会的他们对编程产生了莫大的兴趣,他们约定好互相帮助, ...
- 解决不了bug的时候看一下:
解决不了bug的时候看一下: 1.机器是不会出错的,出错的一定是人.只是你还没有意识到哪里出了错. 2.产生bug 的原因想错了,你以为是系统的bug ,那么你肯定就不想着去解决,你也就解决不了. 这 ...
- 剑指Offer - 九度1385 - 重建二叉树
剑指Offer - 九度1385 - 重建二叉树2013-11-23 23:53 题目描述: 输入某二叉树的前序遍历和中序遍历的结果,请重建出该二叉树.假设输入的前序遍历和中序遍历的结果中都不含重复的 ...
- node express 登录拦截器 request接口请求
1.拦截器 拦截器可以根据需要 做权限拦截 登录只是权限的一种, 思路是req.session.user判断用户session是否存在,是否是需要拦截的地址, 如果是就跳转登录页,或其他页, 如果非需 ...