POJ1013Counterfeit Dollar

这个题主要是判断硬币真假，可能轻可能重，称三次，要输出哪枚是假币，还要输出是重的还是轻的，所以最主要的是标记变量

 #include<cstdio>
 #include<cstring>
 #include<cmath>
 #include<iostream>
 using namespace std ;

 int main()
 {
     int n ;
     while(cin>>n )
     {
         int a['L'+] ;
         for(int k =  ; k <= n ; k++)
         {
             memset(a,,sizeof(a)) ;  //没被标记
             char ch[],sh[] ,ju[];
             for(int j =  ; j <=  ; j++)
             {
                 cin>>ch>>sh>>ju;
                 if(strcmp(ju,"even")==)
                 {
                     for(int i =  ; i <  strlen(ch) ; i++)
                     {
                         a[ch[i]] =  ;//绝对真币为-1
                         a[sh[i]] =  ;
                     }
                 }
                 else if(strcmp(ju,"up") == )
                 {
                     for(int i =  ; i < strlen(ch) ; i++)
                     {
                         if(a[ch[i]] != )
                             a[ch[i]]++;//
                         if(a[sh[i]] != )
                             a[sh[i]]-- ;
                     }
                 }
                 else if(strcmp(ju,"down") == )
                 {
                     for(int i =  ; i < strlen(ch) ; i++)
                     {
                         if(a[ch[i]] != )
                             a[ch[i]] --;
                         if(a[sh[i]] != )
                             a[sh[i]]++ ;
                     }
                 }
             }
             int max =  ;
             char count ;
             for(int j = 'A' ; j <= 'L' ; j++)
             {
                 if(a[j] == )
                     continue ;
                 if( fabs(a[j]) >= max)
                 {
                     max = fabs(a[j]) ;
                     count = j ;
                 }
             }
             cout<<count<< " is the counterfeit coin and it is ";
             if(a[count] > )
                 cout<<"heavy."<<endl ;
             else
                 cout<< "light."<<endl ;
         }
     }
     return  ;
 }