HD-ACM算法专攻系列（3）——Least Common Multiple

题目描述：

源码：

/**/
#include"iostream"
using namespace std;

int MinComMultiple(int n, int m)
{
	int x, y, tmp;
	long long s;
	s = (long long)n * (long long)m;//避免int的乘积越界
	if(n > m)
	{
		tmp = n;
		n = m;
		m = tmp;
	}
	tmp = m % n;
	while(tmp != 0)
	{
		m = n;
		n = tmp;
		tmp = m % n;
	}
	return s / n;
}

int main()
{
	int n, m, result;
	int *p;
	cin>>n;
	for(int i = 0; i < n; i++)
	{
		cin>>m;
		p = new int[m];
		for(int j = 0; j < m; j++)cin>>p[j];
		result = p[0];
		for(int j = 1; j < m; j++)
		{
			result = MinComMultiple(result, p[j]);
		}
		cout<<result<<endl;
	}
    return 0;
}