Python练习-函数版-锁定三次登陆失败的用户

代码如下:

 # 编辑者：闫龙
 if __name__ == '__main__':
     import UserLoginFuncation

 LoclCount=[];
 while True:
     UserName = input("用户名:>>")
     if(UserLoginFuncation.CheckUserLock(UserName)):
         print("用户",UserName,"已被锁定")
         continue
     PassWd = input("密  码:>>")
     if(UserLoginFuncation.UserInfo(UserName,PassWd)):
         print("欢迎",UserName,"登陆")
         break
     else:
         LoclCount.append(UserName);
         print("用户名或密码错误,您还有",3-LoclCount.count(UserName),"次尝试机会")
     if(LoclCount.count(UserName) == 3):
         UserLoginFuncation.LockUser(UserName)
         print("对不起,尝试次数过多",UserName,"用户已被锁定")

用户登录程序流程控制代码

 # 编辑者：闫龙
 import os
 def CheckUserLock(UserName):
     if(os.path.exists("LockUser")):
         with open("LockUser","r",encoding="utf8") as ReadLock:
             p = ReadLock.readline().split(",")
             if(p.count(UserName) != 0):
                 return True

 def LockUser(UserName):
     if(os.path.exists("LockUser")):
         LockFile = open("LockUser", "a", encoding="utf8")
         LockFile.write(UserName+",")
         LockFile.close()
     else:
         LockFile = open("LockUser", "w", encoding="utf8")
         LockFile.write(UserName+",")
         LockFile.close()

 def UserInfo(UserName,PassWd):
     with open("UserInfo",mode="r",encoding="utf8") as userinfo:
         p =  userinfo.readlines()
         for i in p:
             i= i.strip().split(":")
             if(i[0] == UserName and i[1] == PassWd):
                 return True
             else:
                 continue
         return False

用户登录程序调用函数

egon:123
alex:321
long:666

用户登录文件(UserInfo)