北大poj- 1008
| Time Limit: 1000MS | Memory Limit: 10000K | |
| Total Submissions: 80956 | Accepted: 24892 |
Description
For religious purposes, the Maya used another calendar in which the
year was called Tzolkin (holly year). The year was divided into thirteen
periods, each 20 days long. Each day was denoted by a pair consisting
of a number and the name of the day. They used 20 names: imix, ik,
akbal, kan, chicchan, cimi, manik, lamat, muluk, ok, chuen, eb, ben, ix,
mem, cib, caban, eznab, canac, ahau and 13 numbers; both in cycles.
Notice that each day has an unambiguous description. For example, at
the beginning of the year the days were described as follows:
1 imix, 2 ik, 3 akbal, 4 kan, 5 chicchan, 6 cimi, 7 manik, 8 lamat, 9
muluk, 10 ok, 11 chuen, 12 eb, 13 ben, 1 ix, 2 mem, 3 cib, 4 caban, 5
eznab, 6 canac, 7 ahau, and again in the next period 8 imix, 9 ik, 10
akbal . . .
Years (both Haab and Tzolkin) were denoted by numbers 0, 1, : : : ,
where the number 0 was the beginning of the world. Thus, the first day
was:
Haab: 0. pop 0
Tzolkin: 1 imix 0
Help professor M. A. Ya and write a program for him to convert the dates from the Haab calendar to the Tzolkin calendar.
Input
NumberOfTheDay. Month Year
The first line of the input file contains the number of the input
dates in the file. The next n lines contain n dates in the Haab calendar
format, each in separate line. The year is smaller then 5000.
Output
Number NameOfTheDay Year
The first line of the output file contains the number of the output
dates. In the next n lines, there are dates in the Tzolkin calendar
format, in the order corresponding to the input dates.
Sample Input
3
10. zac 0
0. pop 0
10. zac 1995
Sample Output
3
3 chuen 0
1 imix 0
9 cimi 2801 分析:题目很简单,做简单hash表处理就可以0ms了。
#include <stdio.h>
#include <stdlib.h> #define INPUT_BUF_SIZE 10000 typedef struct
{
int day;
int month;
int year;
}Haab; typedef struct
{
int haabNum;
Haab haab[INPUT_BUF_SIZE];
}HaabYears; HaabYears g_haabYears; int g_haabHash[]; char g_tzolkinDay[][] =
{
"imix\0", "ik\0", "akbal\0", "kan\0", "chicchan\0",
"cimi\0", "manik\0", "lamat\0", "muluk\0", "ok\0",
"chuen\0", "eb\0", "ben\0", "ix\0", "mem\0",
"cib\0", "caban\0", "eznab\0", "canac\0", "ahau\0"
}; void InitHash(int *haabHash)
{
haabHash[] = ;
haabHash[] = ;
haabHash[] = ;
haabHash[] = ;
haabHash[] = ;
haabHash[] = ;
haabHash[] = ;
haabHash[] = ;
haabHash[] = ;
haabHash[] = ;
haabHash[] = ;
haabHash[] = ;
haabHash[] = ;
haabHash[] = ;
haabHash[] = ;
haabHash[] = ;
haabHash[] = ;
haabHash[] = ;
haabHash[] = ;
} void GetHaab(HaabYears *years)
{
int i = ;
char tmp;
int hashValue;
scanf("%d", &years->haabNum); for(i = ; i < years->haabNum; i++)
{
hashValue = ;
scanf("%d", &years->haab[i].day);
getchar();
getchar();
while((tmp = getchar()) >= 'a')
{
hashValue += tmp;
}
years->haab[i].month = g_haabHash[hashValue];
scanf("%d", &years->haab[i].year);
getchar();
}
} void printTzolkin(HaabYears *years)
{
int i;
long totalDay;
int year, leftDay, num, day;
printf("%d\n", years->haabNum);
for(i = ; i < years->haabNum; i++)
{
totalDay = years->haab[i].year * + years->haab[i].month * + years->haab[i].day;
year = (int)totalDay/;
leftDay = totalDay%;
num = leftDay% + ;
day = leftDay%;
printf("%d %s %d\n", num, g_tzolkinDay[day], year);
}
} int main()
{
InitHash(g_haabHash);
GetHaab(&g_haabYears);
printTzolkin(&g_haabYears);
return ;
}
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