http://poj.org/problem?id=3461

Oulipo
Time Limit: 1000MS   Memory Limit: 65536K
Total Submissions: 41051   Accepted: 16547

Description

The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a member of the Oulipo group. A quote from the book:

Tout avait Pair normal, mais tout s’affirmait faux. Tout avait Fair normal, d’abord, puis surgissait l’inhumain, l’affolant. Il aurait voulu savoir où s’articulait l’association qui l’unissait au roman : stir son tapis, assaillant à tout instant son imagination, l’intuition d’un tabou, la vision d’un mal obscur, d’un quoi vacant, d’un non-dit : la vision, l’avision d’un oubli commandant tout, où s’abolissait la raison : tout avait l’air normal mais…

Perec would probably have scored high (or rather, low) in the following contest. People are asked to write a perhaps even meaningful text on some subject with as few occurrences of a given “word” as possible. Our task is to provide the jury with a program that counts these occurrences, in order to obtain a ranking of the competitors. These competitors often write very long texts with nonsense meaning; a sequence of 500,000 consecutive 'T's is not unusual. And they never use spaces.

So we want to quickly find out how often a word, i.e., a given string, occurs in a text. More formally: given the alphabet {'A', 'B', 'C', …, 'Z'} and two finite strings over that alphabet, a word W and a text T, count the number of occurrences of W in T. All the consecutive characters of W must exactly match consecutive characters of T. Occurrences may overlap.

Input

The first line of the input file contains a single number: the number of test cases to follow. Each test case has the following format:

  • One line with the word W, a string over {'A', 'B', 'C', …, 'Z'}, with 1 ≤ |W| ≤ 10,000 (here |W| denotes the length of the string W).
  • One line with the text T, a string over {'A', 'B', 'C', …, 'Z'}, with |W| ≤ |T| ≤ 1,000,000.

Output

For every test case in the input file, the output should contain a single number, on a single line: the number of occurrences of the word W in the text T.

Sample Input

3
BAPC
BAPC
AZA
AZAZAZA
VERDI
AVERDXIVYERDIAN

Sample Output

1
3
0
KMP模板题
#include <iostream>
#include <cstdio>
#include <cstring>
#include <queue>
#include <cmath>
#include <vector>
#include <set>
#include <map>
#include <algorithm>
using namespace std;
typedef long long ll;
int nex[];
char s[],p[];
void get_next(char *s)
{
nex[]=-;
int i=,k=-;
int len=strlen(s);
while(i<len)
{
if(k==- || p[i]==p[k])
{
i++;
k++;
nex[i]=k;
}
else k=nex[k];
}
}
void kmp(char *s,char *p)
{
int ans=;
get_next(s);
int len=strlen(p);
int i=,j=;
while(i<len)
{
if(j==- || p[i]==s[j])
{
i++;
j++;
}
else j=nex[j];
if(j==strlen(s)) ans++;
}
printf("%d\n",ans);
}
int main()
{
int n;
scanf("%d",&n);
while(n--)
{
scanf("%s%s",s,p);
kmp(s,p);
}
return ;
}
 

POJ Oulipo KMP 模板题的更多相关文章

  1. POJ Oulipo(KMP模板题)

    题意:找出模板在文本串中出现的次数 思路:KMP模板题 #include<cstdio> #include<cstring> #include<cmath> #in ...

  2. HDU 1686 - Oulipo - [KMP模板题]

    题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1686 Time Limit: 3000/1000 MS (Java/Others) Memory Li ...

  3. poj3461 Oulipo (KMP模板题~) 前面哪些也是模板题 O.O

    # include <stdio.h> # include <algorithm> # include <string.h> using namespace std ...

  4. HDU 1711 - Number Sequence - [KMP模板题]

    题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1711 Time Limit: 10000/5000 MS (Java/Others) Memory L ...

  5. POJ:3461-Oulipo(KMP模板题)

    原题传送:http://poj.org/problem?id=3461 Oulipo Time Limit: 1000MS Memory Limit: 65536K Description The F ...

  6. Number Sequence - HDU 1711(KMP模板题)

    题意:给你一个a串和一个b串,问b串是否是a串的子串,如果是返回b在a中最早出现的位置,否则输出-1   分析:应该是最简单的模板题了吧..... 代码如下: ==================== ...

  7. hdu 1711 Number Sequence(KMP模板题)

    我的第一道KMP. 把两个数列分别当成KMP算法中的模式串和目标串,这道题就变成了一个KMP算法模板题. #include<stdio.h> #include<string.h> ...

  8. HDU 1711Number Sequence【KMP模板题】

    <题目链接> 题目大意: 意思是给出两个串,找出匹配串在模式串中的位置. 解题分析: KMP算法模板题. #include <cstdio> #include <cstr ...

  9. (模板)poj3461(kmp模板题)

    题目链接:https://vjudge.net/problem/POJ-3461 题意:给出主串和模式串,求出模式串在主串中出现的次数. 思路:kmp板子题. AC代码: #include<cs ...

随机推荐

  1. HTTP——学习笔记(3)

    HTTP报文:用于HTTP协议交互的信息,客户端的HTTP报文叫做 请求报文,响应端的叫做 响应报文 本质:是由多行(用CR+LF作换行符)数据构成的字符串文本 注:CR:回车,打印针回到行首   L ...

  2. redis为什么选择单线程工作模型

    1.先说一下为什么出现进程,线程 进程:在计算机发明之初就发现,在输入数据时(I/O速度慢),CPU是空闲的,这样就浪费了CPU资源,为了充分利用CPU资源,发明了进程,在输入程序A的数据时,程序B在 ...

  3. Memcached 集群环境Java客户端

    Memcached 集群环境Java客户端 学习了: http://blog.csdn.net/zhouzhiwengang/article/details/53154112 http://guazi ...

  4. 大海教你学手游2015CocosLua第一季_00课程介绍

    话说大盘从5100直掉到3500点,千仅仅股票跌幅超过20%,跌跌不休.散户.证监会.做空机构開始斗气地主来了: 散户:叫地主 空头:抢地主,3分 证监会:pass 空头:压死 证监会:不要 散户:不 ...

  5. spark groupByKey 也是可以filter的

    >>> v=sc.parallelize(["one", "two", "two", "three", ...

  6. Nginx下部署TP5项目

    标签(空格分隔): linux nginx配置文件: server { listen 81; #listen [::]:80; server_name _; index index.html inde ...

  7. P1452 Beauty Contes(旋转卡壳版)

    题目背景 此处省略1W字^ ^ 题目描述 贝茜在牛的选美比赛中赢得了冠军”牛世界小姐”.因此,贝西会参观N(2 < = N < = 50000)个农场来传播善意.世界将被表示成一个二维平面 ...

  8. bootstrap-treeview简单使用

    废话不多说,直接上干干货. 1.bootstrap-treeview Github网址:https://github.com/jonmiles/bootstrap-treeview 2.使用要求: & ...

  9. 《剑指offer》栈的压入、弹出序列

    一.题目描述 输入两个整数序列,第一个序列表示栈的压入顺序,请判断第二个序列是否为该栈的弹出顺序.假设压入栈的所有数字均不相等.例如序列1,2,3,4,5是某栈的压入顺序,序列4,5,3,2,1是该压 ...

  10. redis动态修改参数

    通过 config get 命令可以查看参数. 通过config set 可以修改某些参数 动态关闭redis的aof功能:(不要忘了也修改配置文件中的aof选项使其保持一致) 127.0.0.1:6 ...