[LeetCode OJ] Max Points on a Line
Submission Details
|
27 / 27 test cases passed.
|
Status:
Accepted |
|
Runtime: 472 ms
|
Submitted: 0 minutes ago
|
Submitted Code
/**
* Definition for a point.
* class Point {
* int x;
* int y;
* Point() { x = 0; y = 0; }
* Point(int a, int b) { x = a; y = b; }
* }
*/
import java.util.HashMap;
import java.util.Map; public class Solution {
public int maxPoints(Point[] points) {
if (points == null || points.length == 0)
return 0;
int N = points.length;
if (N == 1)
return 1;
if (N == 2)
return 2; Map<String, Integer> dict = new HashMap<String, Integer>();
int maxOverall = 0;
for (int i = 0; i < N - 1; i++) {
int same = 1;
int max = 0;
for (int j = i + 1; j < N; j++) { int p1x = points[i].x;
int p1y = points[i].y;
int p2x = points[j].x;
int p2y = points[j].y; if (p1x == p2x && p1y == p2y) {
same++;
continue;
} int A = p2y - p1y;
int B = p1x - p2x; int GCD = gcd(A, B);
if (GCD != 0 && GCD != 1) {
A /= GCD;
B /= GCD;
}
if (A < 0) {
A = -A;
B = -B;
} String key = A + "," + B;
// System.out.println("round:" + i + " " + key);
int value = 1;
if (dict.containsKey(key)) {
value += dict.get(key);
}
dict.put(key, value);
max = max < value ? value : max;
} max += same;
maxOverall = maxOverall < max ? max : maxOverall;
dict.clear();
} return maxOverall;
} public int gcd(int a, int b) {
if (b == 0)
return a;
return gcd(b, a % b);
}
}
[LeetCode OJ] Max Points on a Line的更多相关文章
- [LeetCode OJ] Max Points on a Line—Given n points on a 2D plane, find the maximum number of points that lie on the same straight line.
//定义二维平面上的点struct Point { int x; int y; Point(, ):x(a),y(b){} }; bool operator==(const Point& le ...
- 【leetcode】Max Points on a Line
Max Points on a Line 题目描述: Given n points on a 2D plane, find the maximum number of points that lie ...
- [leetcode]149. Max Points on a Line多点共线
Given n points on a 2D plane, find the maximum number of points that lie on the same straight line. ...
- [LeetCode] 149. Max Points on a Line 共线点个数
Given n points on a 2D plane, find the maximum number of points that lie on the same straight line. ...
- 【leetcode】Max Points on a Line(hard)☆
Given n points on a 2D plane, find the maximum number of points that lie on the same straight line. ...
- Java for LeetCode 149 Max Points on a Line
Given n points on a 2D plane, find the maximum number of points that lie on the same straight line. ...
- leetcode 149. Max Points on a Line --------- java
Given n points on a 2D plane, find the maximum number of points that lie on the same straight line. ...
- LeetCode之Max Points on a Line Total
1.问题描述 Given n points on a 2D plane, find the maximum number of points that lie on the same straight ...
- leetcode[149]Max Points on a Line
Given n points on a 2D plane, find the maximum number of points that lie on the same straight line. ...
随机推荐
- 简单的射击游戏HTML+JS实现
一直想自己写一个游戏玩,时间和精力都不太允许,最近几天刚好有空闲时间,就琢磨了这个小游戏. 刚开始想着计算图片重叠事件,然后让炮弹和飞机消失,傻乎乎写了一天,越整越乱.今天一大早晕过来了,改用数组以后 ...
- WinForm DataGridView根据选中的行多删
private void btndel_Click(object sender, EventArgs e) { int count = 0; ...
- LintCode Find Minimum In Rotated Sorted Array
1. 画图, 直观. 2. 讨论数组为空或者个数为零. 3. 讨论首尾, 若为翻转过的则进行查找直到最后两个数进行比较, 取小者. public class Solution { /** * @par ...
- HackerRank-Longest Subarray
give an array and target value, find the max length of the subarray which sum of the elements is les ...
- PHP 类中的魔术方法
定义: PHP类中以两个下画线“__”开头的方法被称为魔术方法. 分类: 例如:构造方法:__construct:析构方法:__destruct:动态重载:__set().__get().__call ...
- HTML5画布实现方法:
我们可以在HTML中使用属性width和height来定义Canvas.但是实现Canvas的相关功能主要还依赖于Javascript实现,即HTML5 Canvas API.我们使用javascri ...
- java中的集合类(Collection)中的Set
set集合不包含重复元素及与我们无关的排序!我说hibernate实体类中的集合都用Set呢,难道是因为这个?
- android studio入门
目前的工作是蓝牙相关的,所以最近心血来潮想折腾下Android开发,方便调试自己的固件, 装好Android Studio跟SDK之后,感谢nordic的公开代码,研究了一会,感觉并没有多费劲 相关的 ...
- 安装恢复Windows10各种坑
1.安装Windows10最好用微软原装ISO,其它的第三方坑比较多,要么不支持UEFI,要么不支持MBR,要么不支持GPT. 2.恢复系统可以使用WIM备份,或Window原生备份,或者Ghost备 ...
- 提供VR定制开发、AR定制开发(VR游戏定制、应用定制)
设置输出路径 添加烘培输出的贴图类型 添加“LightingMap”类型 设置烘培贴图大小和目标贴图位置为“自发光” 设置烘培材质,选择“输出到源” 点击“渲染”即可 24.标准材质贴图的烘培光影处理 ...