题意:一棵n个结点的完全二叉树,初始i号结点的权值为i。有两种操作:单点修改;询问经过某个结点的路径中,权值和最大的路径的权值和是多少。

修改的时候,暴力修改到根节点的路径上的点的f(x)即可。

跟虚树的思想只是有点点像而已,实际上不是一个东西啦。

队友的代码:

#include <cmath>
#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm>
using namespace std; struct nod{
int lx,d;
long long c;
}q[110000]; struct nod2{
int sum[40],s[40],l;
}ceng;
int ls[2800000],i,n,m,all,wei[40];
long long t[2800000],v[2800000];
char s[100]; int fen(int a)
{
if (a==0) return 0;
int l=1,r=all,mid;
while (l!=r)
{
mid=(l+r)/2;
if (ls[mid]>=a) r=mid; else l=mid+1;
}
return l;
} void add(int a)
{
while (a)
{
ls[++all]=a;
a=a/2;
}
} void quchong()
{
int l,r,now=0;
l=1;
while (l<=all)
{
r=l;
while (r<=all && ls[l]==ls[r]) r++;
ls[++now]=ls[l];
l=r;
}
all=now;
} long long getv(int d)
{
if (d>n) return 0;
int k=fen(d),c,y,ans;
if (ls[k]==d) return t[k];
y=d; c=0;
while (y!=0)
{
c++;
y=y/2;
}
if (d==ceng.s[c]) return ceng.sum[c];
ans=0; y=d;
while (y<=n)
{
ans+=y;
y=y*2+1;
}
return ans; } void modify(int d,long long a)
{
d=fen(d); v[d]=a;
while (d!=0)
{
t[d]=max(getv(ls[d]*2),getv(ls[d]*2+1))+v[d];
d=fen(ls[d]/2);
}
} void getceng(int d)
{
int i;
ceng.l=0;
while (d)
{
ceng.s[++ceng.l]=d;
d=d/2;
}
for (i=1;i<=ceng.l/2;i++) swap(ceng.s[i],ceng.s[ceng.l-i+1]);
ceng.sum[ceng.l]=ceng.s[ceng.l];
for (i=ceng.l-1;i>=1;i--) ceng.sum[i]=ceng.s[i]+ceng.sum[i+1];
} long long getans(int d)
{
long long ans,p,sum=0;
int pre;
d=fen(d); p=t[d];
ans=getv(ls[d]*2)+getv(ls[d]*2+1)+v[d];
pre=d; d=fen(ls[d]/2);
while (d)
{
sum+=v[d];
if (ls[d]*2==ls[pre]) ans=max(ans,p+sum+getv(ls[d]*2+1)); else ans=max(ans,p+sum+getv(ls[d]*2));
pre=d;
d=fen(ls[d]/2);
}
return ans;
} void chushi()
{
int i;
for (i=all;i>=1;i--)
{
v[i]=ls[i];
t[i]=max(getv(ls[i]*2),getv(ls[i]*2+1))+v[i];
}
} int main()
{
wei[0]=1;
for (i=1;i<=30;i++) wei[i]=wei[i-1]*2;
while (scanf("%d%d",&n,&m)!=EOF)
{
all=0;
getceng(n);
for (i=1;i<=m;i++)
{
scanf("%s",&s);
if (s[0]=='q')
{
scanf("%d",&q[i].d);
q[i].lx=0;
}
if (s[0]=='c')
{
scanf("%d%lld",&q[i].d,&q[i].c);
q[i].lx=1;
}
add(q[i].d);
}
sort(ls+1,ls+all+1);
quchong();
chushi();
for (i=1;i<=m;i++)
{
if (q[i].lx==1) modify(q[i].d,q[i].c);
if (q[i].lx==0) printf("%lld\n",getans(q[i].d));
}
}
}

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