CF 332A Down the Hatch! 超级水题。。不过题目太长了
2 seconds
256 megabytes
standard input
standard output
Everybody knows that the Berland citizens are keen on health, especially students. Berland students are so tough that all they drink is orange juice!
Yesterday one student, Vasya and his mates made some barbecue and they drank this healthy drink only. After they ran out of the first barrel of juice, they decided to play a simple game. All n people who came to the barbecue sat in a circle (thus each person received a unique index bi from 0 to n - 1). The person number 0 started the game (this time it was Vasya). All turns in the game were numbered by integers starting from 1. If the j-th turn was made by the person with index bi, then this person acted like that:
- he pointed at the person with index (bi + 1) mod n either with an elbow or with a nod (x mod y is the remainder after dividing x byy);
- if j ≥ 4 and the players who had turns number j - 1, j - 2, j - 3, made during their turns the same moves as player bi on the current turn, then he had drunk a glass of juice;
- the turn went to person number (bi + 1) mod n.
The person who was pointed on the last turn did not make any actions.
The problem was, Vasya's drunk too much juice and can't remember the goal of the game. However, Vasya's got the recorded sequence of all the participants' actions (including himself). Now Vasya wants to find out the maximum amount of juice he could drink if he played optimally well (the other players' actions do not change). Help him.
You can assume that in any scenario, there is enough juice for everybody.
The first line contains a single integer n (4 ≤ n ≤ 2000) — the number of participants in the game. The second line describes the actual game: the i-th character of this line equals 'a', if the participant who moved i-th pointed at the next person with his elbow, and 'b', if the participant pointed with a nod. The game continued for at least 1 and at most 2000 turns.
Print a single integer — the number of glasses of juice Vasya could have drunk if he had played optimally well.
4
abbba
1
4
abbab
0
In both samples Vasya has got two turns — 1 and 5. In the first sample, Vasya could have drunk a glass of juice during the fifth turn if he had pointed at the next person with a nod. In this case, the sequence of moves would look like "abbbb". In the second sample Vasya wouldn't drink a single glass of juice as the moves performed during turns 3 and 4 are different.
题目意思 就是改变Vasya的行动,使他能喝更多酒。 就是看他左边3人是不是字母相同。。因为n>=4。。所以什么都不用考虑了。。
因为Vasya是从0开始的。而且j>=4时才有行动。。所以初始时直接从n开始计数
因为题目太水了。。我决定贴python代码
#!/usr/bin/python
n=input()
s=raw_input()
v,t=n,0
while v < len(s):
if s[v-3]==s[v-2]==s[v-1]:t+=1
v+=n
print t
CF 332A Down the Hatch! 超级水题。。不过题目太长了的更多相关文章
- CF 1008B Turn the Rectangles(水题+贪心)
There are n rectangles in a row. You can either turn each rectangle by 90 degrees or leave it as it ...
- POJ 2017 No Brainer(超级水题)
一.Description Zombies love to eat brains. Yum. Input The first line contains a single integer n indi ...
- CF 1042A Benches——二分答案(水题)
题目:http://codeforces.com/problemset/problem/1042/A #include<iostream> #include<cstdio> # ...
- CF 1042 A Benches —— 二分答案(水题)
题目:http://codeforces.com/problemset/problem/1042/A 代码如下: #include<iostream> #include<cstdio ...
- SRM 584 第一次玩TopCoder。。。只水题一道。。。
第一次topcoder,以前老感觉没有资格去做tc,cf什么的,现在已经慢慢接触了. 感觉还可以,还是有让我们这些蒻菜安慰的水题. tc的确很好玩,用客户端比赛,还有各种规则,而且还是只编写一个类提交 ...
- Acdream 1111:LSS(水题,字符串处理)
LSS Time Limit: 20000/10000 MS (Java/Others) Memory Limit: 128000/64000 KB (Java/Others) SubmitStati ...
- Poj1298_The Hardest Problem Ever(水题)
一.Description Julius Caesar lived in a time of danger and intrigue. The hardest situation Caesar eve ...
- 11.07图论水题Test
11.07图论水题Test 题目 描述 做法 \(BSOJ6378\) 在\(i\)位置可以到\(i+a_i\)或\(i+b_i\)求\(1\rightarrow n\)字典序最小路径 判可达性后贪心 ...
- 11.06水题Test
11.06水题比赛 题目 描述 做法 \(BSOJ5150\) 求\(n\)个数两两之差的中位数 二分中位数,双指针判定\(\le x\)差值对数 \(BSOJ5151\) 求树的最大匹配和其个数 来 ...
随机推荐
- CSS3 制作向左、向右及关闭图标的效果
先看一下效果 1.鼠标移入前的效果 2.鼠标移入的效果 3.制作步骤如下: 轮廓的CSS,就是利用圆角和宽度高度,制作出一个圆: <style> /*显示方式为 inline-block* ...
- C++外观设计模式模式(三)
3.外观模式总结 引入了外观类.解除了客户类与子系统的耦合性.客户类不须要直接操作子系统,而是由外观类负责处理,对client而言是透明的,客户类仅仅须要操作外观类就能够了,符合"迪迷特法则 ...
- JS怎样将拖拉事件与点击事件分离?
帖子:http://bbs.csdn.net/topics/390785395?page=1#post-397369340 怎样将拖拉事件跟点击事件分离? 须要做到:拖拉时不触动点击事件 <ht ...
- asp.net mvc3 的数据验证(一)
原文:asp.net mvc3 的数据验证(一) 对于web开发人员来说,对用户输入的信息进行验证是一个重要但是繁琐的工作,而且很多开发者都会忽略.asp.net mvc3框架使用的是叫做“ ...
- Struts2和Struts1的主要区别(完整版)
Struts1和Struts2的区别和对比: Action 类: • Struts1要求Action类继承一个抽象基类.Struts1的一个普遍问题是使用抽象类编程而不是接口,而struts2的Act ...
- Milo的游戏开发的一些链接资料
http://www.cnblogs.com/miloyip/default.aspx?page=1 http://www.cnblogs.com/miloyip/archive/2010/06/14 ...
- 清除css、javascript及背景图在浏览器中的缓存
在实际项目开发过过程中,页面是上传到服务器上的.而为了减少服务器的压力,让用户少加载,浏览器会将图片.css.js缓存到本地中,以便下次访问网站时使用.这样做不仅减少了服务器的压力,并且也减少了用户的 ...
- POJ 2553 The Bottom of a Graph (强连通分量)
题目地址:POJ 2553 题目意思不好理解.题意是:G图中从v可达的全部点w,也都能够达到v,这种v称为sink.然后升序输出全部的sink. 对于一个强连通分量来说,全部的点都符合这一条件,可是假 ...
- Model和Entity Framework
Model和Entity Framework 上一节:ASP.NET MVC 5 入门教程 (4) View和ViewBag 下一节:ASP.NET MVC5 + EF6 入门教程 (6) View中 ...
- C# 对Outlook联系人的增、删、查
原文:C# 对Outlook联系人的增.删.查 [转] 注:定义变量 Outlook.Application myOlApp = new Outlook.ApplicationClass(); Out ...