HDU 1051:Wooden Sticks
Wooden Sticks
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 11605 Accepted Submission(s): 4792
The setup times are associated with cleaning operations and changing tools and shapes in the machine. The setup times of the woodworking machine are given as follows:
(a) The setup time for the first wooden stick is 1 minute.
(b) Right after processing a stick of length l and weight w , the machine will need no setup time for a stick of length l' and weight w' if l<=l' and w<=w'. Otherwise, it will need 1 minute for setup.
You are to find the minimum setup time to process a given pile of n wooden sticks. For example, if you have five sticks whose pairs of length and weight are (4,9), (5,2), (2,1), (3,5), and (1,4), then the minimum setup time should be 2 minutes since there is
a sequence of pairs (1,4), (3,5), (4,9), (2,1), (5,2).
and the second line contains n 2 positive integers l1, w1, l2, w2, ..., ln, wn, each of magnitude at most 10000 , where li and wi are the length and weight of the i th wooden stick, respectively. The 2n integers are delimited by one or more spaces.
3
5
4 9 5 2 2 1 3 5 1 4
3
2 2 1 1 2 2
3
1 3 2 2 3 1
2
1
3
简单贪心。。
题意能够看做是:给定若干(1<= n <=5000)组二维坐标点,凡是满足 "x1<= x2 && y1<= y2"的话那么我们承认这两个坐标是属于同一个集合中。题目要我们求出这些坐标点最少能表示成几个集合。
#include<cstdio>
#include<cstring>
#include<iostream>
#include<algorithm>
#include<vector>
#include<queue> using namespace std; const int maxn = 5000 + 50; int cas;//案例
int n;//木条数量
int vis[maxn];//标记数组
int ans_minute;//最短时间 struct point
{
int l;//长度
int w;//重量
};
point s[maxn]; bool cmp(point a, point b)
{
if( a.l==b.l )return a.w<b.w;
else return a.l<b.l;
} int main()
{
scanf("%d", &cas);
while( cas-- )
{
scanf("%d", &n);
ans_minute = 0;
memset(vis, 0, sizeof(vis));
for(int i=1; i<=n; i++)scanf("%d%d", &s[i].l, &s[i].w);
sort(s+1, s+n+1, cmp);
//for(int i=1; i<=n; i++)printf("%d__%d ", s[i].l, s[i].w);
int judge = 1;
for(int i=1; i<=n; i++)
{
if( vis[i] ) continue;
ans_minute++;
int temp = s[i].w;
vis[i] = 1;
for(int j=i+1; j<=n; j++)
{
if( temp<=s[j].w && !vis[j] )
{
temp = s[j].w;
judge++;
vis[j] = 1;
continue;
}
}
if(judge>=n)break;
} printf("%d\n", ans_minute);
}
}
HDU 1051:Wooden Sticks的更多相关文章
- HDU 1051: Wooden Sticks(贪心)
Wooden Sticks Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) To ...
- HDU1051:Wooden Sticks
Problem Description There is a pile of n wooden sticks. The length and weight of each stick are know ...
- HDU 1051 Wooden Sticks (贪心)
Wooden Sticks Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) To ...
- HDU 1051 Wooden Sticks 贪心||DP
Wooden Sticks Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Tot ...
- HDU - 1051 Wooden Sticks 贪心 动态规划
Wooden Sticks Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) ...
- hdu 1051:Wooden Sticks(水题,贪心)
Wooden Sticks Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Tot ...
- HDU ACM 1051/ POJ 1065 Wooden Sticks
Wooden Sticks Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Tot ...
- HDOJ 1051. Wooden Sticks 贪心 结构体排序
Wooden Sticks Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) To ...
- HDU 1005 Wooden Sticks
http://acm.hdu.edu.cn/showproblem.php?pid=1051 Problem Description There is a pile of n wooden stick ...
随机推荐
- OGEngine教程:声音载入
以下介绍声音资源从载入到播放的一个流程 首先,我们将须要的音频文件放到assets文件夹下,OGE中SoundRes和MusicRes为我们封装了非常多经常使用的方法,能够用于载入及播放等经常使用功能 ...
- 深入认识Tigase XMPP Server(上)
深入认识Tigase XMPP Server(上) 作者:chszs,转载需注明.博客主页:http://blog.csdn.net/chszs 本文的目的是深入认识Tigase XMPP Serve ...
- tar.gz文件命名和压缩解压方法
tar.gz文件命名 tar这是文件打成一个包,无压缩; gz同gzip标记的包.tar文件压缩; 所以它成为一个.tar.gz档 压缩 # tar cvfz backup.tar.gz /xxx/ ...
- 在Windows系统上实现轻量级的线程间及进程间消息队列
Windows没有message queue累世的IPC内核对象,使得在在处理IPC时少了一种传递消息的手段. 利用Windows的Naming Object可以实现一套简单的Inter-Thread ...
- SQL Server定时自动抓取耗时SQL并归档数据脚本分享
原文:SQL Server定时自动抓取耗时SQL并归档数据脚本分享 SQL Server定时自动抓取耗时SQL并归档数据脚本分享 第一步建库 USE [master] GO CREATE DATABA ...
- Android开发人员必知的开发资源
developer.android.com 官方开发人员网站推荐资源 在动手编写第一个 Android 应用之前,用心读一读 Android Design 章节.尤其是以下的这些文章: Devices ...
- hdu1896之优先队列应用
Stones Time Limit: 5000/3000 MS (Java/Others) Memory Limit: 65535/32768 K (Java/Others) Total Sub ...
- Android开发 更改返回button的图标
非常多的Android应用左上角都有返回button 在默认的情况下 ADT会默认给一个返回图标 而作为开发需求 非常多都要求定制一个新的图标 在Android的站点上 发现了2种能够更改的方法 1. ...
- linux kickstart 自动安装
最近很多业务系统都是linux lnmp平台安装,反复的安装让人觉得很苦恼,仔细钻研了下kickstart .这里环境是red hat linux 5.8 32位,系统盘中的软件包里包含有kickst ...
- 移动开发平台-应用之星app制作教程
目前在AppStore.GooglePlay等应用商店里已经有以百万计的Apps,应用程序使移动互联网空间得以无限拓展.很多人梦想着AngryBirds式的奇迹在自己身上发生,他们渴望自己开发的应用程 ...