According to Wikipedia:

Insertion sort iterates, consuming one input element each repetition, and growing a sorted output list. Each iteration, insertion sort removes one element from the input data, finds the location it belongs within the sorted list, and inserts it there. It repeats until no input elements remain.

Heap sort divides its input into a sorted and an unsorted region, and it iteratively shrinks the unsorted region by extracting the largest element and moving that to the sorted region. it involves the use of a heap data structure rather than a linear-time search to find the maximum.

Now given the initial sequence of integers, together with a sequence which is a result of several iterations of some sorting method, can you tell which sorting method we are using?

Input Specification:

Each input file contains one test case. For each case, the first line gives a positive integer N (<=100). Then in the next line, N integers are given as the initial sequence. The last line contains the partially sorted sequence of the N numbers. It is assumed that the target sequence is always ascending. All the numbers in a line are separated by a space.

Output Specification:

For each test case, print in the first line either "Insertion Sort" or "Heap Sort" to indicate the method used to obtain the partial result. Then run this method for one more iteration and output in the second line the resuling sequence. It is guaranteed that the answer is unique for each test case. All the numbers in a line must be separated by a space, and there must be no extra space at the end of the line.

Sample Input 1:

10
3 1 2 8 7 5 9 4 6 0
1 2 3 7 8 5 9 4 6 0
/*
* 这题思路比较简单:
1.中间序列 前面有序 后面和原始序列相同 则为插入排序。
2.堆排序 后面的数 应该是原数组中从大到小的数 如果遇到不满足这个条件的数 说明堆排序即将进行到当前这个数
在走一趟堆排序即可
*/
#include "iostream"
#include "algorithm"
using namespace std;bool judge(int a[],int b[],int n) { /* 判断是不是插入排序 */
int len = ;
int i;
for ( i = ; i < n - ; i++)
if (b[i] > b[i + ]) {
len = i + ;
break;
}
for (i=len; i < n; i++) {
if (a[i] != b[i])
return false;
}
sort(b, b + len + );
return true;
}
void print(int a[], int n) {
for (int i = ; i < n; i++) {
if (i == )
cout << a[i];
else
cout << " " << a[i];
}
cout << endl;
}
void adjust(int b[], int n) {
int parent = ;
int child;
int temp = b[parent];
for (; parent * + <= n;parent = child) {
child = parent * + ;
if (child + <= n && b[child + ] > b[child])
child = child + ;
if (b[child] <= temp)
break;
b[parent] = b[child];
}
b[parent] = temp;
}
int main() {
int a[], b[];
int n;
cin >> n;
for (int i = ; i < n; i++) {
cin >> a[i];
}
for (int i = ; i < n; i++) {
cin >> b[i];
}
if (judge(a, b, n)) {
cout << "Insertion Sort" << endl;
print(b, n);
}
else {
cout << "Heap Sort" << endl;
int i;
sort(a, a + n);
for (i = n-; i >= ; i--) {
if (a[i] != b[i])
break;
}
int temp = b[];
b[] = b[i];
b[i] = temp;
adjust(b,i-); /* 剩下的元素调整为最大堆 */
print(b, n);
}
}

Sample Output 1:

Insertion Sort
1 2 3 5 7 8 9 4 6 0

Sample Input 2:

10
3 1 2 8 7 5 9 4 6 0
6 4 5 1 0 3 2 7 8 9

Sample Output 2:

Heap Sort
5 4 3 1 0 2 6 7 8 9

1098. Insertion or Heap Sort (25)的更多相关文章

  1. pat 甲级 1098. Insertion or Heap Sort (25)

    1098. Insertion or Heap Sort (25) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yu ...

  2. PAT (Advanced Level) Practise - 1098. Insertion or Heap Sort (25)

    http://www.patest.cn/contests/pat-a-practise/1098 According to Wikipedia: Insertion sort iterates, c ...

  3. PAT (Advanced Level) 1098. Insertion or Heap Sort (25)

    简单题.判断一下是插排还是堆排. #include<cstdio> #include<cstring> #include<cmath> #include<ve ...

  4. PAT甲题题解1098. Insertion or Heap Sort (25)-(插入排序和堆排序)

    题目就是给两个序列,第一个是排序前的,第二个是排序中的,判断它是采用插入排序还是堆排序,并且输出下一次操作后的序列. 插入排序的特点就是,前面是从小到大排列的,后面就与原序列相同. 堆排序的特点就是, ...

  5. 【PAT甲级】1098 Insertion or Heap Sort (25 分)

    题意: 输入一个正整数N(<=100),接着输入两行N个数,表示原数组和经过一定次数排序后的数组.判断是经过插入排序还是堆排序并输出再次经过该排序后的数组(数据保证答案唯一). AAAAAcce ...

  6. PAT Advanced 1098 Insertion or Heap Sort (25) [heap sort(堆排序)]

    题目 According to Wikipedia: Insertion sort iterates, consuming one input element each repetition, and ...

  7. 1098 Insertion or Heap Sort (25分)

    According to Wikipedia: Insertion sort iterates, consuming one input element each repetition, and gr ...

  8. PAT甲级——1098 Insertion or Heap Sort (插入排序、堆排序)

    本文同步发布在CSDN:https://blog.csdn.net/weixin_44385565/article/details/90941941 1098 Insertion or Heap So ...

  9. pat1098. Insertion or Heap Sort (25)

    1098. Insertion or Heap Sort (25) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yu ...

随机推荐

  1. ios loading视图动画(模仿58同城)

    最近看了58同城的加载视图,感觉很不错,如下图: 所以想模仿写一个,下载58同城的app,解压,发现它用的是图片来实现的动画效果, 并不是绘制出来的,所以这就相对简单些了,其实整个动画的逻辑不复杂,无 ...

  2. C#操作xml文档,cuid,dategridview显示数据

    界面 //所有的数据全部在集合中             //dgv控件绑定List集合,List集合中有User类的对象,对象里有属性,把属性绑定到没列的数据上             dgv.Da ...

  3. LINQ to PostgreSQL Tutorial

    原文 LINQ to PostgreSQL Tutorial This tutorial guides you through the process of creating a simple app ...

  4. Django QuerySet API文档

    在查询时发生了什么(When QuerySets are evaluated) QuerySet 可以被构造,过滤,切片,做为参数传递,这些行为都不会对数据库进行操作.只要你查询的时候才真正的操作数据 ...

  5. 为Windows 7添加“Internet打印”功能

    http://wangchunhai.blog.51cto.com/225186/1156589/

  6. Eclipse中将classes文件删除之后显示:找不到或无法加载主类解决方案

    第一步: 将Eclipse自动编译打开 Project -> Build Automatically 第二步: Eclipse - Project - Clean

  7. HNOI2008 GT 考试

    我不明白为什么是DP,我感觉和vijos的核电站问题(https://www.vijos.org/p/1232)差不多啊 这是别人的题解:http://www.cnblogs.com/Skywalke ...

  8. shell 全局和局部变量

    /******************************************************************** * shell 全局和局部变量 * 声明: * 到目前为止, ...

  9. 咨询内容: TF卡一定要重新买吗,为什么我的放进去读不了呢

    京东回复:您好!先科(SAST) SA-992 便携数码音响 (兰色)不用重新买,但是需要您采用FAT分区重新格式化,感谢您对京东的支持!祝您购物愉快!

  10. selenium IDE & Remote Control & Webdriver

    一直忘记写selenium的开始学习的过程,今天趁五一,天气有雨,写下这文章 1.进入selnium官网,了解selenium1,2,grid的区别.下载c#相关的包(使用c#的人非常少) 2.使用I ...